Puzzle MCQ Quiz - Objective Question with Answer for Puzzle - Download Free PDF

Last updated on Jun 5, 2025

Latest Puzzle MCQ Objective Questions

Puzzle Question 1:

If ‘A’ stands for ‘÷’, ‘B’ stands for ‘×’, ‘C’ stands for ‘+’ and ‘D’ stands for ‘–’, then the resultant of which of the following will be 652?

  1. 109 B 6 D 16 A 2 C 6
  2. 109 A 6 D 16 B 2 C 6
  3. 109 B 6 A 16 D 2 C 6
  4. 109 C 6 D 16 A 2 B 6
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : 109 B 6 D 16 A 2 C 6

Puzzle Question 1 Detailed Solution

 

BODMAS table

qImage14137

Given equation: If ‘A’ stands for ‘÷’, ‘B’ stands for ‘×’, ‘C’ stands for ‘+’ and ‘D’ stands for ‘–’

Option 1) 109 B 6 D 16 A 2 C 6

Putting the sign in equation

109 x 6 - 16 ÷ 2 + 6 

⇒109 x 6 - 8 + 6 

⇒654 - 8 + 6

⇒660 - 8

652

Option2) 109 A 6 D 16 B 2 C 6

⇒109 ÷ 6 - 16 x 2 + 6

⇒18.16 - 16 x 2 + 6

⇒18.16 - 32 + 6

⇒24.16 - 32

⇒-7.84

Option3) 109 B 6 A 16 D 2 C 6

⇒109 x 6 ÷ 16 - 2 + 6

⇒109 x 0.375 - 2 + 6

⇒40.875 - 2  + 6

⇒46.875 - 2

⇒44.875

Option 4) 109 C 6 D 16 A 2 B 6

⇒109 + 6 - 16 ÷ 2 x 6

⇒109 + 6 - 8 x 6

⇒109 + 6 - 48

⇒115 - 48

⇒67

Hence the correct answer is "Option 1".

Puzzle Question 2:

Read the information and answer the question given below:

Five friends are working in a company. Kapil, Shiva and Hari are intelligent.

Kapil, Ravi and Jitin are hard working.

Ravi, Hari and Jitin are honest.

Which of the following persons is neither honest nor hardworking but is intelligent?

  1. Shiva
  2. Hari
  3. Jitin
  4. Kapil
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : Shiva

Puzzle Question 2 Detailed Solution

Given: Five friends Kapil, Ravi, Jatin, Hari, Shiva are working in a company.

Explanation:

Kapil, Shiva and Hari are intelligent.

Kapil, Ravi and Jitin are hard working.

Ravi, Hari and Jitin are honest.

 

Friends

Strength

Strength

Strength

Kapil

Intelligent

Hardworking

 

Shiva

Intelligent

 

 

Hari

Intelligent

 

Honest

Jitin

 

Hardworking

Honest

Ravi

 

Hardworking

Honest

 

According to above table, shiva is neither honest nor hardworking but is intelligent.

Hence, Option 1 is the correct answer.

Puzzle Question 3:

If 20 - 10 méans 200, 8 ÷ 4 means 12, 6 × 2 means 4 and 20 + 5 means 4, then

100 - 10 × 1000 ÷ 1000 +100 × 10 = ?

  1. 1910
  2. 0
  3. 10
  4. 1090
  5. None of the above

Answer (Detailed Solution Below)

Option 2 : 0

Puzzle Question 3 Detailed Solution

BODMAS

Symbols are coded as:-

Symbol + - × ÷
Meaning ÷ × - +

 

Given that: 100 - 10 × 1000 ÷ 1000 +100 × 10 = ?

After replacing the symbols with their meanings, we get:-

= 100 × 10 - 1000 + 1000 ÷ 100 - 10

= 100 × 10 - 1000 + 10 - 10 

= 1000 - 1000 + 10 - 10 

= 1010 - 1010

= 0

Hence, " option 2" is the correct answer.

Puzzle Question 4:

Select the correct combination of mathematical signs to replace the * signs and to balance the given equation.

