एका गोळ्याची त्रिज्या 8 सेमी आहे. घन दंडगोलाची आधार त्रिज्या 4 सेमी आणि उंची h सेमी आहे. जर दंडगोलाचे एकूण पृष्ठफळ गोलाच्या पृष्ठफळाच्या अर्धे असेल, तर दंडगोलाची उंची शोधा.

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RRB NTPC CBT 2 Level -4 Official paper (Held On: 10 May 2022 Shift 1)
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  1. 15 सेमी
  2. 12 सेमी
  3. 10 सेमी
  4. 9 सेमी

Answer (Detailed Solution Below)

Option 2 : 12 सेमी
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RRB NTPC CBT-I Official Paper (Held On: 4 Jan 2021 Shift 1)
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Detailed Solution

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दिलेले आहे:

गोलाची त्रिज्या = 8 सेमी

दंडगोलाची त्रिज्या = 4 सेमी

दंडगोलाचे एकूण पृष्ठफळ गोलाच्या पृष्ठफळाच्या अर्धे आहे

वापरलेला सूत्र:

दंडगोलाचे एकूण पृष्ठफळ = 2πr(h + r)

गोलाचे पृष्ठफळ = 4πr2

गणना:

प्रश्नानुसार

दंडगोलाचे एकूण पृष्ठफळ गोलाच्या पृष्ठफळाच्या अर्धे आहे

⇒ 2πr(h + r)/4πr2 = 1/2

⇒ 2 × π × 4(h + 4)/(4 × π × 82) = 1/2

⇒ 8(h + 4)/256 = 1/2

⇒ h + 4/32 = 1/2

⇒ h + 4 = 16

⇒ h = (16 – 4)

⇒ h = 12 सेमी

∴ दंडगोलाची उंची 12 सेमी आहे

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