Puzzle MCQ Quiz - Objective Question with Answer for Puzzle - Download Free PDF
Last updated on Jun 5, 2025
Latest Puzzle MCQ Objective Questions
Puzzle Question 1:
If ‘A’ stands for ‘÷’, ‘B’ stands for ‘×’, ‘C’ stands for ‘+’ and ‘D’ stands for ‘–’, then the resultant of which of the following will be 652?
Answer (Detailed Solution Below)
Puzzle Question 1 Detailed Solution
BODMAS table
Given equation: If ‘A’ stands for ‘÷’, ‘B’ stands for ‘×’, ‘C’ stands for ‘+’ and ‘D’ stands for ‘–’
Option 1) 109 B 6 D 16 A 2 C 6
Putting the sign in equation
⇒109 x 6 - 16 ÷ 2 + 6
⇒109 x 6 - 8 + 6
⇒654 - 8 + 6
⇒660 - 8
⇒652
Option2) 109 A 6 D 16 B 2 C 6
⇒109 ÷ 6 - 16 x 2 + 6
⇒18.16 - 16 x 2 + 6
⇒18.16 - 32 + 6
⇒24.16 - 32
⇒-7.84
Option3) 109 B 6 A 16 D 2 C 6
⇒109 x 6 ÷ 16 - 2 + 6
⇒109 x 0.375 - 2 + 6
⇒40.875 - 2 + 6
⇒46.875 - 2
⇒44.875
Option 4) 109 C 6 D 16 A 2 B 6
⇒109 + 6 - 16 ÷ 2 x 6
⇒109 + 6 - 8 x 6
⇒109 + 6 - 48
⇒115 - 48
⇒67
Hence the correct answer is "Option 1".
Puzzle Question 2:
Read the information and answer the question given below:
Five friends are working in a company. Kapil, Shiva and Hari are intelligent.
Kapil, Ravi and Jitin are hard working.
Ravi, Hari and Jitin are honest.
Which of the following persons is neither honest nor hardworking but is intelligent?
Answer (Detailed Solution Below)
Puzzle Question 2 Detailed Solution
Given: Five friends Kapil, Ravi, Jatin, Hari, Shiva are working in a company.
Explanation:
Kapil, Shiva and Hari are intelligent.
Kapil, Ravi and Jitin are hard working.
Ravi, Hari and Jitin are honest.
Friends |
Strength |
Strength |
Strength |
Kapil |
Intelligent |
Hardworking |
|
Shiva |
Intelligent |
|
|
Hari |
Intelligent |
|
Honest |
Jitin |
|
Hardworking |
Honest |
Ravi |
|
Hardworking |
Honest |
According to above table, shiva is neither honest nor hardworking but is intelligent.
Hence, Option 1 is the correct answer.
Puzzle Question 3:
If 20 - 10 méans 200, 8 ÷ 4 means 12, 6 × 2 means 4 and 20 + 5 means 4, then
100 - 10 × 1000 ÷ 1000 +100 × 10 = ?
Answer (Detailed Solution Below)
Puzzle Question 3 Detailed Solution
Symbols are coded as:-
Symbol | + | - | × | ÷ |
Meaning | ÷ | × | - | + |
Given that: 100 - 10 × 1000 ÷ 1000 +100 × 10 = ?
After replacing the symbols with their meanings, we get:-
= 100 × 10 - 1000 + 1000 ÷ 100 - 10
= 100 × 10 - 1000 + 10 - 10
= 1000 - 1000 + 10 - 10
= 1010 - 1010
= 0
Hence, " option 2" is the correct answer.
Puzzle Question 4:
Select the correct combination of mathematical signs to replace the * signs and to balance the given equation.
96 * 3 * 5 * 56 * 16 * 120
Answer (Detailed Solution Below)
Puzzle Question 4 Detailed Solution
BODMAS table
Given : 96 * 3 * 5 * 56 * 16 * 120
Option 1. ÷, × , -, +, = by substituting these values by BODMAS rule
- 96 ÷ 3 × 5 - 56 +16 = 120
- 32 × 5 - 56 +16 = 120
- 160 - 56 +16 = 120
- 176 - 56 = 120
- 120 = 120 (LHS = RHS )
Option 2.× , ÷, +, -, =by substituting these values by BODMAS rule
- 96 × 3 ÷ 5 + 56 -16 = 120
- 96 × 0.6 + 56 -16 = 120
- 57.6 + 56 - 16 = 120
- 113.6 ≠ 120 (LHS ≠ RHS )
Option 3.÷, × , +, -, =by subsituting these values by BODMAS rule
- 96 ÷ 3 × 5 + 56 -16 = 120
- 32 × 5 + 56 - 16 = 120
- 160 + 56 -16 = 120
- 216 - 16 = 120
- 200 ≠ 120( LHS ≠ RHS )
Option 4. -, +, ÷, × , =by subsituting these values by BODMAS rule
- 96 - 3 + 5 ÷ 56 × 16 = 120
- 96 - 3 + 0.08 × 16 = 120
- 96 - 3 + 1.28 = 120
- 97.28 - 3 = 120
- 94.28 ≠ 120 ( LHS ≠ RHS )
Hence, " ÷, × , -, +, =" is the correct answer.