96 * 3 * 5 * 56 * 16 * 120

  1. ÷, × , -, +, =
  2. × , ÷, +, -, =
  3. ÷, × , +, -, =
  4. -, +, ÷, × , =
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : ÷, × , -, +, =

Puzzle Question 4 Detailed Solution

BODMAS table

6203fea433474e3b330f0951 22-7-22 Shashi Savita D1

Given : 96 * 3 * 5 * 56 * 16 * 120

Option 1. ÷, × , -, +, = by substituting these values by BODMAS rule

  • 96 ÷ 3 × 5 - 56 +16 = 120
  • 32 × 5 - 56 +16 = 120
  • 160 - 56 +16 = 120
  • 176 - 56 = 120
  • 120 = 120 (LHS = RHS )

Option 2.× , ÷, +, -, =by substituting these values by BODMAS rule

  • 96 × 3 ÷ 5 + 56 -16 = 120
  • 96 × 0.6 + 56 -16 = 120
  • 57.6 + 56 - 16 = 120
  • 113.6 ≠ 120 (LHS ≠ RHS )

Option 3.÷, × , +, -, =by subsituting these values by BODMAS rule

  • 96 ÷ 3 × 5 + 56 -16 = 120
  • 32 × 5 + 56 - 16 = 120
  • 160 + 56 -16 = 120
  • 216 - 16 = 120
  • 200 ≠ 120( LHS ≠ RHS )

Option 4. -, +, ÷, × , =by subsituting these values by BODMAS rule

  • 96 - 3 + 5 ÷ 56 × 16 = 120
  • 96 - 3 + 0.08 × 16 = 120
  • 96 - 3 + 1.28 = 120
  • 97.28 - 3 = 120
  • 94.28 ≠ 120 ( LHS ≠ RHS )

Hence, " ÷, × , -, +, =" is the correct answer.

Puzzle Question 5:

In a zoo, there are Monkeys and Pigeons. If heads are counted, there are 200 and if legs are counted, there are 580. How many Pigeons are there?

  1. 90
  2. 100
  3. 110
  4. 120
  5. None of the above

Answer (Detailed Solution Below)

Option 3 : 110

Puzzle Question 5 Detailed Solution

If we summarised the information:

→ Total heads = 200; it means total no of animals is also 200

M = monkeys

P = Pigeons

M + P = 200 → (1)

Monkeys have 4 legs and Pigeons have 2 legs;

It means; 4 M + 2 P = 580 → (2)

→ Equation (1) × 2

→ (M + P = 200) × 2

→ 2 M + 2 P = 400 → (3)

→ Equation (2) ─ (3)

→ 4 M + 2 P – 2M – 2P  = 580 – 400

→ 2 M = 180

→ M = 180 ÷ 2

→ M = 90 = no of Monkeys

By putting value in equation (1)

→ M + P = 200

→ 90 + P = 200

→ P = 200 ─ 90

→ P = 110 = no of Pigeons

Hence, 110 Pigeons were there.

Top Puzzle MCQ Objective Questions

Three-fifths of my current age is the same as five-sixths of that of one of my cousins’. My age ten years ago will be his age four years hence. My current age is ______ years.

  1. 55
  2. 45
  3. 60
  4. 50

Answer (Detailed Solution Below)

Option 4 : 50

Puzzle Question 6 Detailed Solution

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Let my current age = x years and my cousin’s age = y years.

Three-fifths of my current age is the same as five-sixths of that of one of my cousins’,

⇒ 3x/5 = 5y/6

⇒ 18x = 25y

My age ten years ago will be his age four years hence,

⇒ x – 10 = y + 4

⇒ y = x – 14,

⇒ 18x = 25(x – 14)

⇒ 18x = 25x – 350

⇒ 7x = 350

∴ x = 50 years

Mohit and Sudesh bought pens and notebooks from the same shop. Mohit bought 3 pens and 6 notebooks by paying an amount of Rs. 180. Sudesh bought 5 pens and 2 notebooks by paying an amount of Rs. 116. How much did Mohit spend on buying notebooks? 

