Question
Download Solution PDFयदि (X - \(\rm \frac{1}{x}\)) = 6 है, और x > 0 है, तब (x2 - \(\rm \frac{1}{x^2}\)) का मान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है
x - 1/x = 6
प्रयुक्त सूत्र
x + 1/x = √ ((x - 1/x)2 + 4)
x2 - 1/x2 = (x - 1/x)(x + 1/x)
गणना:
x - 1/x = 6
x + 1/x = √ ((x - 1/x)2 + 4)
⇒ x + 1/x = √(40)
⇒ x + 1/x = 2√10
x2 - 1/x2 = (x - 1/x)(x + 1/x)
= 2√10 × 6
= 12√10
सही उत्तर 12√10 है।
Last updated on Jun 25, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.
->The UGC NET Exam Analysis 2025 for June 25 is out for Shift 1.