Data Interpretation MCQ Quiz - Objective Question with Answer for Data Interpretation - Download Free PDF
Last updated on May 22, 2025
Latest Data Interpretation MCQ Objective Questions
Data Interpretation Question 1:
Comprehension:
Directions: Observe the given pie chart and answer the following questions.
The pie chart shows the percentage of positive corona cases on a particular day of May due to Covid -19 in four cities Delhi, Jaipur, Kanpur, and Mumbai.
Find how much percentage of corona cases in Jaipur is more than that of Kanpur.
Answer (Detailed Solution Below)
Data Interpretation Question 1 Detailed Solution
Given: 100
Total positive corona cases = 150000
Percentage of positive corona cases in Jaipur = 22%
Percentage of positive corona cases in Kanpur = 17%
Calculation:
The number of positive corona cases in Jaipur = 150000 × 22/100
⇒ 33000
⇒ The number of positive corona cases in Kanpur = 150000 × 17/100
⇒ 25500
⇒ Required percentage = [(33000 - 25500)/25500] × 100
⇒ (7500/25500) × 100%
⇒ Required percentage = 500/17 = 29.42%
Difference in cases in Jaipur when compared to Kanpur = 22% - 17% = 5%
Percentage difference = 5/17 × 100 = 29.41%
∴ The corona cases in Jaipur is 29.42% more than that of Kanpur.
Data Interpretation Question 2:
Comprehension:
Directions: Observe the given pie chart and answer the following questions.
The pie chart shows the percentage of positive corona cases on a particular day of May due to Covid -19 in four cities Delhi, Jaipur, Kanpur, and Mumbai.
If 5% of positive cases are vaccinated and the death rate of vaccinated cases is 0.2% then find how many deaths took place on that day?
Answer (Detailed Solution Below)
Data Interpretation Question 2 Detailed Solution
Given:
Total positive corona cases = 150000
Percentage of vaccinated cases = 5%
Death rate of vaccinated cases = 0.2%
Calculation:
Total number of vaccinated cases = 150000 × 5/100
⇒ 7500
The number of deaths of vaccinated cases = 7500 × 0.2/100
⇒ 15
∴ The number of deaths of vaccinated cases is 15.
Data Interpretation Question 3:
Comprehension:
Directions: Observe the given pie chart and answer the following questions.
The pie chart shows the percentage of positive corona cases on a particular day of May due to Covid -19 in four cities Delhi, Jaipur, Kanpur, and Mumbai.
If the mortality rate in all cities is 3.5%, then find how many more deaths happened in Delhi as compared to Jaipur.
Answer (Detailed Solution Below)
Data Interpretation Question 3 Detailed Solution
Given:
Total positive corona cases = 150000
Death rate = 3.5%
Percentage of positive corona cases in Dehli = 26%
Percentage of positive corona cases in Jaipur = 22%
Calculation:
The number of positive corona cases in Delhi = 150000 × 26/100
⇒ 39000
⇒ Total deaths in Delhi = 39000 × 3.5/100 = 1365
The number of positive corona cases in Jaipur = 150000 × 22/100
⇒ 33000
⇒ Total deaths in Jaipur = 33000 × 3.5/100 = 1155
⇒ Required difference = 1365 - 1155 = 210
∴ 210 more deaths happened in Delhi as compare to Jaipur.
Data Interpretation Question 4:
Comprehension:
Directions: Observe the given pie chart and answer the following questions.
The pie chart shows the percentage of positive corona cases on a particular day of May due to Covid -19 in four cities Delhi, Jaipur, Kanpur, and Mumbai.
Find the average number of positive cases in Delhi, Kanpur and Mumbai together.
Answer (Detailed Solution Below)
Data Interpretation Question 4 Detailed Solution
Given:
Total positive corona cases = 150000
Percentage of positive corona cases in Dehli = 26%
Percentage of positive corona cases in Kanpur = 17%
Percentage of positive corona cases in Mumbai = 35%
Calculation:
The number of positive corona cases in Delhi = 150000 × 26/100
⇒ 39000
The number of positive corona cases in Kanpur = 150000 × 17/100
⇒ 25500
The number of positive corona cases in Mumbai = 150000 × 35/100
⇒ 52500
⇒ Total positive cases in Dehli, Kanpur and Mumbai = 39000 + 25500 + 52500
⇒ 117000
⇒ Required average = 117000/3 = 39000
Average percentage of cases in Delhi, Kanpur and Mumbai = (26 + 17 + 35)%/3
⇒ Average number = 78%/3 × 150000 = 39000
∴ The average number of positive cases in Delhi, Kanpur and Mumbai is 39000.
