Question
Download Solution PDFयदि \(\rm z=\frac{1}{3}\begin{vmatrix}i&2i&1\\\ 2i&3i&2\\\ 3&1&3\end{vmatrix}=x+iy;i=\sqrt{-1}\) है, तो Z का मापांक क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFस्पष्टीकरण:
दिया गया है,
\(\rm z=\frac{1}{3}\begin{vmatrix}i&2i&1\\\ 2i&3i&2\\\ 3&1&3\end{vmatrix}\)
\(Z = \frac{1}{3}[[ (i9 – 2) – 2i (6i – 6) 1(2i – 9i)]\)
\(Z = \frac{1}{3}[3+3i] =1 + i \)
|Z| = \(√{1^2+1^2} =\) √2
∴ विकल्प (b) सही है।
Last updated on May 30, 2025
->UPSC has released UPSC NDA 2 Notification on 28th May 2025 announcing the NDA 2 vacancies.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced for cycle 2. The written examination will be held on 14th September 2025.
-> Earlier, the UPSC NDA 1 Exam Result has been released on the official website.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.