1 + sec2 46° - cot2 44° =

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Allahabad High Court Group D (Mains) Exam Official Paper (Held On: 02 Apr, 2023)
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  1. 9
  2. 1 + √2
  3. 1
  4. 2

Answer (Detailed Solution Below)

Option 4 : 2
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Given:

1 + sec2 46º - cot2 44º

Formula Used:

\(sec^2 \theta = 1 + tan^2 \theta\)

\(cot \theta = tan (90º - \theta)\)

Calculation:

sec2 46º = 1 + tan2 46º

cot2 44º = tan2 (90º - 44º)

cot2 44º = tan2 46º

⇒ 1 + sec2 46º - cot2 44º

⇒ 1 + (1 + tan2 46º) - tan2 46º

⇒ 1 + 1

⇒ 2

The correct answer is option 4

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