बहुपद 9x2 - 4 के शून्यक निम्नलिखित में कौन है :  

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Bihar STET TGT (Maths) Official Paper-I (Held On: 04 Sept, 2023 Shift 2)
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  1. \(\frac{2}{3}, \frac{-2}{3}\)
  2. 4, 4
  3. 9, -9
  4. \(\frac{3}{2}, -\frac{3}{2}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{2}{3}, \frac{-2}{3}\)
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Bihar STET Paper 1 Social Science Full Test 1
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संकल्पना-

माना कि बहुपद p(x) है तो p(x) = 0 आपको बहुपद का शून्यक देता है।

स्पष्टीकरण -

हमारे पास बहुपद 9x2 - 4 है। 

अब बहुपद के शून्यकों के लिए -

 9x2 - 4  = 0

⇒  9x2 = 4

⇒  x2 = 4/9

⇒ \(x = \frac{2}{3} \ \ and \ \ x = \frac{-2}{3}\)

अतः विकल्प (1) सही है।​

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