Electronic Mechanic MCQ Quiz - Objective Question with Answer for Electronic Mechanic - Download Free PDF
Last updated on Jul 10, 2025
Latest Electronic Mechanic MCQ Objective Questions
Electronic Mechanic Question 1:
How does the 8051 microcontroller access external memory?
Answer (Detailed Solution Below)
Electronic Mechanic Question 1 Detailed Solution
Explanation:
The 8051 microcontroller accesses external memory primarily through indirect addressing using the Data Pointer (DPTR).
Here's why:
-
DPTR (Data Pointer): The DPTR is a 16-bit register in the 8051 that holds the 16-bit address of the external memory location to be accessed.
-
MOVX Instruction: The 8051 uses special instructions like
MOVX
(Move External) to read from or write to external data memory. For example,MOVX A, @DPTR
moves data from the external memory location pointed to by DPTR into the accumulator. -
Indirect Addressing: This method is called indirect addressing because the instruction doesn't directly specify the memory address but rather uses the content of a register (DPTR) as the address.
While the 8051 also has direct, immediate, and register addressing modes, these are primarily for accessing internal memory (RAM, SFRs) or for immediate data operations, not for accessing external memory.
Therefore, the correct option is: By using indirect addressing through DPTR
Electronic Mechanic Question 2:
Which ports are mainly utilised for address and data lines when interfacing external RAM with the 8051 microcontroller?
Answer (Detailed Solution Below)
Electronic Mechanic Question 2 Detailed Solution
The correct answer is option 4
Explanation:
When interfacing external RAM with the 8051 microcontroller, the 8051 needs to output address and data signals to the external memory.
The 8051 uses:
-
Port 0: Multiplexed lower 8 bits of address (A0–A7) and data bus (D0–D7).
(This is why an external latch is needed to demultiplex address & data.) -
Port 2: Outputs the higher 8 bits of address (A8–A15) directly.
Electronic Mechanic Question 3:
The Address of the Accumulator register in the 8051 Microcontroller is _____.
Answer (Detailed Solution Below)
Electronic Mechanic Question 3 Detailed Solution
Explanation:
The Accumulator Register in the 8051 Microcontroller
Definition: The accumulator register in the 8051 microcontroller is a special-purpose register used extensively in arithmetic, logical, and data transfer operations. It acts as an intermediary for computation and is integral to the functioning of the microcontroller. The accumulator is denoted by the symbol "A" and is widely used in instructions for performing operations such as addition, subtraction, logical comparisons, and data transfers.
Address of the Accumulator Register: The accumulator register in the 8051 microcontroller has a specific address within the Special Function Register (SFR) memory space. The correct address for the accumulator register is 0E0h. This hexadecimal address is reserved for the accumulator in the microcontroller's architecture.
Explanation of Correct Option:
Option 1: 0E0h
The accumulator register in the 8051 microcontroller is located at the address 0E0h. This address falls within the SFR memory space, which ranges from 80h to FFh in the 8051 architecture. The SFRs are a specific set of memory locations used to control and monitor the microcontroller's operations. The accumulator register, being a core part of the 8051's functionality, is assigned to the address 0E0h for direct access during computations and instructions.
The accumulator is involved in almost every arithmetic and logical operation performed by the microcontroller. For instance, when an addition operation is executed, one operand is typically stored in the accumulator, and the result is also stored there. This makes the accumulator a pivotal element in the microcontroller's operation.
Electronic Mechanic Question 4:
The 8051 Microcontroller is packaged in a _____ pin DIP.
Answer (Detailed Solution Below)
Electronic Mechanic Question 4 Detailed Solution
The correct answer is option 3
Concept:
- 8051 is an 8-bit (data bus) microcontroller built with 40 pins DIP (dual inline package).
- 8051 has internal RAM (128 Bytes) and ROM (4K Bytes).
- Of the 128-byte internal RAM, only 16 bytes are a bit-addressable. The rest must be accessed in byte format.
