Question
Download Solution PDF2.8 सेमी त्रिज्या और 8 सेमी ऊँचाई वाला एक बेलन 5.6 सेमी त्रिज्या और 24 सेमी ऊँचाई वाले एक ठोस शंकु से निकाला जाता है। शंकु के शेष भाग का आयतन (सेमी³ में) क्या है? (π =
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
बेलन:
त्रिज्या (rc) = 2.8 सेमी, ऊँचाई (hc) = 8 सेमी
शंकु:
त्रिज्या (rco) = 5.6 सेमी, ऊँचाई (hco) = 24 सेमी
प्रयुक्त सूत्र:
बेलन का आयतन = πrc2hc
शंकु का आयतन = (1/3)πrco2hco
गणना:
बेलन का आयतन:
Vc = (22/7) × (2.8)2 × 8 = (22/7) × 7.84 × 8
Vc = 197.12 सेमी3
शंकु का आयतन:
Vco = (1/3) × (22/7) × (5.6)2 × 24 = (1/3) × (22/7) × 31.36 × 24
⇒ (22/7) × 31.36 × 8
Vco = 788.48 सेमी3
शेष भाग का आयतन = शंकु का आयतन - बेलन का आयतन
Vशेष = Vco - Vc
Vशेष = 788.48 - 197.12 = 591.36 सेमी3
∴ शंकु के शेष भाग का आयतन 591.36 सेमी3 है।
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