Question
Download Solution PDF1 + 2sin2θ cos2θ - sin4θ - cos4θ चे कमाल मूल्य किती आहे, जेथे 0° < θ < 90° आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
2sinθ.cosθ = sin2θ
sin2θ + cos2θ = 1
a2 + b2 = (a + b)2 - 2ab
गणना :
आपल्याकडे आहे 1 + 2sin2θ cos2θ - sin4θ - cos4θ⇒ 1 + 2sin2θ cos2θ - (sin4θ + cos4θ)
⇒ 1 + 2sin2θ cos2θ - [(sin2θ)2 + (cos2θ)2]
⇒ 1 + 2sin2θ cos2θ - [(sin2θ + cos2θ)2 - 2sin2θcos2θ]
⇒ 1 + 2sin2θ cos2θ - 1 + 2sin2θcos2θ
⇒ 4sin2θ cos2θ
⇒ (2sinθ.cosθ)2
⇒ (sin2θ)2
⇒ sin22θ
Last updated on Jun 18, 2025
-> The UPSC CDS 2 Registration Date has been extended at upsconline.gov.in. for 453 vacancies.
-> Candidates can now apply online till 20th June 2025.
-> The CDS 2 Exam will be held on 14th September 2025.
-> Attempt UPSC CDS Free Mock Test to boost your score.
-> The selection process includes Written Examination, SSB Interview, Document Verification, and Medical Examination.
-> Refer to the CDS Previous Year Papers to enhance your preparation.