0.000064 का घनमूल क्या है?

This question was previously asked in
NPCIL Stipendiary Trainee 2021 Official Paper-I
View all NPCIL Stipendiary Trainee Papers >
  1. 4
  2. 0.4
  3. 0.04
  4. 0.004

Answer (Detailed Solution Below)

Option 3 : 0.04
Free
NPCIL Stipendiary Trainee General Awareness Subject Test - 01
0.8 K Users
20 Questions 60 Marks 12 Mins

Detailed Solution

Download Solution PDF

दिया गया है:

0.000064 का घनमूल

प्रयुक्त सूत्र:

किसी संख्या का घनमूल दिया जाता है

गणना:

⇒ (0.000064)1/3

⇒ (64 × 10-6)1/3

⇒ 641/3 × (10-6)1/3

⇒ 4 × 10-2

⇒ 0.04

इसलिए, सही उत्तर विकल्प 3 है।

Latest NPCIL Stipendiary Trainee Updates

Last updated on May 28, 2025

-> NPCIL Stipendiary Trainee recruitment application form 2025 has been released. 

-> Candidates can fill the NPCIL recruitment form 2025 from May 28 to June 17 for the Kakrapar Unit. A total of 177 vacancies are announced for the Kakrapar Unit. 

-> NPCIL Stipendiary Trainee 2025 Detailed Notification has been released. 

-> NPCIL Stipendiary Trainee Recruitment has been announced for 308 vacancies at the Kaiga Site.

-> Candidates can apply online from 12th March to 1st April, 2025.

-> Candidates with a Diploma/Graduation degree are eligible for this post.

-> The selection process includes a Written Test followed by a Skill Test/Interview, depending on the post.

-> Prepare for the exam with NPCIL Stipendiary Trainee Previous Year Papers.

More Number System Questions

Get Free Access Now
Hot Links: teen patti app lotus teen patti teen patti all