Train Crossing a Stationary Object or Man MCQ Quiz - Objective Question with Answer for Train Crossing a Stationary Object or Man - Download Free PDF

Last updated on May 27, 2025

Train Problems is a vast, common and requisite section. It’s further divided into more sub-topics such as Train Crossing a Stationary Object or Man. Train Crossing a Stationary Object or Man MCQs Quiz are quite common in entrance and aptitude tests. Recruitments have allocated a fair number of weightage to Train Crossing a Stationary Object or Man objective questions. In this article, you will find some Train Crossing a Stationary Object or Man questions, its solutions, explanations and tricks.

Latest Train Crossing a Stationary Object or Man MCQ Objective Questions

Train Crossing a Stationary Object or Man Question 1:

The ratio of the speed of train A and train B is 1 : 2 respectively. Train B crosses a pole in 10 sec. Average of the length of train A and train B is 1500 meter. Ratio of the length of train A and train B is 2 : 1. Find the time taken by train A to cross a pole.

  1. 49 sec
  2. 43 sec
  3. 42 sec
  4. 50 sec
  5. 40 sec

Answer (Detailed Solution Below)

Option 5 : 40 sec

Train Crossing a Stationary Object or Man Question 1 Detailed Solution

Calculation

Let length of train A and train B is 2x and x respectively.

So, [2x +x]/2 = 1500

Or, 3x = 3000

Or, x = 1000

So, Length of train A is 2000 and length of train B 1000.

Speed of train B is 1000/10 = 100 m/sec

Speed of train A is 100/2 = 50 m/sec

So, required time = [2000/50] = 40 sec

Train Crossing a Stationary Object or Man Question 2:

 A train of length 800 m which travels at a speed of 126 kmph crosses a Tunnel in 61 seconds. Find the length of the Tunnel? (In metres)

  1. 1235
  2. 1435
  3. 1335
  4. 1535

Answer (Detailed Solution Below)

Option 3 : 1335

Train Crossing a Stationary Object or Man Question 2 Detailed Solution

Given:

Length of the train = 800 m

Speed of the train = 126 kmph

Time to cross the tunnel = 61 seconds

Formula Used:

Total Distance = Length of the train + Length of the tunnel

Speed = Distance / Time

Calculation:

Convert speed to m/s: Speed = 126 × (1000 / 3600)

⇒ Speed = 126 × (10 / 36)

⇒ Speed = 35 m/s

Distance covered in 61 seconds: Distance = Speed × Time

⇒ Distance = 35 × 61

⇒ Distance = 2135 m

Length of the tunnel = Distance - Length of the train

⇒ Length of the tunnel = 2135 - 800

⇒ Length of the tunnel = 1335 m

The length of the tunnel is 1335 m.

Train Crossing a Stationary Object or Man Question 3:

 A train passes a platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km per hour, what is the length of the platform?

  1. 120 m
  2. 240 m
  3. 300 m
  4. 360 m

Answer (Detailed Solution Below)

Option 2 : 240 m

Train Crossing a Stationary Object or Man Question 3 Detailed Solution

Given:

Speed of the train = 54 km/h

Time taken to pass the platform = 36 seconds

Time taken to pass a man = 20 seconds

Formula Used:

Length of the train = Speed × Time taken to pass a man

Length of the platform = Speed × Time taken to pass the platform - Length of the train

Calculation:

Speed in m/s = 54 × (1000 / 3600) = 15 m/s

Length of the train = 15 × 20 = 300 m

Length of the platform = 15 × 36 - 300

⇒ Length of the platform = 540 - 300

⇒ Length of the platform = 240 m

The correct answer is option 2.

Train Crossing a Stationary Object or Man Question 4:

The train is 130m long and traveling at 45 km/hr can cross in 30 sec. What is the length of the bridge?

