Question
Download Solution PDFलंब गोलाकार शंकुचे घनफळ, ज्याच्या पायाची त्रिज्या त्याच्या उंचीच्या 5/9 व्या भाग आणि गोळ्याच्या घनफळाच्या समान आहे. गोलाच्या शंकूच्या त्रिज्येचे गुणोत्तर काय आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFलंब वृत्तीय शंकु:
उंची = h आणि त्रिज्या = r
दिलेले, तर पायाची त्रिज्या त्याच्या उंचीच्या पाच-नवव्या भागाइतकीच आहे:
∴ r = 5h/9
⇒ h = 9r/5
लंब वृत्तीय शंकुचे घनफळ = π/3 × r2 × h
= π/3 × r2 × 9r/5
= 3π/5 × r3
आणि
R त्रिज्या असलेल्या गोलाचे घनफळ = 4π/3 × R3
दोन आकृत्यांचे घनफळ समान असल्यामुळे:
3π/5 × r3 = 4π/3 × R3
⇒ r3/R3 = 20/9
⇒ r3/R3 = 60/27
⇒ r : R =
Last updated on Jun 2, 2025
-> The RRB NTPC Admit Card 2025 has been released on 1st June 2025 on the official website.
-> The RRB Group D Exam Date will be soon announce on the official website. Candidates can check it through here about the exam schedule, admit card, shift timings, exam patten and many more.
-> A total of 1,08,22,423 applications have been received for the RRB Group D Exam 2025.
-> The RRB Group D Recruitment 2025 Notification was released for 32438 vacancies of various level 1 posts like Assistant Pointsman, Track Maintainer (Grade-IV), Assistant, S&T, etc.
-> The minimum educational qualification for RRB Group D Recruitment (Level-1 posts) has been updated to have at least a 10th pass, ITI, or an equivalent qualification, or a National Apprenticeship Certificate (NAC) granted by the NCVT.
-> This is an excellent opportunity for 10th-pass candidates with ITI qualifications as they are eligible for these posts.
-> The selection of the candidates is based on the CBT, Physical Test, and Document Verification.
-> Prepare for the exam with RRB Group D Previous Year Papers.