Data Interpretation Question 5:
Comprehension:
Directions: Observe the given pie chart and answer the following questions.
The pie chart shows the percentage of positive corona cases on a particular day of May due to Covid -19 in four cities Delhi, Jaipur, Kanpur, and Mumbai.
Find the difference between the total numbers of positive corona cases in Delhi and Kanpur together and the total number of positive corona cases in Mumbai alone?
Answer (Detailed Solution Below)
Data Interpretation Question 5 Detailed Solution
Given:
Total positive corona cases = 150000
Percentage of positive corona cases in Dehli = 26%
Percentage of positive corona cases in Kanpur = 17%
Percentage of positive corona cases in Mumbai = 35%
Calculation:
The number of positive corona cases in Delhi = 150000 × 26/100
⇒ 39000
The number of positive corona cases in Kanpur = 150000 × 17/100
⇒ 25500
⇒ The number of positive corona cases in Mumbai = 150000 × 35/100
⇒ 52500
⇒ Total number of positive corona cases in Delhi and Kanpur together = 39000 + 25500
⇒ 64500
⇒ Required difference = 64500 - 52500
⇒ 12000
Total number of corona cases in Delhi and Kanpur = 26% + 17% = 43%
Total percentage of corona cases in Mumbai = 35%
Difference = (43 - 35)% × 150000 = 12000
∴ The required difference is 12000.
Top Data Interpretation MCQ Objective Questions
Comprehension:
Given below the data about three employees of a call center named ZINTOCA. In the given table, data about calls received by them, calls selected for further lead and calls finally received is given:
| A | B | C | |
| Initial calls(% out of total calls) | 40% | 30% | 30% |
| Lead calls (% out of initial calls) | 80% | x% | 88% |
| Final received calls(% out of lead calls) | 90% | 80% | y% |
Total number of initial calls in the company is 24000 and total number of calls not received by company C is 4464 less than the total number of calls received by company A. Find the value of y.
Answer (Detailed Solution Below)
Data Interpretation Question 6 Detailed Solution
Download Solution PDFCalculation:
Let the total number of calls be 1000z.
Initial calls (% out of total calls) of A = (1000z × 40/100) = 400z
Initial calls (% out of total calls) of B = (1000z × 30/100) = 300z
Initial calls (% out of total calls) of C = (1000z × 30/100) = 300z
Lead calls (% out of initial calls) of A = (400z × 80/100) = 320z
Lead calls (% out of initial calls) of B = (300z × x/100) = 3zx
Lead calls (% out of initial calls) of C = (300z × 88/100) = 264z
Final received calls (% out of lead calls) of A = (320z × 90/100) = 288z
Final received calls (% out of lead calls) of B = (3zx × 80/100) = 3zx × (4/5)
Final received calls (% out of lead calls) of C = (264z × y/100)
Total number of initial calls in the company = 24000
⇒ (400z + 300z + 300z) = 24000
⇒ 1000z = 24000
⇒ z = (24000/1000)
⇒ z = 24
Total number of calls not received calls by C = (300h – 264z × y/100)
⇒ (300 × 24 – 264z × y/100)
⇒ (7200 – 264z × y/100)
According to the question
Total number of calls not received by company C is 4464 less than the total number of calls received by company A
⇒ (7200 – 264z × y/100) + 4464 = 288z
⇒ (7200 – 264 × 24 × y/100) + 4464 = 288 × 24
⇒ 7200 – 6336y/100 + 4464 = 6912
⇒ (720000 – 6336y + 446400)/100 = 6912
⇒ (720000 – 6336y + 446400) = 6912 × 100
⇒ (1166400 – 6336y) = 691200
⇒ (-6336y) = (691200 – 1166400)
⇒ (-6336y) = -475200
⇒ y = [-475200/(-6336)]
⇒ y = 75
∴ The value of y is 75
The table shows the daily income (in Rs.) of 50 persons.