Puzzle Question 5:
In a zoo, there are Monkeys and Pigeons. If heads are counted, there are 200 and if legs are counted, there are 580. How many Pigeons are there?
Answer (Detailed Solution Below)
Puzzle Question 5 Detailed Solution
If we summarised the information:
→ Total heads = 200; it means total no of animals is also 200
M = monkeys
P = Pigeons
M + P = 200 → (1)
Monkeys have 4 legs and Pigeons have 2 legs;
It means; 4 M + 2 P = 580 → (2)
→ Equation (1) × 2
→ (M + P = 200) × 2
→ 2 M + 2 P = 400 → (3)
→ Equation (2) ─ (3)
→ 4 M + 2 P – 2M – 2P = 580 – 400
→ 2 M = 180
→ M = 180 ÷ 2
→ M = 90 = no of Monkeys
By putting value in equation (1)
→ M + P = 200
→ 90 + P = 200
→ P = 200 ─ 90
→ P = 110 = no of Pigeons
Hence, 110 Pigeons were there.Top Puzzle MCQ Objective Questions
Three-fifths of my current age is the same as five-sixths of that of one of my cousins’. My age ten years ago will be his age four years hence. My current age is ______ years.
Answer (Detailed Solution Below)
Puzzle Question 6 Detailed Solution
Download Solution PDFLet my current age = x years and my cousin’s age = y years.
Three-fifths of my current age is the same as five-sixths of that of one of my cousins’,
⇒ 3x/5 = 5y/6
⇒ 18x = 25y
My age ten years ago will be his age four years hence,
⇒ x – 10 = y + 4
⇒ y = x – 14,
⇒ 18x = 25(x – 14)
⇒ 18x = 25x – 350
⇒ 7x = 350
∴ x = 50 yearsMohit and Sudesh bought pens and notebooks from the same shop. Mohit bought 3 pens and 6 notebooks by paying an amount of Rs. 180. Sudesh bought 5 pens and 2 notebooks by paying an amount of Rs. 116. How much did Mohit spend on buying notebooks?
Answer (Detailed Solution Below)
Puzzle Question 7 Detailed Solution
Download Solution PDFLet,
Price of one pen = x
Price of one notebook = y
Given:
1) Mohit bought 3 pens and 6 notebooks by paying an amount of Rs. 180
=> 3x + 6y = 180
=> 3x = 180 – 6y
=> x = (180 – 6y) ÷ 3
=> x = 60 – 2y --------------- (i)
2) Sudesh bought 5 pens and 2 notebooks by paying an amount of Rs. 116
=> 5x + 2y = 116
Putting the value of x from eq (i)
=> 5(60 – 2y) + 2y = 116
=> 300 – 10y + 2y = 116
=> 300 – 116 = 10y – 2y
=> 8y = 184
=> y = 23
Mohit spend on buying 6 notebooks
=> 6y = 6 × 23 = 138
Hence, Mohit spend “Rs. 138” on buying notebooks.After interchanging the given two numbers and two signs what will be the values of equation (I) and (II) respectively?
× and +, 3 and 9
I. 7 × 9 – 8 ÷ 2 + 3
Answer (Detailed Solution Below)
Puzzle Question 8 Detailed Solution
Download Solution PDFAccording to the question, after interchanging the given two signs and two numbers i.e :
- × and +
- Two numbers 3 and 9
So,
I. 7 + 3 – 8 ÷ 2 × 9
⇒ 7 + 3 - 4 × 9
⇒ 7 + 3 - 36
⇒ 10 - 36
⇒ -26
II. 4 + 3 – 9 × 8 ÷ 2
⇒ 4 + 3 - 9 × 4
⇒ 4 + 3 - 36
⇒ 7 - 36
⇒ -29
Here, values of equation (I) and (II) are (-26) and (-29) respectively.
Ages of father and son add up to 50. Six years back father's age was 6 more than thrice his son's age. What will be the father's age 6 years hence?
Answer (Detailed Solution Below)
Puzzle Question 9 Detailed Solution
Download Solution PDFLet the age of father be F and that of son be S.
F + S = 50 (Given)
S = 50 – F _____ (i)
Six years back father's age was 6 more than thrice his son's age.
According to problem:
(F – 6) = 3(S – 6) + 6 _____ (ii)
Substituting the value of equation (i) in (ii), we get:
F – 6 = 3(50 – F – 6) + 6
⇒ F – 6 = 3(44 – F) + 6
⇒ F – 6 = 132 – 3F + 6
⇒ F + 3F = 132 + 6 + 6
⇒ 4F = 144
⇒ F = 144/4
⇒ F = 36
So, father's age 6 years hence = (36 + 6) = 42
Hence, ‘42’ is the correct answer.