  1. 245m
  2. 345m
  3. 225m
  4. 169m

Answer (Detailed Solution Below)

Option 1 : 245m

Train Crossing a Stationary Object or Man Question 4 Detailed Solution

Given:

Length of train = 130 m

Speed of train = 45 km/hr

Time to cross = 30 sec

Formula used:

Speed = Distance / Time

Distance = Length of train + Length of bridge

Calculation:

Convert speed to m/sec: 45 km/hr = 45 × (1000/3600) m/sec

⇒ 45 × (5/18) m/sec

⇒ 225/18 m/sec

⇒ 12.5 m/sec

Distance = Speed × Time

⇒ 12.5 × 30 m

⇒ 375 m

Distance = Length of train + Length of bridge

⇒ 375 = 130 + Length of bridge

⇒ Length of bridge = 375 - 130

⇒ Length of bridge = 245 m

∴ The length of the bridge is 245 m.

Train Crossing a Stationary Object or Man Question 5:

A man is standing on a railway bridge that is 120 m long. He finds that a train crosses the bridge in 10 sec but crosses him in 6 sec. Find the length of the train and its speed, respectively?

  1. 119 m and 107 kmph
  2. 180 m and 107 kmph
  3. 180 m and 108 kmph
  4. 119 m and 108 kmph 

Answer (Detailed Solution Below)

Option 3 : 180 m and 108 kmph

Train Crossing a Stationary Object or Man Question 5 Detailed Solution

Given:

The length of the railway bridge = 120 m

Formula used:

Let the length of the train be L meters and speed of the train be S m/s

Speed (S) = Distance / Time

Calculation:

When train crosses the man, it covers its own length:

⇒ S = L / 6

When train crosses the bridge, it covers its own length plus the length of the bridge:

⇒ S = (L + 120) / 10

Equating both speed equations:

⇒ L / 6 = (L + 120) / 10

⇒ 10L = 6(L + 120)

⇒ 10L = 6L + 720

⇒ L = 180 m

Now, substitute L into S = L / 6:

⇒ S = 180 / 6 = 30 m/s

Convert speed into km/h:

⇒ Speed = 30 × 18 / 5 = 108 km/h

∴ The length of the train is 180 m and its speed is 108 km/h. The correct answer is option (3).

Top Train Crossing a Stationary Object or Man MCQ Objective Questions

A train having a length of 500 m passes through a tunnel of 1000 m in 1 minute. What is the speed of the train in Km/hr?

  1. 75 Km/hr
  2. 90 Km/hr
  3. 87 Km/hr
  4. 96 Km/hr

Answer (Detailed Solution Below)

Option 2 : 90 Km/hr

Train Crossing a Stationary Object or Man Question 6 Detailed Solution

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Let the speed of the train be x m/s.

Given length of the train = 500 m

Length of the tunnel = 1000 m

Time taken to pass the tunnel = 1 minute = 60 seconds

∴ x = (500 + 1000) ÷ 60

x = 25 m/s

Speed of the train in km/hr =\(\;25 \times \frac{{18}}{5}\frac{{km}}{{hr}}\)

Speed of the train = 90 km/hr.

The ratio of speeds of two trains is 4 : 7. Both the trains can cross a pole in 12 seconds. Find the time in which the faster train will cross the slower one moving in same direction.

  1. 54 seconds
  2. 42 seconds
  3. 45 seconds
  4. 44 seconds
  5. 36 seconds

Answer (Detailed Solution Below)

Option 4 : 44 seconds

Train Crossing a Stationary Object or Man Question 7 Detailed Solution

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∵ The ratio of speeds of two trains is 4 : 7;

Suppose the speed of the trains are 4x & 7x respectively;

∵ Both the trains can cross a pole in 12 seconds;

∴ Length of 1st train = 4x × 12 = 48x

Length of 2nd train = 7x × 12 = 84x

∴ Time in which the faster train will cross the slower one moving in same direction = (48x + 84x)/(7x – 4x) = 44 second

Two trains A and B are running in opposite directions with different speeds. The speed of train B is 18 km/h more than that of A. Train A crosses a pole in 32 seconds and its length is 210 m less than that of train B. If they cross each other in 34 seconds, the length of train A is ________.

