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BODMAS table

Given equation: If ‘A’ stands for ‘÷’, ‘B’ stands for ‘×’, ‘C’ stands for ‘+’ and ‘D’ stands for ‘–’

Option 1) 109 B 6 D 16 A 2 C 6

Putting the sign in equation

⇒109 x 6 - 16 ÷ 2 + 6 

⇒109 x 6 - 8 + 6 

⇒654 - 8 + 6

⇒660 - 8

⇒652

Option2) 109 A 6 D 16 B 2 C 6

⇒109 ÷ 6 - 16 x 2 + 6

⇒18.16 - 16 x 2 + 6

⇒18.16 - 32 + 6

⇒24.16 - 32

⇒-7.84

Option3) 109 B 6 A 16 D 2 C 6

⇒109 x 6 ÷ 16 - 2 + 6

⇒109 x 0.375 - 2 + 6

⇒40.875 - 2  + 6

⇒46.875 - 2

⇒44.875

Option 4) 109 C 6 D 16 A 2 B 6

⇒109 + 6 - 16 ÷ 2 x 6

⇒109 + 6 - 8 x 6

⇒109 + 6 - 48

⇒115 - 48

⇒67

Hence the correct answer is "Option 1".

Given: Five friends Kapil, Ravi, Jatin, Hari, Shiva are working in a company.

Explanation:

Kapil, Shiva and Hari are intelligent.

Kapil, Ravi and Jitin are hard working.

Ravi, Hari and Jitin are honest.

According to above table, shiva is neither honest nor hardworking but is intelligent.

Hence, Option 1 is the correct answer.

Symbols are coded as:-

Given that: 100 - 10 × 1000 ÷ 1000 +100 × 10 = ?

After replacing the symbols with their meanings, we get:-

= 100 × 10 - 1000 + 1000 ÷ 100 - 10

= 100 × 10 - 1000 + 10 - 10 

= 1000 - 1000 + 10 - 10 

= 1010 - 1010

= 0

Hence, " option 2" is the correct answer.

BODMAS table

Given : 96 * 3 * 5 * 56 * 16 * 120

Option 1. ÷, × , -, +, = by substituting these values by BODMAS rule

• 96 ÷ 3 × 5 - 56 +16 = 120
• 32 × 5 - 56 +16 = 120
• 160 - 56 +16 = 120
• 176 - 56 = 120
• 120 = 120 (LHS = RHS )

Option 2.× , ÷, +, -, =by substituting these values by BODMAS rule

• 96 × 3 ÷ 5 + 56 -16 = 120
• 96 × 0.6 + 56 -16 = 120
• 57.6 + 56 - 16 = 120
• 113.6 ≠ 120 (LHS ≠ RHS )

Option 3.÷, × , +, -, =by subsituting these values by BODMAS rule

• 96 ÷ 3 × 5 + 56 -16 = 120
• 32 × 5 + 56 - 16 = 120
• 160 + 56 -16 = 120
• 216 - 16 = 120
• 200 ≠ 120( LHS ≠ RHS )

Option 4. -, +, ÷, × , =by subsituting these values by BODMAS rule

• 96 - 3 + 5 ÷ 56 × 16 = 120
• 96 - 3 + 0.08 × 16 = 120
• 96 - 3 + 1.28 = 120
• 97.28 - 3 = 120
• 94.28 ≠ 120 ( LHS ≠ RHS )

Hence, " ÷, × , -, +, =" is the correct answer.

If we summarised the information:

→ Total heads = 200; it means total no of animals is also 200

M = monkeys

P = Pigeons

M + P = 200 → (1)

Monkeys have 4 legs and Pigeons have 2 legs;

It means; 4 M + 2 P = 580 → (2)

→ Equation (1) × 2

→ (M + P = 200) × 2

→ 2 M + 2 P = 400 → (3)

→ Equation (2) ─ (3)

→ 4 M + 2 P – 2M – 2P  = 580 – 400

→ 2 M = 180

→ M = 180 ÷ 2

→ M = 90 = no of Monkeys

By putting value in equation (1)

→ M + P = 200

→ 90 + P = 200

→ P = 200 ─ 90

→ P = 110 = no of Pigeons

Let my current age = x years and my cousin’s age = y years.

