Which of the following is the zeros of the polynomial 9x2 - 4: 

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Bihar STET TGT (Maths) Official Paper-I (Held On: 04 Sept, 2023 Shift 2)
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  1. \(\frac{2}{3}, \frac{-2}{3}\)
  2. 4, 4
  3. 9, -9
  4. \(\frac{3}{2}, -\frac{3}{2}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{2}{3}, \frac{-2}{3}\)
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Detailed Solution

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Concept -

let the polynomial be p(x) then p(x) = 0 gives you the zeros of the polynomial.

Explanation -

We have the polynomial  9x2 - 4

Now for the zeros of the polynomial -

 9x2 - 4  = 0

⇒  9x2 = 4

⇒  x2 = 4/9

⇒ \(x = \frac{2}{3} \ \ and \ \ x = \frac{-2}{3}\)

Hence option (1) is true.

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