Question
Download Solution PDFTrain A of length 80m while moving crosses a pole in 16 seconds. lf it is known that the lengths of train B and train A is in the ratio of 3:1, then how long would it take train B to cross a platform which is half the length of train A if the speed of train B is same as that of train A?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculations:
Speed of Train A = Distance / Time = 80 m / 16 s = 5 m/s.
Since the speed of Train B is the same as Train A, the speed of Train B = 5 m/s.
Length of Train B = 3 × Length of Train A
⇒ 3 × 80 = 240 m.
Length of the platform = (1/2) × Length of Train A
⇒ (1/2) × 80 = 40 m.
To cross the platform, Train B needs to cover its own length plus the length of the platform, i.e., 240 m + 40 m = 280 m.
Time taken by Train B to cross the platform = Distance / Speed
⇒ 280 m / 5 m/s = 56 seconds.
∴ It would take Train B 56 seconds to cross the platform.
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