Three-fifths of my current age is the same as five-sixths of that of one of my cousins’,

⇒ 3x/5 = 5y/6

⇒ 18x = 25y

My age ten years ago will be his age four years hence,

⇒ x – 10 = y + 4

⇒ y = x – 14,

⇒ 18x = 25(x – 14)

⇒ 18x = 25x – 350

⇒ 7x = 350

Let,

Price of one pen = x

Price of one notebook = y

Given:

1) Mohit bought 3 pens and 6 notebooks by paying an amount of Rs. 180

=> 3x + 6y = 180

=> 3x = 180 – 6y

=> x = (180 – 6y) ÷ 3

=> x = 60 – 2y --------------- (i)

2) Sudesh bought 5 pens and 2 notebooks by paying an amount of Rs. 116

=> 5x + 2y = 116

Putting the value of x from eq (i)

=> 5(60 – 2y) + 2y = 116

=> 300 – 10y + 2y = 116

=> 300 – 116 = 10y – 2y

=> 8y = 184

=> y = 23

Mohit spend on buying 6 notebooks

=> 6y = 6 × 23 = 138

According to the question, after interchanging the given two signs and two numbers i.e :

• × and +
• Two numbers 3 and 9

So,

I. 7 + 3 – 8 ÷ 2 × 9

⇒ 7 + 3 - 4 × 9

⇒ 7 + 3 - 36

⇒ 10 - 36

⇒ -26

II. 4 + 3 – 9 × 8 ÷ 2

⇒ 4 + 3 - 9 × 4

⇒ 4 + 3 - 36

⇒ 7 - 36

⇒ -29

Let the age of father be F and that of son be S.

F + S = 50 (Given)

S = 50 – F     _____ (i)

Six years back father's age was 6 more than thrice his son's age.

According to problem:

(F – 6) = 3(S – 6) + 6     _____ (ii)

Substituting the value of equation (i) in (ii), we get:

F – 6 = 3(50 – F – 6) + 6

⇒ F – 6 = 3(44 – F) + 6

⇒ F – 6 = 132 – 3F + 6

⇒ F + 3F = 132 + 6 + 6

⇒ 4F = 144

⇒ F = 144/4

⇒ F = 36

So, father's age 6 years hence = (36 + 6) = 42

Hence, ‘42’ is the correct answer.

The logic followed here is:

1) 15 → 12 + 3 = 15 kg

2) 20 → 12 + 8 = 20 kg

3) 23 → 12 + 8 + 3 = 23 kg

4) 21 → It CANNOT be the total weight, in kg, of any combination of these boxes.

Let the number of bulls be ‘a’ and the number of hens be ‘b’.

So, the total numbers of heads are (a + b) and total numbers of legs are (4a + 2b).

According to question:

(4a + 2b) = 2(a + b) + 48

4a + 2b = 2a + 2b + 48

4a + 2b – 2a – 2b = 48

2a = 48

a = 24

So, the number of bulls is 24.

Hence, ‘24’ is the correct answer.

Given:

A side of a square-shaped park is 12 m.

• If a square-shaped garden with a side of 24 m is developed around the park, then the garden with the park will look like the picture below:

Formula:

Area of square = Side × Side

Calculation:

=> Total area of the park including the garden = Area of the outer square = 24 × 24

=> Area of square = 576 m2

Let the present age of Anamika be A, Malini be M and that of Srinidhi be S.

The, according to the question:

1) Seven years from now, Anamika will be as old as Malini was 4 years ago. 

A + 7 = M - 4

⇒ M = A + 11

S = 2 years

And, 

2) Srinidhi was born 2 years ago. The average age of Anamika, Malini and Srinidhi 10 years from now will be 33 years.

\({(A + 10 + M + 10 + S + 10) \over 3} = 33 \)

\(A + M + S + 30 = 33 \times 3\)

A + M + S = 99 - 30

A + M + S = 69 

Now, by substituting the above values,

A + (A + 11) + 2 = 69 

2A + 13 = 69

A = 56 ÷ 2

A = 28 years

Hence, the present age of Anamika is 28 years is the correct answer.

For this question, We have to check the given equation as-

146 –  2 + 3 × 123 × 5 + 2

New equation after replacing symbols-

146 ÷ 2 × 3 – 123 - 5 × 2

According to the BODMAS rule-

⇒ 73 × 3 –  123 – 5 × 2

⇒ 219 –  123 –  10

⇒ 86

Hence, Option (4) is correct.

BODMAS Table: 

Given equation I: 55 + 42 – 36 × 20 ÷ 9 = 17

Now, if '20 and 36' are interchanged, then:

⇒ 55 + 42 – 20 × 36 ÷ 9 = 17

⇒ 55 + 42 – 20 × 4 = 17

⇒ 55 + 42 – 80 = 17

⇒ 97 – 80 = 17

= 17 = 17.

LHS = RHS.

Given equation II: 20 ÷ 2 × 36 + 81 – 41 = 400

Now, if '20 and 36' are interchanged, then:

⇒ 36 ÷ 2 × 20 + 81 – 41 = 400

⇒ 18 × 20 + 81 – 41 = 400

⇒ 360 + 81 – 41 = 400

⇒ 441 – 41 = 400

= 400 = 400

LHS = RHS.

Here, Both I and II are correct equation after interchanging the given symbol.

Hence, the correct answer is "Option 3".