  1. Rs. 84
  2. Rs. 115
  3. Rs. 138
  4. Rs. 122

Answer (Detailed Solution Below)

Option 3 : Rs. 138

Puzzle Question 7 Detailed Solution

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Let,

Price of one pen = x

Price of one notebook = y

Given:

1) Mohit bought 3 pens and 6 notebooks by paying an amount of Rs. 180

=> 3x + 6y = 180

=> 3x = 180 – 6y

=> x = (180 – 6y) ÷ 3

=> x = 60 – 2y --------------- (i)

2) Sudesh bought 5 pens and 2 notebooks by paying an amount of Rs. 116

=> 5x + 2y = 116

Putting the value of x from eq (i)

=> 5(60 – 2y) + 2y = 116

=> 300 – 10y + 2y = 116

=> 300 – 116 = 10y – 2y

=> 8y = 184

=> y = 23

Mohit spend on buying 6 notebooks

=> 6y = 6 × 23 = 138

Hence, Mohit spend Rs. 138” on buying notebooks.

After interchanging the given two numbers and two signs what will be the values of equation (I) and (II) respectively? 

× and +, 3 and 9

I. 7 × 9 – 8 ÷ 2 + 3

II. 4 × 9 – 3 + 8 ÷ 2

  1. 0, 1
  2. –26, –29
  3. 6, 0
  4. 12, 13

Answer (Detailed Solution Below)

Option 2 : –26, –29

Puzzle Question 8 Detailed Solution

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BODMAS

According to the question, after interchanging the given two signs and two numbers i.e :

  • × and +
  • Two numbers 3 and 9

So,

I. 7 + 3 – 8 ÷ 2 × 9

⇒ 7 + 3 - × 9

⇒ 7 + 3 - 36

10 - 36

⇒ -26

II. 4 + 3 – 9 × 8 ÷ 2

⇒ 4 + 3 - 9 × 4

4 + 3 - 36

7 - 36

⇒ -29

Here, values of equation (I) and (II)  are (-26) and (-29) respectively.

Hence, "Option - (2)" is the correct answer.

Ages of father and son add up to 50. Six years back father's age was 6 more than thrice his son's age. What will be the father's age 6 years hence?

  1. 40 years
  2. 42 years
  3. 50 years
  4. 48 years

Answer (Detailed Solution Below)

Option 2 : 42 years

Puzzle Question 9 Detailed Solution

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Let the age of father be F and that of son be S.

F + S = 50 (Given)

S = 50 – F     _____ (i)

Six years back father's age was 6 more than thrice his son's age.

According to problem:

(F – 6) = 3(S – 6) + 6     _____ (ii)

Substituting the value of equation (i) in (ii), we get:

F – 6 = 3(50 – F – 6) + 6

⇒ F – 6 = 3(44 – F) + 6

⇒ F – 6 = 132 – 3F + 6

⇒ F + 3F = 132 + 6 + 6

⇒ 4F = 144

⇒ F = 144/4

⇒ F = 36

So, father's age 6 years hence = (36 + 6) = 42

Hence, ‘42’ is the correct answer.

The weights of three boxes are 3 kg, 8 kg and 12 kg. Which of the following CANNOT be the total weight, in kg, of any combination of these boxes?

  1. 15
  2. 20
  3. 23
  4. 21

Answer (Detailed Solution Below)

Option 4 : 21

Puzzle Question 10 Detailed Solution

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The logic followed here is:

1) 15 → 12 + 3 = 15 kg

2) 20 → 12 + 8 = 20 kg

3) 23 → 12 + 8 + 3 = 23 kg

4) 21 → It CANNOT be the total weight, in kg, of any combination of these boxes.

Hence, ‘21’ is the correct answer.

In a group of bulls and hens, the number of legs is 48 more than twice the number of heads. The number of bulls is ________.

  1. 50
  2. 48
  3. 26
  4. 24

Answer (Detailed Solution Below)

Option 4 : 24

Puzzle Question 11 Detailed Solution

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Let the number of bulls be ‘a’ and the number of hens be ‘b’.

So, the total numbers of heads are (a + b) and total numbers of legs are (4a + 2b).

According to question:

(4a + 2b) = 2(a + b) + 48

4a + 2b = 2a + 2b + 48

4a + 2b – 2a – 2b = 48

2a = 48

a = 24

So, the number of bulls is 24.

