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The value of sin2 θ + \(\rm \frac{1}{1+\tan^2 \theta}\) will be? 

This question was previously asked in
Bihar STET TGT (Maths) Official Paper-I (Held On: 04 Sept, 2023 Shift 2)
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  1. 1
  2. -1
  3. 0
  4. none of these

Answer (Detailed Solution Below)

Option 1 : 1
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Detailed Solution

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Calculation:

sin2 θ + \(\rm \frac{1}{1+\tan^2 θ}\) = sin2θ + 1/sec2θ = sin2θ + cos2θ = 1

Hence, The Correct Answer is 1.

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