Question
Download Solution PDF\(\frac{{{{\tan }^2}60^\circ + {{\cot }^2}30^\circ }}{{{{\tan }^2}20^\circ - {{\sec }^2}20^\circ }} - \frac{{\sin 90^\circ + \cos 0^\circ }}{{\cos e{c^2}20^\circ - {{\cot }^2}20^\circ }}\) এর মান নির্ণয় করুন।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFঅনুসৃত সূত্র:
tan 60º = √3
cot 30º = √3
sec2a - tan2a = 1
cosec2a - cot2a = 1
গণনা:
\(\frac{{{{\tan }^2}60^\circ + {{\cot }^2}30^\circ }}{{{{\tan }^2}20^\circ - {{ \sec }^2}20^\circ }} - \frac{{\sin 90^\circ + \cos 0^\circ }}{{\cos e{c^2}20^\circ - {{\ খাট }^2}20^\circ }}\)
⇒ (√32 + √32)/(-1) - (1 + 1)/1
⇒ - 6 - 2 = - 8
সুতরাং, সঠিক উত্তর হল -8
Last updated on Jul 18, 2025
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