Study the table and answer the question:
|
Income (Rs) |
No. of persons |
|
Less than 200 |
12 |
|
Less than 250 |
26 |
|
Less than 300 |
34 |
|
Less than 350 |
40 |
|
Less than 400 |
50 |
How many persons earn Rs. 200 or more but less than Rs. 300?
Answer (Detailed Solution Below)
Data Interpretation Question 7 Detailed Solution
Download Solution PDFCalculation:
Number less than 200 = 12
Number less than 250 = 26
Number less than between 250 and 200 = (26 – 12)
⇒ 14
Again,
Number less than 250 = 26
Number less than 300 = 34
Number less than between 300 and 250 = (34 – 26)
⇒ 8
Persons earn Rs. 200 or more but less than Rs. 300 = (14 + 8)
⇒ 22
∴ Required persons is 22
Directions: The data for family sizes in a town is given below. Based on the bar graph, answer the question given below:
Calculate the average family size from the given data.
Answer (Detailed Solution Below)
Data Interpretation Question 8 Detailed Solution
Download Solution PDFCalculation:
Number of families having 1 member = 5
Total members = 5
Number of families having 2 members = 30
Total members = 60
Number of families having 3 members = 45
Total members = 135
Number of families having 4 members = 40
Total members = 160
Number of families having 5 members = 25
Total members = 125
Number of families having 6 members = 5
Total members = 30
So, the total membes in all types of families = 5 + 60 + 135 + 160 + 125 + 30 = 515
Total number of families = 5 + 30 + 45 + 40 + 25 + 5 =150
The average family size = 515 / 150 = 3.4
Hence, option 3 is correct.
The given data shows the registration of bikes and total vehicles (in thousands) for 6 months in 2017 in City X.
Note: In the chart, the first number represents bikes and the second number represents total vehicles.
Based on the given data, the increase in the registration of vehicles other than bikes in April 2017 in comparison of Jan 2017 is _______.
Answer (Detailed Solution Below)
Data Interpretation Question 9 Detailed Solution
Download Solution PDFNumber of registration of vehicles other than bikes in January 2017 = 27,000 - 21,000 = 6,000
Number of registration of vehicles other than bikes in April 2017 = 35,000 - 20,000 = 15,000
∴ the increase in the registration of vehicles other than bikes in April 2017 in comparison of Jan 2017 = 15,000 - 6,000 = 9,000
Study the given pie-chart carefully and answer the following question. If scholarship has to be paid out of the donation fund, then what is the percentage of donation fund used for this purpose (rounded off to two decimal places)?
The entire fund that school gets from different sources is equal to Rs. 10 lakh
Answer (Detailed Solution Below)
Data Interpretation Question 10 Detailed Solution
Download Solution PDFCalculation:
Total fund got by school = 100% = 1000000
Funds got through donation = 35%
Scholarship paid = 26%
Required percentage = 26/35 × 100
⇒ 2600/35 = 74.285% ≈ 74.29%
∴ The correct answer is 74.29%.
Study the given table and answer the question that follows.
The table shows the classification of 100 students based on the marks obtained by them in History and Geography in an examination.
|
Subject |
Marks out of 50 |
||||
|
40 and above |
30 and above |
20 and above |
10 and above |
0 and above |
|
|
History |
9 |
32 |
80 |
92 |
100 |
|
Geography |
4 |
21 |
66 |
81 |
100 |
|
Average (Aggregate) |
7 |
27 |
73 |
87 |
100 |
Based on the table, what is the number of students scoring less than 20% marks in aggregate?
Answer (Detailed Solution Below)
Data Interpretation Question 11 Detailed Solution
Download Solution PDFCalculation
We have 20% of 50 = 10
Therefore Required number:
Number of students scoring less than 10 marks in aggregate
= 100 - Number of students scoring 10 and above marks in aggregate
= 100 - 87
= 13.
The number of students scoring less than 20% marks in aggregate is 13.
Various expenditures incurred by a publishing company for publishing a book in 2018 are given in the following pie chart. Study the chart and answer the question.
