Train Crossing a Stationary Object or Man MCQ Quiz - Objective Question with Answer for Train Crossing a Stationary Object or Man - Download Free PDF
Last updated on May 27, 2025
Latest Train Crossing a Stationary Object or Man MCQ Objective Questions
Train Crossing a Stationary Object or Man Question 1:
The ratio of the speed of train A and train B is 1 : 2 respectively. Train B crosses a pole in 10 sec. Average of the length of train A and train B is 1500 meter. Ratio of the length of train A and train B is 2 : 1. Find the time taken by train A to cross a pole.
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 1 Detailed Solution
Calculation
Let length of train A and train B is 2x and x respectively.
So, [2x +x]/2 = 1500
Or, 3x = 3000
Or, x = 1000
So, Length of train A is 2000 and length of train B 1000.
Speed of train B is 1000/10 = 100 m/sec
Speed of train A is 100/2 = 50 m/sec
So, required time = [2000/50] = 40 sec
Train Crossing a Stationary Object or Man Question 2:
A train of length 800 m which travels at a speed of 126 kmph crosses a Tunnel in 61 seconds. Find the length of the Tunnel? (In metres)
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 2 Detailed Solution
Given:
Length of the train = 800 m
Speed of the train = 126 kmph
Time to cross the tunnel = 61 seconds
Formula Used:
Total Distance = Length of the train + Length of the tunnel
Speed = Distance / Time
Calculation:
Convert speed to m/s: Speed = 126 × (1000 / 3600)
⇒ Speed = 126 × (10 / 36)
⇒ Speed = 35 m/s
Distance covered in 61 seconds: Distance = Speed × Time
⇒ Distance = 35 × 61
⇒ Distance = 2135 m
Length of the tunnel = Distance - Length of the train
⇒ Length of the tunnel = 2135 - 800
⇒ Length of the tunnel = 1335 m
The length of the tunnel is 1335 m.
Train Crossing a Stationary Object or Man Question 3:
A train passes a platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km per hour, what is the length of the platform?
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 3 Detailed Solution
Given:
Speed of the train = 54 km/h
Time taken to pass the platform = 36 seconds
Time taken to pass a man = 20 seconds
Formula Used:
Length of the train = Speed × Time taken to pass a man
Length of the platform = Speed × Time taken to pass the platform - Length of the train
Calculation:
Speed in m/s = 54 × (1000 / 3600) = 15 m/s
Length of the train = 15 × 20 = 300 m
Length of the platform = 15 × 36 - 300
⇒ Length of the platform = 540 - 300
⇒ Length of the platform = 240 m
The correct answer is option 2.
Train Crossing a Stationary Object or Man Question 4:
The train is 130m long and traveling at 45 km/hr can cross in 30 sec. What is the length of the bridge?
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 4 Detailed Solution
Given:
Length of train = 130 m
Speed of train = 45 km/hr
Time to cross = 30 sec
Formula used:
Speed = Distance / Time
Distance = Length of train + Length of bridge
Calculation:
Convert speed to m/sec: 45 km/hr = 45 × (1000/3600) m/sec
⇒ 45 × (5/18) m/sec
⇒ 225/18 m/sec
⇒ 12.5 m/sec
Distance = Speed × Time
⇒ 12.5 × 30 m
⇒ 375 m
Distance = Length of train + Length of bridge
⇒ 375 = 130 + Length of bridge
⇒ Length of bridge = 375 - 130
⇒ Length of bridge = 245 m
∴ The length of the bridge is 245 m.
Train Crossing a Stationary Object or Man Question 5:
A man is standing on a railway bridge that is 120 m long. He finds that a train crosses the bridge in 10 sec but crosses him in 6 sec. Find the length of the train and its speed, respectively?
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 5 Detailed Solution
Given:
The length of the railway bridge = 120 m
Formula used:
Let the length of the train be L meters and speed of the train be S m/s
Speed (S) = Distance / Time
Calculation:
When train crosses the man, it covers its own length:
⇒ S = L / 6
When train crosses the bridge, it covers its own length plus the length of the bridge:
⇒ S = (L + 120) / 10
Equating both speed equations:
⇒ L / 6 = (L + 120) / 10
⇒ 10L = 6(L + 120)
⇒ 10L = 6L + 720
⇒ L = 180 m
Now, substitute L into S = L / 6:
⇒ S = 180 / 6 = 30 m/s
Convert speed into km/h:
⇒ Speed = 30 × 18 / 5 = 108 km/h
∴ The length of the train is 180 m and its speed is 108 km/h. The correct answer is option (3).