The weights of three boxes are 3 kg, 8 kg and 12 kg. Which of the following CANNOT be the total weight, in kg, of any combination of these boxes?
Answer (Detailed Solution Below)
Puzzle Question 10 Detailed Solution
Download Solution PDFThe logic followed here is:
1) 15 → 12 + 3 = 15 kg
2) 20 → 12 + 8 = 20 kg
3) 23 → 12 + 8 + 3 = 23 kg
4) 21 → It CANNOT be the total weight, in kg, of any combination of these boxes.
Hence, ‘21’ is the correct answer.In a group of bulls and hens, the number of legs is 48 more than twice the number of heads. The number of bulls is ________.
Answer (Detailed Solution Below)
Puzzle Question 11 Detailed Solution
Download Solution PDFLet the number of bulls be ‘a’ and the number of hens be ‘b’.
So, the total numbers of heads are (a + b) and total numbers of legs are (4a + 2b).
According to question:
(4a + 2b) = 2(a + b) + 48
4a + 2b = 2a + 2b + 48
4a + 2b – 2a – 2b = 48
2a = 48
a = 24
So, the number of bulls is 24.
Hence, ‘24’ is the correct answer.
A side of a square-shaped park is 12 m. If a square-shaped garden with a side of 24 m is developed around the park, what will be the total area of the park including the garden?
Answer (Detailed Solution Below)
Puzzle Question 12 Detailed Solution
Download Solution PDFGiven:
A side of a square-shaped park is 12 m.
- If a square-shaped garden with a side of 24 m is developed around the park, then the garden with the park will look like the picture below:
Formula:
Area of square = Side × Side
Calculation:
=> Total area of the park including the garden = Area of the outer square = 24 × 24
=> Area of square = 576 m2
Hence, the total area of the park including the garden is 576 m2.Seven years from now, Anamika will be as old as Malini was 4 years ago. Srinidhi was born 2 years ago. The average age of Anamika, Malini and Srinidhi 10 years from now will be 33 years. What is the present age of Anamika?
Answer (Detailed Solution Below)
Puzzle Question 13 Detailed Solution
Download Solution PDFLet the present age of Anamika be A, Malini be M and that of Srinidhi be S.
The, according to the question:
1) Seven years from now, Anamika will be as old as Malini was 4 years ago.
A + 7 = M - 4
⇒ M = A + 11
S = 2 years
And,
2) Srinidhi was born 2 years ago. The average age of Anamika, Malini and Srinidhi 10 years from now will be 33 years.
\({(A + 10 + M + 10 + S + 10) \over 3} = 33 \)
\(A + M + S + 30 = 33 \times 3\)
A + M + S = 99 - 30
A + M + S = 69
Now, by substituting the above values,
A + (A + 11) + 2 = 69
2A + 13 = 69
A = 56 ÷ 2
A = 28 years
Hence, the present age of Anamika is 28 years is the correct answer.
If + means ×, × means -, ÷ means +, & - means ÷, then,
146 - 2 + 3 × 123 × 5 + 2 = ?
Answer (Detailed Solution Below)
Puzzle Question 14 Detailed Solution
Download Solution PDF
For this question, We have to check the given equation as-
146 – 2 + 3 × 123 × 5 + 2
Symbol | Means |
+ | × |
× | – |
÷ | + |
– | ÷ |
New equation after replacing symbols-
146 ÷ 2 × 3 – 123 - 5 × 2
According to the BODMAS rule-
⇒ 73 × 3 – 123 – 5 × 2
⇒ 219 – 123 – 10
⇒ 86
Hence, Option (4) is correct.
By interchanging the two numbers 20 and 36, which of the following equations will be correct?
I. 55 + 42 – 36 × 20 ÷ 9 = 17
II. 20 ÷ 2 × 36 + 81 – 41 = 400
Answer (Detailed Solution Below)
Puzzle Question 15 Detailed Solution
Download Solution PDFBODMAS Table:
Given equation I: 55 + 42 – 36 × 20 ÷ 9 = 17
Now, if '20 and 36' are interchanged, then:
⇒ 55 + 42 – 20 × 36 ÷ 9 = 17
⇒ 55 + 42 – 20 × 4 = 17
⇒ 55 + 42 – 80 = 17
⇒ 97 – 80 = 17
= 17 = 17.
LHS = RHS.
Given equation II: 20 ÷ 2 × 36 + 81 – 41 = 400
Now, if '20 and 36' are interchanged, then:
⇒ 36 ÷ 2 × 20 + 81 – 41 = 400
⇒ 18 × 20 + 81 – 41 = 400
⇒ 360 + 81 – 41 = 400
⇒ 441 – 41 = 400
= 400 = 400
LHS = RHS.
Here, Both I and II are correct equation after interchanging the given symbol.
Hence, the correct answer is "Option 3".