Basic Problems MCQ Quiz - Objective Question with Answer for Basic Problems - Download Free PDF
Last updated on Jun 7, 2025
Latest Basic Problems MCQ Objective Questions
Basic Problems Question 1:
In ΔABC, ∠C = 90° and CD ⊥ AB, also ∠A = 65°, then ∠CBA is equal to
Answer (Detailed Solution Below)
Basic Problems Question 1 Detailed Solution
Given:
∠C = 90°
CD ⊥ AB
∠A = 65°
Concept used:
The sum of the angles of a triangle is 180°.
Calculation:
In ΔABC,
∠BAC + ∠CBA + ∠ACB = 180°
⇒ 65° + 90° + ∠CBA = 180°
⇒ ∠CBA = 25°
Important Points
We can arrive at the solution based on the perpendicular as well. But it is more time-consuming. Since ∠A and ∠C are given, it is wise to directly apply them in the concept and get the solution.
Basic Problems Question 2:
If the bisectors of angle ∠ABC and ∠ACB of a triangle ABC meet at a point 0 and if ∠A = 60°, then ∠BOC =
Answer (Detailed Solution Below)
Basic Problems Question 2 Detailed Solution
In triangle \( ABC \), if the bisectors of \( \angle ABC \) and \( \angle ACB \) meet at point \( O \) and \( \angle A = 60^\circ \), then the angle \( \angle BOC \) is given by:
\[ \angle BOC = 90^\circ + \frac{\angle A}{2} \]
Substituting \( \angle A = 60^\circ \):
\[ \angle BOC = 90^\circ + \frac{60^\circ}{2} = 120^\circ \]
Thus, the measure of \( \angle BOC \) is:
\[ \boxed{120^\circ} \]
Basic Problems Question 3:
In △ABC, DE || AC, where D and E are the points on sides AB and BC, respectively. If BD = 8 cm and AD = 7 cm, then what is the ratio of the area of △BDE to the trapezium ADEC?
Answer (Detailed Solution Below)
Basic Problems Question 3 Detailed Solution
Given:
In △ABC, DE || AC
BD = 8 cm, AD = 7 cm
Formula used:
By Basic Proportionality Theorem (Thales' theorem):
If DE || AC, then
Area of two similar triangles is proportional to the square of corresponding sides.
Ratio of areas = (BD / AB)2
Calculation:
AB = AD + BD = 7 + 8 = 15 cm
Ratio of areas of △BDE to △ABC = (8/15)2 = 64/225
Area of trapezium ADEC = Area of △ABC - Area of △BDE
Required ratio:
Area(△BDE) : Area(ADEC)
= 64 : (225 - 64)
= 64 : 161
∴ The ratio of the area of △BDE to the trapezium ADEC is 64 : 161.
Basic Problems Question 4:
ABC is a triangle such that ∠A = 90º and P is any point on the side AC. If BC = 10 cm, AC = 8 cm and BP = 9 cm, then what is the length of AP?
Answer (Detailed Solution Below)
Basic Problems Question 4 Detailed Solution
Given:
In ΔABC, ∠A = 90º
BC = 10 cm
AC = 8 cm
BP = 9 cm
Formula Used:
Using Pythagoras theorem in ΔABC:
\(AB^2 + AC^2 = BC^2\)
Using Pythagoras theorem in ΔABP:
\(AB^2 + AP^2 = BP^2\)
Calculation:
Using Pythagoras theorem in ΔABC:
AB2 + 82 = 102
⇒ AB2 + 64 = 100
⇒ AB2 = 36
⇒ AB = 6 cm
Using Pythagoras theorem in ΔABP:
62 + AP2 = 92
⇒ 36 + AP2 = 81
⇒ AP2 = 45
⇒ AP = √45
⇒ AP = 3√5 cm
The correct answer is option 4.
Basic Problems Question 5:
In an equilateral triangle ABC, AD perpendicular to BC, then which of the following is true ?
Answer (Detailed Solution Below)
Basic Problems Question 5 Detailed Solution
Given:
In an equilateral triangle ABC, AD is perpendicular to BC.
Calculation:
Let the side of the equilateral triangle be AB = a.
AD2 = AB2 - BD2
⇒ AD2 = a2 - (a/2)2
⇒ AD2 = a2 - a2/4
⇒ AD2 = 3/4 a2
Since, a = AB, so a2 = AB2
⇒ AD2 = 3/4 AB2
⇒ 4AD2 = 3 AB2
⇒ 3 AB2 = 4 AD2
∴ The correct answer is option (2).
