Shan wishes to pour 2 litres of milk into three bottles so that the first bottle holds \(\frac 1 2\) of the milk, the second bottle holds \(\frac 3 4\) of the rest of the milk and the third bottle holds \(\frac 1 5\) of the remaining milk. How much amount of milk will be left with Shan after filling all the three bottles?

Given:

Shan wishes to pour milk = 2 L

First bottle holds = 1/2 of the milk

Second bottle holds = 3/4 of the rest of the milk

Third the bottle holds = 1/5 of the remaining milk 

Calculation:     

Shan wishes to pour milk = 2 L   

⇒ First bottle holds = 1/2 of 2 L = 1 L

 ⇒Remaining milk = 2 L - 1 L = 1L

Second bottle holds = 3/4 of the rest of the milk 

⇒ Second bottle holds = 3/4 of 1 L = 3/4 L

⇒ Remaining milk = 1 - 3/4 = 1/4 L

1 L = 1000 ml

1/4 L = 1000/4 = 250 ml

Third bottle holds = 1/5 of remaining milk

⇒Third bottle milk = 1/5 of 250 = 50 ml

⇒ Remaining holds milk = 250 - 50 = 200 ml

∴ 200 ml of milk will be left with Shan after filling all the three bottles.