  1. 420 m
  2. 400 m
  3. 380 m
  4. 320 m

Answer (Detailed Solution Below)

Option 4 : 320 m

Train Crossing a Stationary Object or Man Question 8 Detailed Solution

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Given:

Speed of train B is 18km/h more than that of train A.

Length of train A is 210m less than that of train B.

Calculation:

Let D is the length of train A and the speed of train A be x m/s.

Then length of train B = D + 210

And the speed of train B is 18 km/h(18 × 5/18 = 5 m/s) more than the speed of train A.

Speed of train B = (x + 5) m/s

Train A crosses a pole in 32 seconds,

32 = D/x

⇒ x = D/32  ...... (i)

Both trains cross each other in 34 seconds

34 = (D + D + 210)/(x + x + 5) = (2D + 210)/(2x+5)

From (i),

⇒ 34 = (2D + 210)/(2 × D/32 +5)

⇒ 34 = (2D + 210)/(D/16 + 5)

⇒ 34 × (D/16 + 5) = 2D + 210

⇒ 34D + 16 × 170 = 32D +  16 × 210

⇒ 34D - 32D = 16 × 210 - 16 × 170

⇒ 2D = 16 × 40

D = 320 m. 

A train crosses a 600 metres long platform in 50 seconds. It crosses another 900 metres long platform in 60 seconds. What is the length and speed of the train?

  1. 900 metres, 108 km/h
  2. 900 metres, 96 km/h
  3. 600 metres, 108 km/h
  4. 700 metres, 96 km/h

Answer (Detailed Solution Below)

Option 1 : 900 metres, 108 km/h

Train Crossing a Stationary Object or Man Question 9 Detailed Solution

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Formula Used:

Time taken = Distance/Speed

Calculation:

Let the length of the train be x

\(\Rightarrow {\rm{}}\frac{{600\; + \;x}}{{50}} = \frac{{900\; +\; x}}{{60}}\)

⇒ 3600 + 6x = 4500 + 5x

⇒ x = 900 metres

\(\Rightarrow {\rm{}}Speed = \frac{{600\; + \;900}}{{50}} = 30\;m/sec.\)

⇒ Speed = 30 × 18/5 = 108 km/h

∴ The length and speed of the train are 900 metres and 108 km/h.

Additional Information

1 km/hr = 5/18 m/sec 

The distance between two stations, A and B, is 575 km, A train starts from station ‘A’ at 3.00 p.m and moves towards station ‘B’ at an average speed of 50 km/h. Another train starts from station ‘B’ at 3.30 p.m and moves towards station ‘A’ at an average speed of 60 km/h, how far from station ‘A’ will the trains meet?

  1. 325 km
  2. 300 km
  3. 275 km
  4. 225 km

Answer (Detailed Solution Below)

Option 3 : 275 km

Train Crossing a Stationary Object or Man Question 10 Detailed Solution

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The distance between two stations, A and B = 575 km,

Speed of first train = 50 km/hr

Speed of second train = 60 km/hr

Distance covered by first train in 30 min (1/2 hr) = 50 × 1/2 = 25 km

Remaining distance = 575 - 25 = 550 km

Relative speed, if opposite direction = 50 + 60 = 110 km/hr

As we know,

Time = Distance/speed

Both train meet each other in = 550/110 = 5 hrs

Distance covered in 5 hrs by first train = 5 × 50 = 250 km

Total distance covered by first train = 25 + 250 = 275 km

Both trains meet each other 275 km far from station A.

A train having length 330 meters takes 11 second to cross a 550 meters long bridge. How much time will the train take to cross a 570 meters long bridge?

  1. (45/4) seconds
  2. (47/4) seconds
  3. 20 seconds
  4. 16 seconds

Answer (Detailed Solution Below)

Option 1 : (45/4) seconds

Train Crossing a Stationary Object or Man Question 11 Detailed Solution

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Given

Length of train = 330 meters

The train crosses a 550 meters long bridge in 11 seconds

Formula used:

Time = Distance/Speed

Solution:

Speed of train = (330 + 550)/11 = 880/11

Time taken to cross the second bridge = (330 + 570)/880 × 11 = (45/4) seconds

Therefore, the train takes (45/4) the seconds to cross a 570 meters long bridge.

