Question
Download Solution PDFপ্রদত্ত একটি রম্বসের প্রতিটি বাহুর দৈর্ঘ্য 5 মিটার করে এবং তার একটি কর্ণের দৈর্ঘ্য 2.8 মিটার। তাহলে রম্বসটির ক্ষেত্রফল কত হবে?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFধরি, রম্বসটির অপর কর্ণের দৈর্ঘ্য 2x মিটার
আমরা জানি,
a2 = (d1/2)2 + (d2/2)2 [a =রম্বসের বাহু , d1 এবং d2 হ'ল কর্ণদ্বয়ের দৈর্ঘ্য]
⇒ (2.8/2)2 + (2x/2)2 = (5)2
⇒ 1.96 + x2 = 25
⇒ x2 = 23.04
⇒ x = 4.8 মিটার
অপর কর্ণের দৈর্ঘ্য = 4.8 × 2 = 9.6 মিটার
আর, রম্বসটির ক্ষেত্রফল হ'ল = ½ × কর্ণের গুণফল
∴ রম্বসটির ক্ষেত্রফল = 1/2 × 2.8 × 9.6 = 13.44 মিটার2Last updated on Jun 2, 2025
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