Question
Download Solution PDFयदि A + B = 90° और sin A = \(\frac{3}{5}\), तब tan B का मान __________ है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFA + B = 90°
SinA = 3/5
प्रयुक्त सूत्र:-
कर्ण2 = लंब2 + आधार2
Sinθ = लंब(P)/कर्ण(H)
tanθ = लंब/आधार(B)
tan(90° - A) = cotA
गणना:-
SinA = 3/5 = P/H
⇒ P = 3k और H = 5k [जहाँ k एक स्थिरांक है]
आधार = √(H2 - P2)
⇒ आधार = √(5k)2 - (3k)2
⇒ आधार = 4k
⇒ tanA = P/B
⇒ tanA = 3k/4k = 3/4
⇒ tan(90° - B) = 3/4
⇒ cotB = 3/4
⇒ tanB = 4/3
∴ अभीष्ट उत्तर tanB = 4/3 है।
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