Top Basic Problems MCQ Objective Questions
In ΔABC, AB = 8 cm. ∠A is bisected internally to intersect BC at D. BD = 6 cm and DC = 7.5 cm. What is the length of CA?
Answer (Detailed Solution Below)
Basic Problems Question 6 Detailed Solution
Download Solution PDFGiven:
In ΔABC, AB = 8cm
∠A bisected internally to intersect BC at D.
AB = 8 cm, BD = 6 cm and DC = 7.5 cm
Concept used:
In a triangle, the angle bisector of an angle is divides the opposite side to the angle in the ratio of the remaining two sides.
\(\frac{AB}{AC} = \frac{BD}{DC}\)
Calculation:
AB = 8 cm, ∠A is bisected internally to intersect BC at D,
⇒ AB/AC = BD/CD
⇒ 8/AC = 6/7.5
∴ AC = 10 cmChoose the CORRECT option if the two sides of a triangle are of length 3 cm and 8 cm and the length of its third side is x cm.
Answer (Detailed Solution Below)
Basic Problems Question 7 Detailed Solution
Download Solution PDFGiven that,
The two sides of a triangle are of length 3 cm and 8 cm and the length of its third side is x cm.
As we know,
Sum of two sides of triangle is always greater than third side of the triangle.
∴ Sum of two sides of triangle > third side of the triangle.
⇒ 3 + 8 > Third side
⇒ 11 > x
Also,
Another case will be,
⇒ x + 3 > 8
⇒ x > 8 - 3
⇒ x > 5
∴ 5 < x < 11
In a ΔABC, points D and E are lying on AB and AC, respectively. DE is also parallel to the base BC. O is the intersection of BE and CD. If AD : DB = 4 : 3 find the ratio of DO to DC.
Answer (Detailed Solution Below)
Basic Problems Question 8 Detailed Solution
Download Solution PDFConcept:
Similar triangles:
Similar triangle are triangles that have the same shape, but their sizes may vary.
Properties:
- Both have the same shape but sizes may be different
- Each pair of corresponding angles are equal
- The ratio of corresponding sides is the same
Calculation:
In ΔADE and ΔABC
∠A is common
∠D = ∠B and ∠E = ∠C
∴ ΔADE ∼ ΔABC
According to similar triangle property
\(\frac{{AD}}{{AB}} = \frac{{AE}}{{AC}} = \frac{{DE}}{{BC}}\)
\(\begin{array}{l} \frac{4}{{4 + 3}} = \frac{{DE}}{{BC}}\\ \frac{{DE}}{{BC}} = \frac{4}{7} \end{array}\)
Similarly in ΔDOE & ΔBOC
∠DEO = ∠OBC (Corresponding angles are equal)
∠DOE = ∠BOC (vertically opposite angles)
∴ ΔDEO ∼ ΔOBC
\(\begin{array}{l} \frac{{DE}}{{BC}} = \frac{{DO}}{{OC}}\\ \frac{{DO}}{{OC}} = \frac{4}{7} \end{array}\)
Hence, \(\frac{{DO}}{{DC}} = \frac{4}{{4 + 7}} = \frac{4}{{11}}\)
If three sides of a right-angled triangle are (k – 4) cm, k, and (k + 4), then the value of k is:
Answer (Detailed Solution Below)
Basic Problems Question 9 Detailed Solution
Download Solution PDFGiven:
Three sides of the triangle are (k – 4), k and (k + 4).
Formula:
As we know,
Pythagoras Theorem
(Hypotenuse)2 = (Perpendicular)2 + (Base)2
Calculation:
According to the question
(k + 4)2 = (k – 4)2 + k2
⇒ k2 + 16 + 8k = k2 + 16 – 8k + k2
⇒ k2 = 16k
⇒ k = 16
Three sides of a triangle are 8 cm, 6 and 5 cm respectively, then the triangle is
Answer (Detailed Solution Below)
Basic Problems Question 10 Detailed Solution
Download Solution PDFGiven:
Three sides of the triangle are 8 cm, 6 cm and 5 cm respectively.
Concept:
P2 + B2 = H2 (For right angles triangle)
P2 + B2 > H2 (For acute triangle)
P2 + B2 < H2 (For obtuse triangle)
Calculation:
According to the question
82 > 62 + 52
⇒ 64 > 36 + 25
⇒ 64 > 61
Hence, triangle is obtuse angled triangle.