-
Additional Information
The Block Diagram of an 8051 microcontroller is as shown:
In an 8051 microcontroller,
- Internal RAM (data memory) - 128 bytes
- Internal memory (code memory) - 4 kB (ROM)
- Timer/counter - 2
- No. of interrupt - 5
- I/O pins - 32
- Serial port - 1
Electronic Mechanic Question 5:
Calculate the approximate power added efficiency of following power amplifier:
DC Voltage : 8 volts
DC Current : 5 Amp.
AC Input signal : 0 dBm
O/P power : 30 dBm
Answer (Detailed Solution Below)
Electronic Mechanic Question 5 Detailed Solution
Explanation:
Power Added Efficiency of Power Amplifier
Definition: Power added efficiency (PAE) is a key performance metric for power amplifiers, particularly in RF and microwave engineering. It measures the efficiency with which the amplifier converts the DC power it consumes into useful RF output power, considering the input signal power as part of the calculation.
Formula:
PAE is calculated using the following formula:
PAE = [(Pout - Pin) ÷ PDC] × 100
Where:
- Pout: Output power (RF power delivered by the amplifier).
- Pin: Input signal power (RF power fed into the amplifier).
- PDC: DC power supplied to the amplifier.
Calculation:
Given data:
- DC Voltage (VDC): 8 volts
- DC Current (IDC): 5 amps
- AC Input Signal Power (Pin): 0 dBm
- Output Power (Pout): 30 dBm
Step 1: Convert dBm values to watts.
- Pin (in watts) = 10^((0 - 30)/10) = 10^(-3) = 0.001 watts
- Pout (in watts) = 10^((30 - 30)/10) = 10^(0) = 1 watt
Step 2: Calculate DC power (PDC).
PDC = VDC × IDC
PDC = 8 × 5 = 40 watts
Step 3: Calculate Power Added Efficiency (PAE).
PAE = [(Pout - Pin) ÷ PDC] × 100
Substitute the values:
PAE = [(1 - 0.001) ÷ 40] × 100
PAE = [0.999 ÷ 40] × 100
PAE ≈ 0.025 × 100
PAE ≈ 2.5%
Conclusion: The approximate power added efficiency of the given power amplifier is 2.5%, which corresponds to Option 2
Top Electronic Mechanic MCQ Objective Questions
If the difference between the mode and median is 2, then find the difference between the median and mean(in the given order).
Answer (Detailed Solution Below)
Electronic Mechanic Question 6 Detailed Solution
Download Solution PDFConcept:
Relation between mode, median and mean is given by:
Mode = 3 × median – 2 × mean
Calculation:
Given:
Mode – median = 2
As we know
Mode = 3 × median – 2 × mean
Now, Mode = median + 2
⇒ (2 + median) = 3median – 2mean
⇒ 2Median - 2Mean = 2
⇒ Median - Mean = 1
∴ The difference between the median and mean is 1.Which among the following laws gives the mutual electric forces between multiple charges?
Answer (Detailed Solution Below)
Electronic Mechanic Question 7 Detailed Solution
Download Solution PDFCONCEPT:
Coulomb's law in Electrostatics:
- Coulomb's law state’s that force of interaction between two stationary point charges is directly proportional to the product of the charges, and inversely proportional to the square of the distance between them and acts along the straight line joining the two charges.
Faraday's Laws of Electromagnetic Induction :
- Whenever the number of magnetic lines of force (magnetic flux) passing through a circuit/coil changes an emf is produced in the circuit called induced emf.
Pascal’s law:
- Pressure at each and every point in the closed fluid is same.
Charles law:
- If the pressure remaining constant, the volume of the given mass of a gas is directly proportional to its absolute temperature.
i.e. V ∝ T
EXPLANATION:
- Coulomb’s law states that the mutual electric force between two charges q1 and q2 separated by r distance can be given by
Force (F) ∝ q1 × q2
\(F \propto \;\frac{1}{{{r^2}}}\)
\(F = K\frac{{{q_1} \times {q_2}}}{{{r^2}}}\)
Where K is a constant = 9 × 109 Nm2/C2
- If we want to calculate mutual electric forces between multiple charges we have to apply superposition principle along with coulomb’s law.