A train 120 m long passes a bridge in 18 seconds moving at a speed of 60 km/h. Find out the length of the bridge.

  1. 150 m
  2. 160 m
  3. 170 m
  4. 180 m

Answer (Detailed Solution Below)

Option 4 : 180 m

Train Crossing a Stationary Object or Man Question 12 Detailed Solution

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Given:

Length of the train = 120 m

Speed of the train = 60 km/h

Time taken to cross the bridge = 18 seconds

Formula used:

Speed = Distance/Time

Solution:

Let the length of the bridge be x.

Speed = 60 km/h = 60 × 5/18 m/s

Time = 18 s

Distance = Speed ×  Time = 60 × 5/18 × 18 s = 300 m

300 m = 120 m + x

x = 300 m - 120 m

x = 180 m

Therefore, the length of the bridge is 180 m.

Trains A and B started from X and Y respectively at the same time towards each other. They crossed each other after 4 hours. A travels the distance XY in 10 hours. Find the time taken by B to travel XY.

  1. 6.4 hours
  2. 4.8 hours
  3. 7.2 hours
  4. 6.67 hours
  5. 4.5 hours

Answer (Detailed Solution Below)

Option 4 : 6.67 hours

Train Crossing a Stationary Object or Man Question 13 Detailed Solution

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Formula:

Let t be the time taken by A and B to cross each other

Let t1 and t2 be the times taken by A and B respectively to reach their destinations after crossing each other

 Then, t2 = t1 × t2

Calculation:

Here, t = 4 hours

t1 = 10 hours

Time taken by train A after meeting =10 - 4 = 6 hours

⇒ 42 = 6 × t2

⇒ 16 = 6 × t2

⇒ t2 = 2.67

∴ Total time taken by B to travel XY = 4 + 2.7 = 6.67 hours

A 220 metre long train is running at a speed of 54 kilometre per hour. In what time will it pass a man who is moving in the opposite direction of the train at speed of 12 kilometre per hour?

  1. 6 sec
  2. 10 sec
  3. 8 sec
  4. 12 sec

Answer (Detailed Solution Below)

Option 4 : 12 sec

Train Crossing a Stationary Object or Man Question 14 Detailed Solution

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Concept:

When two bodies run in the opposite direction, then their relative velocities get added.

1 km/hr = 5/18 m/s.

1 m/s = 18/5 km/hr.

Calculation:

Length of train = 220 m, Speed of train = 54 km/hr ⇒ 15 m/s and Speed of man = 12 km/hr ⇒ 10/3 m/s [ 1 km/hr = 5/18 m/s]

\(Time = \frac{Distance}{Speed}\)

⇒ \(\frac{220}{\frac{10}{3}\;+\;15} \)   -----(Speed gets added due to different direction)

\(⇒ \frac{220\;\times\;3}{55}\)

⇒ 12 sec.

Two trains are running on parallel tracks in the same direction at the speed of 80 km/h and 90 km/h, respectively. The trains crossed each other in 3 minutes. If the length of one train is 230 m, then what is the length (in m) of the other train?

  1. 250
  2. 270
  3. 300
  4. 230

Answer (Detailed Solution Below)

Option 2 : 270

Train Crossing a Stationary Object or Man Question 15 Detailed Solution

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Given:

Speed of the two trains is 80 km/h and 90 km/h

They cross each other in 3 minutes

Concept used:

Time = Distance/speed

Relative speed = When two bodies moving in the same direction then their relative speed of them will be different of the individual speed

Calculation:

3 min = 180 sec

The relative speed of the trains = 90 - 80

⇒ 10 km/h

Speed in m/sec = 10 × (5/18)

⇒ 25/9

Let the length of the other train be x m

Now,

[(230 + x)/(25/9)] = 180

⇒ (230 + x) = 180 × (25/9)

⇒ 230 + x = 500

⇒ x = 270

So, length of the other train = 270 m

∴ The length (in m) of the other train is 270.

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