P2 + B2 = H2 (For right angles triangle)
P2 + B2 > H2 (For acute triangle)
P2 + B2 < H2 (For obtuse triangle)
where P, B, and H are the three sides of any triangle, H being the largest side.
So, while applying the given values in the conditions for each type of triangle we need to careful not to put the wrong value in the wrong place.
The base of an isosceles triangle is 10 cm and the altitude is 6/5th of the base. What is the in-radius of the triangle?
Answer (Detailed Solution Below)
Basic Problems Question 11 Detailed Solution
Download Solution PDF⇒ Base of an isosceles triangle is BC = 10 cm
⇒ Altitude of isosceles triangle is AD = 10 × [6/5] = 12 cm
As we know, D is a point of BC
∴ BD = DC = [1/2] × BC = 5 cm
In right angled triangle BDA
⇒ (BA)2 = (BD)2 + (AD)2
⇒ (BA)2 = 52 + 122
⇒ BA = 13 cm = AC
⇒ Area of the ΔABC = [1/2] × BC × AD = [1/2] × 10 × 12 = 60 cm2
⇒ Semi perimeter of ΔABC = (13 + 13 + 10)/2 = 36/2 = 18 cm
As we know,
⇒ In-radius of ΔABC = (Area of Δ)/S = 60/18 = 10/3 cm
Two sides of a triangle are 12.8 m and 9.6 m. If the height of the triangle is 12 m, corresponding to 9.6 m then what its height (in m) corresponding to 12.8 m?
Answer (Detailed Solution Below)
Basic Problems Question 12 Detailed Solution
Download Solution PDFGiven:
Two sides of a triangle = 12.8 m & 9.6 m
Formula used:
Area of a triangle = 1/2 × Base × Height
Calculation:
Let the height of the corresponding side 12.8 m = h
1/2 × 9.6 × 12 = 1/2 × 12.8 × h
⇒ (9.6 × 12)/12.8 = h
⇒ h = 9 m
∴ The height of the triangle corresponding to side with length 12.8 m long = 9 m
Find the area of a triangle whose length of each side is 13 inches, 15 inches and 14 inches.
Answer (Detailed Solution Below)
Basic Problems Question 13 Detailed Solution
Download Solution PDFGiven:
Length of side a = 13 inches
Length of side b = 15 inches
Length of side c = 14 inches
Formula Used:
Heron's formula: Area of a triangle = \(√(s(s-a)(s-b)(s-c))\), where s is the semi-perimeter of the triangle.
Solution:
We can use Heron's formula to find the area of the triangle.
First, we need to calculate the semi-perimeter of the triangle:
s = (a + b + c)/2
⇒ (13 + 15 + 14)/2
⇒ 21
Next, we can use Heron's formula to find the area of the triangle:
Area = \(√(s(s-a)(s-b)(s-c))\)
⇒ \(√(21(21-13)(21-15)(21-14))\)
⇒ √(21(8)(6)(7))
⇒ √(24 x 32 x 72)
⇒ 84
Therefore, the area of the triangle is 84 square inches.
The sides of a triangle are in the ratio 5 : 4 : 3. If the perimeter of the triangle is 84 cm, then what will be the length of the largest side?
Answer (Detailed Solution Below)
Basic Problems Question 14 Detailed Solution
Download Solution PDFGiven:
ratio of sides of a triangle = 5 : 4 : 3
perimeter of the triangle = 84 cm
Formula used:
Perimeter of triangle = Sum of sides
Calculations:
Let the sides of triangle be 5x, 4x and 3x so that they are in ratio 5 : 4 : 3.
∴ 5x + 4x + 3x = 84
⇒ 12x = 84
⇒ x = 7 cm
So, the sides of triangles are 35, 28 and 21 meters.
∴ The length of the largest side is 35 m.
In ΔDEF, M and N are the points on sides DE and DF respectively. MN is parallel to EF and MN ∶ EF = 2 ∶ 5. If DE = 60 cm, then what is the length of ME?
Answer (Detailed Solution Below)
Basic Problems Question 15 Detailed Solution
Download Solution PDFCalculation:
Consider the following figure :
MN || EF
⇒ ∆DMN is similar to ∆DEF
⇒ DM/DE= DN/DF = MN/EF
Given,
MN/EF = 2 ∶ 5 and DE = 60
⇒ 2/5 = DM/60
⇒ DM = 2 × 12 = 24 cm
∴ ME = DE - DM = 60 - 24 = 36 cm
∴ Option 4 is the correct answer.