Price printed on a book is 15% above the cost price. If the price printed on a book is Rs. 942, then the cost of paper for a single copy in Rs. is (rounded off to one decimal place)
Answer (Detailed Solution Below)
Data Interpretation Question 12 Detailed Solution
Download Solution PDFCalculation:
Let the Cost price of the book be 100
Then, Marked Price of the book is 100 + (15% of 100) = 115
Printed price or marked price = 942
Cost price of book = 942 × (100/115)
⇒ 819.13
Now,
Paper cost = 819.13 × 15/100
⇒ 122.869 ≈ 122.9
∴ The required answer is Rs. 122.9
The line chart given below shows the profit percentage of a company on 5 different products P1, P2, P3, P4 and P5.
The expenditure of product P5 is Rs. 46000. What is the revenue of product P5?
Answer (Detailed Solution Below)
Data Interpretation Question 13 Detailed Solution
Download Solution PDFGIVEN:
From the chart
Profit percentage in P5 = 8%
Expenditure = Rs. 46000
FORMULA USED:
Profit percentage = [(Revenue – Expenditure)/Expenditure] × 100
CALCULATION:
Profit percentage = [(Revenue – Expenditure)/Expenditure] × 100
⇒ 8 = [(Revenue – 46000)/46000] × 100
⇒ Revenue – 46000 = 8 × 460
⇒ Revenue = 3680 + 46000
⇒ Revenue = 49680The following table shows the number of different items in different shops and their respective selling prices per unit.
|
Shops |
Total No. of Items |
AC ∶ Cooler ∶ Fan |
Selling Price per unit |
||
|
Cooler |
AC |
Fan |
|||
|
A |
5000 |
4 ∶ 5 ∶ 1 |
8000 |
25000 |
8500 |
|
B |
1800 |
3 ∶ 2 ∶ 4 |
10000 |
20000 |
16000 |
|
C |
3400 |
6 ∶ 4 ∶ 7 |
6000 |
42000 |
15000 |
|
D |
3600 |
4 ∶ 2 ∶ 3 |
12000 |
32000 |
8000 |
|
E |
4000 |
5 ∶ 1 ∶ 4 |
8000 |
26500 |
12200 |
|
F |
1210 |
2 ∶ 4 ∶ 5 |
11000 |
28000 |
11100 |
Find the percentage of total revenue which comes from Cooler from shop E, considering all given items are being sold from shop E and from all the given shops only given three items are being sold. (Rounded off to three decimal places)
Answer (Detailed Solution Below)
Data Interpretation Question 14 Detailed Solution
Download Solution PDFCalculation:
Total cooler sold by shop E = 4000 × (1/10)
⇒ 400
Selling price of 400 coolers = 400 × 8000
⇒ 3200000
Total ACs sold by shop E = 4000 × (5/10)
⇒ 2000
Selling price of 2000 ACs = 2000 × 26500
⇒ 53000000
Total Fans sold by shop E = 4000 × (4/10)
⇒ 1600
Selling price of 1600 Fans = 1600 × 12200
⇒ 19520000
Now,
Required % = [3200000/(3200000 + 53000000 + 19520000)] × 100
⇒ [3200000/(75720000)] × 100
⇒ 4.226 ≈ 4.23%
∴ The required answer is 4.23%.
Study the given pie-chart and table and answer the question that follows.
The pie - chart shows the percentage distribution of age groups of visitors to a park in a month.
The table shows the male, female distribution of the visitors in terms of the percentage.
|
Age |
Male Percentage |
Female Percentage |
|
More than 60 |
58 |
42 |
|
45 - 60 |
80 |
20 |
|
35 - 45 |
81 |
19 |
|
25 - 35 |
60 |
40 |
|
Less than 25 |
45 |
55 |
If 2000 male visitors and 1500 female visitors were there in all, then the ratio of the number of male visitors the age group 25 - 35, to the female visitors of the age group 45 - 60 is:
Answer (Detailed Solution Below)
Data Interpretation Question 15 Detailed Solution
Download Solution PDFCalculation:
Total visitors = Male visitors + Female visitors
= 2000 + 1500
= 3500
The total visitors in the age group 25 - 35 is = 27% of 3500 = 945
so
The number of male visitors in the age group 25 - 35 is = 60% of 945 = 567
Similarly,
The total visitors in the age group 45 - 60 is = 29% of 3500 = 1015
so
The number of female visitors in the age group 45 - 60 is = 20% of 1015 = 203
The expected ratio will be,
567 : 203
⇒ 81: 29
∴ The correct option is 4