Top Train Crossing a Stationary Object or Man MCQ Objective Questions
A train having a length of 500 m passes through a tunnel of 1000 m in 1 minute. What is the speed of the train in Km/hr?
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 6 Detailed Solution
Download Solution PDFLet the speed of the train be x m/s.
Given length of the train = 500 m
Length of the tunnel = 1000 m
Time taken to pass the tunnel = 1 minute = 60 seconds
∴ x = (500 + 1000) ÷ 60
x = 25 m/s
Speed of the train in km/hr =\(\;25 \times \frac{{18}}{5}\frac{{km}}{{hr}}\)
Speed of the train = 90 km/hr.The ratio of speeds of two trains is 4 : 7. Both the trains can cross a pole in 12 seconds. Find the time in which the faster train will cross the slower one moving in same direction.
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 7 Detailed Solution
Download Solution PDF∵ The ratio of speeds of two trains is 4 : 7;
Suppose the speed of the trains are 4x & 7x respectively;
∵ Both the trains can cross a pole in 12 seconds;
∴ Length of 1st train = 4x × 12 = 48x
Length of 2nd train = 7x × 12 = 84x
∴ Time in which the faster train will cross the slower one moving in same direction = (48x + 84x)/(7x – 4x) = 44 secondTwo trains A and B are running in opposite directions with different speeds. The speed of train B is 18 km/h more than that of A. Train A crosses a pole in 32 seconds and its length is 210 m less than that of train B. If they cross each other in 34 seconds, the length of train A is ________.
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 8 Detailed Solution
Download Solution PDFGiven:
Speed of train B is 18km/h more than that of train A.
Length of train A is 210m less than that of train B.
Calculation:
Let D is the length of train A and the speed of train A be x m/s.
Then length of train B = D + 210
And the speed of train B is 18 km/h(18 × 5/18 = 5 m/s) more than the speed of train A.
Speed of train B = (x + 5) m/s
Train A crosses a pole in 32 seconds,
32 = D/x
⇒ x = D/32 ...... (i)
Both trains cross each other in 34 seconds
34 = (D + D + 210)/(x + x + 5) = (2D + 210)/(2x+5)
From (i),
⇒ 34 = (2D + 210)/(2 × D/32 +5)
⇒ 34 = (2D + 210)/(D/16 + 5)
⇒ 34 × (D/16 + 5) = 2D + 210
⇒ 34D + 16 × 170 = 32D + 16 × 210
⇒ 34D - 32D = 16 × 210 - 16 × 170
⇒ 2D = 16 × 40
⇒ D = 320 m.
A train crosses a 600 metres long platform in 50 seconds. It crosses another 900 metres long platform in 60 seconds. What is the length and speed of the train?
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 9 Detailed Solution
Download Solution PDFFormula Used:
Time taken = Distance/Speed
Calculation:
Let the length of the train be x
\(\Rightarrow {\rm{}}\frac{{600\; + \;x}}{{50}} = \frac{{900\; +\; x}}{{60}}\)
⇒ 3600 + 6x = 4500 + 5x
⇒ x = 900 metres
\(\Rightarrow {\rm{}}Speed = \frac{{600\; + \;900}}{{50}} = 30\;m/sec.\)
⇒ Speed = 30 × 18/5 = 108 km/h
∴ The length and speed of the train are 900 metres and 108 km/h.
Additional Information
1 km/hr = 5/18 m/sec
The distance between two stations, A and B, is 575 km, A train starts from station ‘A’ at 3.00 p.m and moves towards station ‘B’ at an average speed of 50 km/h. Another train starts from station ‘B’ at 3.30 p.m and moves towards station ‘A’ at an average speed of 60 km/h, how far from station ‘A’ will the trains meet?