The first term of an A.P. is 2 and common difference is 4. The sum of its 40 terms will be
Answer (Detailed Solution Below)
Electronic Mechanic Question 8 Detailed Solution
Download Solution PDFHere a = 2; d = 4
⇒ A40th term = a + 39d = 2 + 39 × 4 = 2 + 156 = 158
∴ Sum of 40 terms = \(\frac{n}{2}\left[ {a + A40th} \right]\)
⇒ \(Sum = \frac{{40}}{2} \times \left[ {2 + 158} \right] = 20 \times 160 = 3200\)
∴ Sum of 40 terms = 3200
The dimensions of power are
Answer (Detailed Solution Below)
Electronic Mechanic Question 9 Detailed Solution
Download Solution PDFCONCEPT:
- The rate of work done is called power.
- It is denoted by P. The SI unit of power is the watt (W).
Power (P) = W / t
W = work done
t = time
EXPLANATION:
Dimensions of force is \(ML{T^{ - 2}}\).
Energy or Work done = Force × Distance
Dimensions of energy is \(M{L^2}{T^{ - 2}}\).
The dimensions of power = (Dimension of work) / Time (t) = (\(M{L^2}{T^{ - 2}}\))/T = \(M{L^2}{T^{ - 3}}\).
Quantities | Dimension |
Dynamic viscosity | M1L-1T-1 |
Kinematic viscosity | L2T−1 |
Magnetic Flux | ML2T-2I-1 |
Magnetic field | M1 T-2 I-1 |
Power | ML2T-3 |
Torque | M1L2T-2 |
Work | ML2T-2 |
Pressure | ML-1T-2 |
Force | M1L1T-2 |
Surface Tension | M1L0T-2 |
Which of the following phenomenon is/are responsible for formation of a rainbow in the sky?
Answer (Detailed Solution Below)
Electronic Mechanic Question 10 Detailed Solution
Download Solution PDFCONCEPT:
- Dispersion: The splitting of light into its component colors is called dispersion.
- Reflection: Reflection of Light is the process of sending back the light rays which fall on the surface of an object.
- Refraction: The bending of the light beam as it travels from one medium to another is known as the refraction of light.
- It takes place at the boundary between the two mediums.
EXPLANATION:
There various stages of phenomenon in the formation of a rainbow:
- The ray is first refracted at the air-droplet interface and dispersed into 7 colors.
- The dispersed rays are then totally internally reflected by the droplet-air interface.
- The dispersed rays then undergo refraction at the droplet-air interface and finally rainbow is formed.
- In this, we can see that that refraction and total internal reflection plays an important role in rainbow formation also the splitting of white light into seven colors is caused because of phenomena known as dispersion
- Thus all three phenomenon- refraction, reflection and dispersion are responsible for the formation of a rainbow in the sky. Hence option 4 is correct.
The waveform of a certain signal can be studied by
Answer (Detailed Solution Below)
Electronic Mechanic Question 11 Detailed Solution
Download Solution PDFThe Correct Answer is 'Cathode ray oscilloscope.'
- The waveform of a certain signal can be studied by a cathode ray oscilloscope.
Key Points
- The cathode ray oscilloscope is an electronic instrument used to obtain waveforms when the different input signals are given
- It is also called an oscillograph
- It is a graph plotting device that is used to measure different characteristics of signals.
- When horizontal deflection plates and vertical deflection plates of CRO (Cathode Ray Oscilloscope) are connected to two sinusoidal voltages, the patterns that appear at the CRO screen are called the Lissajous pattern
- The Lissajous pattern obtained in a CRO depends upon frequency, amplitude, and phase relationship
- The patterns used to measure phase and frequency with a cathode ray oscilloscope are called the Lissajous pattern
Additional Information
- It is an instrument used to measure properties of light over a specific portion of the electromagnetic spectrum.
