Pie Chart MCQ Quiz - Objective Question with Answer for Pie Chart - Download Free PDF

Calculation:

P(Admitted) = 8550 × 0.22 = 1881

P(Passed) = 5700 × 0.18 = 1026

Q(Admitted) = 8550 × 0.15 = 1282.5

Q(Passed) = 5700 × 0.17 = 969

R(Admitted) = 8550 × 0.10 = 855

R(Passed) = 5700 × 0.13 = 741

S(Admitted) = 8550 × 0.17 = 1453.5

S(Passed) = 5700 × 0.16 = 912

T(Admitted) = 8550 × 0.08 = 684

T(Passed) = 5700 × 0.09 = 513

V(Admitted) = 8550 × 0.12 = 1026

V(Passed) = 5700 × 0.15 = 855

X(Admitted) = 8550 × 0.16 = 1368

X(Passed) = 5700 × 0.12 = 684

Passing % from P = \(\dfrac{1026}{1881}\) × 100 = 54.54%

Passing % from Q = \(\dfrac{969}{1282.5}\) × 100 = 75.55%

Passing % from R = \(\dfrac{741}{855}\) × 100 = 86.67%

Passing % from S = \(\dfrac{912}{1453.5}\) × 100 = 62.74%

Passing % from T = \(\dfrac{513}{684}\) × 100 = 75%

Passing % from V = \(\dfrac{855}{1026}\) × 100 = 83.33%

Passing % from X = \(\dfrac{684}{1368}\) × 100 = 50%

∴ Highest percentage is from R.

Given:

T(Admitted) = 8550 × 8% = 684

T(Passed) = 5700 × 9% = 513

Calculation:

Passing % from T = \(\dfrac{513}{684}\) × 100 = 75%

∴ The percentage of candidates passed the examination from institute T out of the total No. of candidates admitted from the same institute is 75%.

Given:

S(Passed) = 5700 × 0.16 = 912

P(Passed) = 5700 × 0.18 = 1026

T(Admitted) = 8550 × 0.08 = 684

R(Admitted) = 8550 × 0.10 = 855

Calculation:

Total Passed from S and P = 912 + 1026 = 1938

Total Admitted in T and R = 684 + 855 = 1539

Required difference = 1938 - 1539 = 399

∴ The number of candidates passed from institute S and P together exceeds the number of candidates admitted from institute T and R together by 399.

Calculation: 

P(Admitted) = 8550 × 0.22 = 1881

P(Passed) = 5700 × 0.18 = 1026

Required Ratio = 1026 : 1881 = 6 : 11

∴ The ratio of candidates passed to the candidates admitted from institute P is 6 : 11.

Calculation:

Q(Admitted) = 8550 × 0.15 = 1282.5

Q(Passed) = 5700 × 0.17 = 969

R(Admitted) = 8550 × 0.10 = 855

R(Passed) = 5700 × 0.13 = 741

Total Passed = 969 + 741 = 1710

Total Admitted = 1282.5 + 855 = 2137.5

Required Percentage = \(\dfrac{1710}{2137.5} \) × 100 = 80%

∴ The percentage of candidates passed to the candidates admitted for institutes Q and R taken together is 80%.

Calculation:

Total fund got by school = 100% = 1000000

Funds got through donation = 35%

Scholarship paid = 26% 

Required percentage = 26/35 × 100

⇒ 2600/35 = 74.285% ≈ 74.29%

∴ The correct answer is 74.29%.

Calculation:

Let the Cost price of the book be 100

Then, Marked Price of the book is 100 + (15% of 100) = 115

Printed price or marked price = 942

Cost price of book = 942 × (100/115)

⇒ 819.13

Now,

Paper cost = 819.13 × 15/100

⇒ 122.869 ≈ 122.9

∴ The required answer is Rs. 122.9

Given:

Total faculties in school F = 1820

Calculation:

It's given that the total number of faculties (Male and Female) in school F is 1820 

Female faculties = Total faculties - Male faculties 

But according to the chart male percentage in school F = 18%

Total faculties in school F = 1820

Total male faculties in school F = 8400 × 18/100 = 1512

Female faculties in school F = 1820 - 1512 = 308

Male faculties in school B = 8400 × 20/100 = 1680

∴ Required percentage = (1680 - 308)/1680 × 100

⇒ 1372/1680 × 100 = 81.66%.

∴ Female faculties in school F are 81.66% less than male faculties in school B.

Calculation:

Percentage of Kerala in total production = \(\frac {200}{220 + 240 + 180 + 160 + 200} \times 100 \) = 20%

We know that 100% of the pie chart represents 360°.

Now, the 20% pie chart represents = \(\frac {360 \times 20}{100}\) = 72°

∴ The central angle corresponding to the production of steel by Kerala is 72°.

Given:

The performance of 1800 students in grades has been shown in the following pie chart.

Calculation:

Total percentage of grades B and E = 27% + 8% = 35%

Here, (54/1800) × 100 = 3%

Then, 54 students of 1800 is 3% students

We have to find the sum of two groups in which the sum of percentage = 35% - 3% = 32%

The percentage of students in Grade C = 24%

The percentage of students in Grade E = 8%

The total percentage of Grade C and E = 24% + 8% = 32%

∴ The number of students is 54 less than the number of students in grades B and E taken together in Grade C and E

Calculation:

Total percentage of trucks sold in B, C, F and H = 27 + 18 + 7 + 14

⇒ 66%

Difference = 100% - 66%

⇒ 34%

∴ The required answer is 34 percent.

Concept used:

The sum of variables/No. of variables = Average of variables

Calculation

The number of girls in the colleges C = 20% of 2500

⇒ 500

The number of girls in the colleges E = 26% of 2500

⇒ 650

The average number of girls in colleges C and E = (500 + 650)/2

⇒ 575

The average number of girls in colleges C and E is 575.

Given data:

Total startups in Education = 1280

Successful startup in Education = 520

Total startups in Health and sports = 1050

Successful startup in Health and sports = 300

Calculation:

Successful startup % in education = \(520\over 1280\) × 100 = 40.625%

Requisite successful startups in Health and sports = \(40.625\over 100\) × 1050 = 427 (approximately)

Total increase in the successful startups required for health and sports = 427 - 300 = 127

∴ The answer is 127.

Total expenditure of all sports = 16 + 128 + 72 + 23 + 51 + 10 = 300 crores

Expenditure on football = 51 crores

300 crores represents = 360°

1 crore represents = 360/300°

Calculation:

Total % of D1 and D4 = 12 + 14

⇒ 26%

Total % of D2 and D7 = 11 + 11

⇒ 22%

Difference = 26% - 22%

⇒ 4%

Difference in amount = 4962000 × 4%

⇒ 198480

∴ The required answer is Rs. 1,98,480.