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 10 Detailed Solution
Download Solution PDFThe distance between two stations, A and B = 575 km,
Speed of first train = 50 km/hr
Speed of second train = 60 km/hr
Distance covered by first train in 30 min (1/2 hr) = 50 × 1/2 = 25 km
Remaining distance = 575 - 25 = 550 km
Relative speed, if opposite direction = 50 + 60 = 110 km/hr
As we know,
Time = Distance/speed
Both train meet each other in = 550/110 = 5 hrs
Distance covered in 5 hrs by first train = 5 × 50 = 250 km
Total distance covered by first train = 25 + 250 = 275 km
Both trains meet each other 275 km far from station A.
A train having length 330 meters takes 11 second to cross a 550 meters long bridge. How much time will the train take to cross a 570 meters long bridge?
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 11 Detailed Solution
Download Solution PDFGiven
Length of train = 330 meters
The train crosses a 550 meters long bridge in 11 seconds
Formula used:
Time = Distance/Speed
Solution:
Speed of train = (330 + 550)/11 = 880/11
Time taken to cross the second bridge = (330 + 570)/880 × 11 = (45/4) seconds
Therefore, the train takes (45/4) the seconds to cross a 570 meters long bridge.
A train 120 m long passes a bridge in 18 seconds moving at a speed of 60 km/h. Find out the length of the bridge.
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 12 Detailed Solution
Download Solution PDFGiven:
Length of the train = 120 m
Speed of the train = 60 km/h
Time taken to cross the bridge = 18 seconds
Formula used:
Speed = Distance/Time
Solution:
Let the length of the bridge be x.
Speed = 60 km/h = 60 × 5/18 m/s
Time = 18 s
Distance = Speed × Time = 60 × 5/18 × 18 s = 300 m
300 m = 120 m + x
x = 300 m - 120 m
x = 180 m
Therefore, the length of the bridge is 180 m.
Trains A and B started from X and Y respectively at the same time towards each other. They crossed each other after 4 hours. A travels the distance XY in 10 hours. Find the time taken by B to travel XY.
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 13 Detailed Solution
Download Solution PDFFormula:
Let t be the time taken by A and B to cross each other
Let t1 and t2 be the times taken by A and B respectively to reach their destinations after crossing each other
Then, t2 = t1 × t2
Calculation:
Here, t = 4 hours
t1 = 10 hours
Time taken by train A after meeting =10 - 4 = 6 hours
⇒ 42 = 6 × t2
⇒ 16 = 6 × t2
⇒ t2 = 2.67
∴ Total time taken by B to travel XY = 4 + 2.7 = 6.67 hours
A 220 metre long train is running at a speed of 54 kilometre per hour. In what time will it pass a man who is moving in the opposite direction of the train at speed of 12 kilometre per hour?
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 14 Detailed Solution
Download Solution PDFConcept:
When two bodies run in the opposite direction, then their relative velocities get added.
1 km/hr = 5/18 m/s.
1 m/s = 18/5 km/hr.
Calculation:
Length of train = 220 m, Speed of train = 54 km/hr ⇒ 15 m/s and Speed of man = 12 km/hr ⇒ 10/3 m/s [ 1 km/hr = 5/18 m/s]
\(Time = \frac{Distance}{Speed}\)
⇒ \(\frac{220}{\frac{10}{3}\;+\;15} \) -----(Speed gets added due to different direction)
\(⇒ \frac{220\;\times\;3}{55}\)
⇒ 12 sec.
Two trains are running on parallel tracks in the same direction at the speed of 80 km/h and 90 km/h, respectively. The trains crossed each other in 3 minutes. If the length of one train is 230 m, then what is the length (in m) of the other train?
Answer (Detailed Solution Below)
Train Crossing a Stationary Object or Man Question 15 Detailed Solution
Download Solution PDFGiven:
Speed of the two trains is 80 km/h and 90 km/h
They cross each other in 3 minutes
Concept used:
Time = Distance/speed
Relative speed = When two bodies moving in the same direction then their relative speed of them will be different of the individual speed
Calculation:
3 min = 180 sec
The relative speed of the trains = 90 - 80
⇒ 10 km/h
Speed in m/sec = 10 × (5/18)
⇒ 25/9
Let the length of the other train be x m
Now,
[(230 + x)/(25/9)] = 180
⇒ (230 + x) = 180 × (25/9)
⇒ 230 + x = 500
⇒ x = 270
So, length of the other train = 270 m
∴ The length (in m) of the other train is 270.