Hence, ‘24’ is the correct answer.

A side of a square-shaped park is 12 m. If a square-shaped garden with a side of 24 m is developed around the park, what will be the total area of the park including the garden?

  1. 324 m2
  2. 576 m2
  3. 288 m2
  4. 144 m2

Answer (Detailed Solution Below)

Option 2 : 576 m2

Puzzle Question 12 Detailed Solution

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Given:

A side of a square-shaped park is 12 m.

  • If a square-shaped garden with a side of 24 m is developed around the park, then the garden with the park will look like the picture below:

F1 Savita SSC 9-6-22 D23

Formula:

Area of square = Side × Side

Calculation:

=> Total area of the park including the garden = Area of the outer square = 24 × 24

=> Area of square = 576 m2

Hence, the total area of the park including the garden is 576 m2.

Seven years from now, Anamika will be as old as Malini was 4 years ago. Srinidhi was born 2 years ago. The average age of Anamika, Malini and Srinidhi 10 years from now will be 33 years. What is the present age of Anamika?

  1. 30 years
  2. 29 years
  3. 28 years
  4. 31 years

Answer (Detailed Solution Below)

Option 3 : 28 years

Puzzle Question 13 Detailed Solution

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Let the present age of Anamika be A, Malini be M and that of Srinidhi be S.

The, according to the question:

1) Seven years from now, Anamika will be as old as Malini was 4 years ago. 

A + 7 = M - 4

⇒ M = A + 11

S = 2 years

And, 

2) Srinidhi was born 2 years ago. The average age of Anamika, Malini and Srinidhi 10 years from now will be 33 years.

\({(A + 10 + M + 10 + S + 10) \over 3} = 33 \)

\(A + M + S + 30 = 33 \times 3\)

A + M + S = 99 - 30

A + M + S = 69 

Now, by substituting the above values,

A + (A + 11) + 2 = 69 

2A + 13 = 69

A = 56 ÷ 2

A = 28 years

Hence, the present age of Anamika is 28 years is the correct answer.

If + means ×, × means -, ÷ means +, &  -  means ÷, then,

146 -  2 + 3 × 123 × 5 + 2 = ?

  1. 132
  2. 128
  3. 116
  4. 86

Answer (Detailed Solution Below)

Option 4 : 86

Puzzle Question 14 Detailed Solution

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For this question, We have to check the given equation as-

146 –  2 + 3 × 123 × 5 + 2

Symbol Means
+ ×
×  
÷ +
  ÷

New equation after replacing symbols-

146 ÷ 2 × 3 – 123 - 5 × 2

According to the BODMAS rule-

⇒ 73 × 3 –  123 – 5 × 2

⇒ 219 –  123 –  10

⇒ 86

Hence, Option (4) is correct.

By interchanging the two numbers 20 and 36, which of the following equations will be correct?

I. 55 + 42 – 36 × 20 ÷ 9 = 17

II. 20 ÷ 2 × 36 + 81 – 41 = 400

  1. Only I 
  2. Only II
  3. Both I and II
  4. Neither I nor II 

Answer (Detailed Solution Below)

Option 3 : Both I and II

Puzzle Question 15 Detailed Solution

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BODMAS Table: 

qImage14137

Given equation I: 55 + 42 – 36 × 20 ÷ 9 = 17

Now, if '20 and 36' are interchanged, then:

⇒ 55 + 42 – 20 × 36 ÷ 9 = 17

⇒ 55 + 42 – 20 × 4 = 17

⇒ 55 + 42 – 80 = 17

97 – 80 = 17

17 = 17.

LHS = RHS.

Given equation II: 20 ÷ 2 × 36 + 81 – 41 = 400

Now, if '20 and 36' are interchanged, then:

36 ÷ 2 × 20 + 81 – 41 = 400

18 × 20 + 81 – 41 = 400

⇒ 360 + 81 – 41 = 400

⇒ 441 – 41 = 400

400 = 400

LHS = RHS.

Here, Both I and II are correct equation after interchanging the given symbol.

Hence, the correct answer is "Option 3".

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