Question
Download Solution PDFतीन संख्याएँ 1 ∶ 2 ∶ 5 के अनुपात में हैं और उनका लघुत्तम समापवर्त्य 1600 है। संख्याओं का महत्तम समापवर्तक ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
संख्याएँ 1 : 2 : 5 के अनुपात में हैं
संख्याओं का लघुत्तम समापवर्त्य = 1600
गणना:
माना संख्या 1x, 2x और 5x है।
(1x, 2x और 5x) का लघुत्तम समापवर्त्य = 1 × 2 × 5 × (x)
⇒ 10x
प्रश्न के अनुसार, 10x = 1600
⇒ x = 1600/10
⇒ x = 160
तो, संख्याएँ 160, 320, 800 हैं
अब,
160 = 25 × 5
320 = 26 × 5
800 = 25 × 52
इसलिए, महत्तम समापवर्तक = 25 × 5 = 160
∴ तीन संख्याओं का महत्तम समापवर्तक 160 है।
Last updated on Jul 18, 2025
-> A total of 1,08,22,423 applications have been received for the RRB Group D Exam 2025.
-> The RRB Group D Exam Date will be announced on the official website. It is expected that the Group D Exam will be conducted in August-September 2025.
-> The RRB Group D Admit Card 2025 will be released 4 days before the exam date.
-> The RRB Group D Recruitment 2025 Notification was released for 32438 vacancies of various level 1 posts like Assistant Pointsman, Track Maintainer (Grade-IV), Assistant, S&T, etc.
-> The minimum educational qualification for RRB Group D Recruitment (Level-1 posts) has been updated to have at least a 10th pass, ITI, or an equivalent qualification, or a NAC granted by the NCVT.
-> Check the latest RRB Group D Syllabus 2025, along with Exam Pattern.
-> The selection of the candidates is based on the CBT, Physical Test, and Document Verification.
-> Prepare for the exam with RRB Group D Previous Year Papers.