Question
Download Solution PDFcot4θ + cot2θ = 3 అయితే, cosec4θ – cosec2θ = ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFcot4θ + cot2θ = 3 = cos4x/sin4x + cos2x/sin2x
⇒ cos2x(cos2x + sin2x)/ sin4x = 3(క.సా.గు తీసుకోవడం)
⇒ cos2x/sin4x = 3 = cot2xcosec2x
∴ cosec4θ – cosec2θ = cosec2θ(cosec2θ – 1) = cosec2θcot2x = 3
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