यदि (a + b + c) = 16, और (a2 + b2 + c2) = 90 है, तो (ab + bc + ca) का मान ज्ञात कीजिए।

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SSC CGL 2023 Tier-I Official Paper (Held On: 14 Jul 2023 Shift 1)
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  1. 84
  2. 83
  3. 82
  4. 81

Answer (Detailed Solution Below)

Option 2 : 83
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दिया गया है

(a + b + c) = 16

(a2 + b2 + c2) = 90

प्रयुक्त सूत्र 

(a + b + c)2 = (a2 + b2 + c2) + 2(ab + bc + ca)

गणना

162 = 90 + 2(ab + bc + ca)

⇒ 256 - 90 = 2(ab + bc + ca)

⇒ 166 = 2(ab + bc + ca)

⇒ (ab + bc + ca) = 166/2

⇒ (ab + bc + ca) = 83

मान 83 है।

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