- The basic function of a spectrometer is to take light in, break it into its spectral components, digitize the signal as a function of wavelength, and read it out and display it through a computer.
- The mass spectrometer, NMR spectrometer, and the optical spectrometer are the three most common types of spectrometers found in research labs around the world.
- The incident light from the light source can be transmitted, absorbed, or reflected through the sample.
- A p-n junction diode is a two-terminal device, which allows the electric current in only one direction while blocks the electric current in the opposite or reverse direction
- The p-n junction, which is formed when the p-type and n-type semiconductors are joined, is called a p-n junction diode.
- A sonometer is an apparatus made of a hollow box having two holes.
- A string is attached to it by which the transverse vibrations of strings can be studied.
What will be the backup time of a UPS if it is backed by 150 Ah, 12 V battery driving a load of 150 W?
Answer (Detailed Solution Below)
Electronic Mechanic Question 12 Detailed Solution
Download Solution PDFConcept:
Load Power = 150 watts
Rating of battery used in UPS = 12 Volts, 150 Ah
The energy supplied by battery = Voltage x Ah
Energy supplied by battery = 12 × 150 = 1800 watt-hour
∴ A battery can supply energy of 1800 watt-hour
Backup time = (Energy supplied by the battery)/(Load Power)
Backup time \(=\frac{1800}{150}=12~h\)
What are the roots of the equation 2x2 + 4x = 30?
Answer (Detailed Solution Below)
Electronic Mechanic Question 13 Detailed Solution
Download Solution PDFRoot of the equation of 2x2 + 4x = 30
2x2 + 4x – 30 = 0
Divided by 2
x2 + 2x – 15 = 0
x2 + 5x – 3x – 15 = 0
x (x + 5) – 3 (x + 5) = 0
(x + 5) (x – 3) = 0
Taking,
(x + 5) = 0
x = (-5)
Taking,
(x – 3) = 0
x = 3
So, the roots of the equation of 2x2 + 4x = 30 are (-5) and 3.
Tip: To find the answer quickly we can put the values of the options directly in the equation and check whether the values satisfy the equation.
MS Word is an example of
Answer (Detailed Solution Below)
Electronic Mechanic Question 14 Detailed Solution
Download Solution PDFMS WORD is an example of Application Software.
Key Points
Application Software - Application software is a program or group of programs designed for end-users. Examples of an application include a word processor, a spreadsheet, an accounting application, a web browser, an email client, a media player, a file viewer, simulators, a console game, or a photo editor.
Additional Information
1. System Software - System software is software designed to provide a platform for other software. Examples of system software include operating systems like macOS, GNU/Linux, Android and Microsoft Windows, computational science software, game engines, industrial automation, and software as a service application.
2. Operating Software - An Operating System (OS) is an interface between a computer user and computer hardware. An operating system is software that performs all the basic tasks like file management, memory management, process management, handling input and output, and controlling peripheral devices such as disk drives and printers. Five of the most common operating systems are Microsoft Windows, Apple macOS, Linux, Android, and Apple's iOS.
3. Translating Program - A translator is a programming language processor that converts a computer program from one language to another. It takes a program written in source code and converts it into machine code. It discovers and identifies the error during translation.
Thus, option 3 is the correct answer.
The protection system of the household circuit that trips if someone receives a shock is:
Answer (Detailed Solution Below)
Electronic Mechanic Question 15 Detailed Solution
Download Solution PDF- The sensation of electric shock is caused by the flow of electric current through the human body to the earth.
- When a person comes in contact with electrically live objects like water heaters, washing machines electric iron, etc., the extent of damages caused by this current depends on its magnitude and duration.
- This kind of current is called the leakage current which comes in milli-amps.
- These leakage currents being very small in magnitude, hence undetected by the fuses/MCBs are the major cause for the fires due to electricity.
- Residual current operated circuit breakers provide maximum protection from electric shocks and fires caused due to earth leakage current and also prevents the waste of electrical energy.
- These residual current circuit breakers (RCCB) are popularly called as earth leakage circuit breakers (ELCB).