Caselet DI MCQ Quiz - Objective Question with Answer for Caselet DI - Download Free PDF
Last updated on Jul 7, 2025
Latest Caselet DI MCQ Objective Questions
Caselet DI Question 1:
Comprehension:
Directions: Study the information carefully and answer the questions.
Rajat and Suman jointly acquired a 6-acre fruit orchard in the ratio of 4:2 in the year 2020 and began cultivating apples in the year 2021. In that year, Rajat, being the primary investor, gave 60 kg of apples, which was 10% of his total production for that year, to Suman. As a result, Suman's total apple quantity increased by 30%. In the year 2022, Suman's total apple production was 50% more than the previous year, so he returned 20% of his total apples produced quantity to Rajat. After receiving from Suman, Rajat's total apple quantity increased by 15%. In the year 2023, both had produced an equal quantity of apples, and Rajat's production of apples was increased by 20% over the total quantity of apples he had produced in the previous year.
In which year was the percentage difference between Rajat's and Suman's apple production the greatest?
Answer (Detailed Solution Below)
Caselet DI Question 1 Detailed Solution
General Solution:
Orchard Area Division
Total land = 6 acres
Rajat : Suman = 4 : 2 ⇒ 2 : 1
Apple Production in 2021:
Let Rajat's production = R₁ kg
He gave 60 kg to Suman, which was 10% of his production
⇒ 10% of R₁ = 60 ⇒ R₁ = 600 kg
Suman got 60 kg which increased his total by 30%
⇒ 60 = 30% of S₁ ⇒ S₁ = 200 kg
2021: Rajat = 600 kg, Suman = 200 kg
2022 Production:
Suman's 2022 production = 50% more than 2021 = 200 + 50% of 200 = 300 kg
He gives 20% of 300 = 60 kg to Rajat
Let Rajat's 2022 own production = R₂
Total apples with Rajat = R₂ + 60 = 15% more than R₂
⇒ R₂ + 60 = R₂ + 15% of R₂ = R₂ × 1.15
⇒ R₂ + 60 = 1.15R₂ ⇒ 60 = 0.15R₂ ⇒ R₂ = 400 kg
2022: Rajat = 400 kg, Suman = 300 kg
2023 Production:
Both produced equal quantities
Rajat's 2023 production is 20% more than previous year = 400 + 20% of 400 = 480 kg
⇒ So, Suman’s 2023 production = 480 kg
2023: Rajat = 480 kg, Suman = 480 kg
Thus:
| Year | Rajat (kg) | Suman (kg) |
|---|---|---|
| 2021 | 600 | 200 |
| 2022 | 400 | 300 |
| 2023 | 480 | 480 |
Calculations:
Calculate percentage difference = |R - S| ÷ ((R + S)/2) × 100
2021: |600 - 200| ÷ 400 × 100 = 400 ÷ 400 × 100 = 100%
2022: |400 - 300| ÷ 350 × 100 ≈ 28.57%
2023: |480 - 480| ÷ 480 × 100 = 0%
Thus, the correct answer is 2021.
Short trick:
The highest difference is in 2021, i.e, 400.
Caselet DI Question 2:
Comprehension:
Directions: Study the information carefully and answer the questions.
Rajat and Suman jointly acquired a 6-acre fruit orchard in the ratio of 4:2 in the year 2020 and began cultivating apples in the year 2021. In that year, Rajat, being the primary investor, gave 60 kg of apples, which was 10% of his total production for that year, to Suman. As a result, Suman's total apple quantity increased by 30%. In the year 2022, Suman's total apple production was 50% more than the previous year, so he returned 20% of his total apples produced quantity to Rajat. After receiving from Suman, Rajat's total apple quantity increased by 15%. In the year 2023, both had produced an equal quantity of apples, and Rajat's production of apples was increased by 20% over the total quantity of apples he had produced in the previous year.
If the apple price is ₹50 per kg in 2021 and increases by 10% each subsequent year, what is the total revenue earned by Suman over the 3 years (assume that Suman sold his apples after the transactions)?
Answer (Detailed Solution Below)
Caselet DI Question 2 Detailed Solution
General Solution:
Orchard Area Division
Total land = 6 acres
Rajat : Suman = 4 : 2 ⇒ 2 : 1
Apple Production in 2021:
Let Rajat's production = R₁ kg
He gave 60 kg to Suman, which was 10% of his production
⇒ 10% of R₁ = 60 ⇒ R₁ = 600 kg
Suman got 60 kg which increased his total by 30%
⇒ 60 = 30% of S₁ ⇒ S₁ = 200 kg
2021: Rajat = 600 kg, Suman = 200 kg
2022 Production:
Suman's 2022 production = 50% more than 2021 = 200 + 50% of 200 = 300 kg
He gives 20% of 300 = 60 kg to Rajat
Let Rajat's 2022 own production = R₂
Total apples with Rajat = R₂ + 60 = 15% more than R₂
⇒ R₂ + 60 = R₂ + 15% of R₂ = R₂ × 1.15
⇒ R₂ + 60 = 1.15R₂ ⇒ 60 = 0.15R₂ ⇒ R₂ = 400 kg
2022: Rajat = 400 kg, Suman = 300 kg
2023 Production:
Both produced equal quantities
Rajat's 2023 production is 20% more than previous year = 400 + 20% of 400 = 480 kg
⇒ So, Suman’s 2023 production = 480 kg
2023: Rajat = 480 kg, Suman = 480 kg
Thus:
| Year | Rajat (kg) | Suman (kg) |
|---|---|---|
| 2021 | 600 | 200 |
| 2022 | 400 | 300 |
| 2023 | 480 | 480 |
Calculations:
Apple prices per year:
2021: ₹50 per kg
2022: ₹50 + 10% = ₹55 per kg
2023: ₹55 + 10% = ₹60.5 per kg
Suman's final apple quantity each year
2021: He had 200 kg + 60 kg from Rajat = 260 kg
2022: Produced 300 kg – gave 60 kg to Rajat = 240 kg
2023: Produced = 480 kg
Calculate Revenue for each year:
2021: 260 kg × ₹50 = ₹13,000
2022: 240 kg × ₹55 = ₹13,200
2023: 480 kg × ₹60.5 = ₹29,040
Total Revenue = 13,000 + 13,200 + 29,040 = ₹55,240
Thus, the correct answer is ₹55,240.
Caselet DI Question 3:
Comprehension:
Directions: Study the information carefully and answer the questions.
Rajat and Suman jointly acquired a 6-acre fruit orchard in the ratio of 4:2 in the year 2020 and began cultivating apples in the year 2021. In that year, Rajat, being the primary investor, gave 60 kg of apples, which was 10% of his total production for that year, to Suman. As a result, Suman's total apple quantity increased by 30%. In the year 2022, Suman's total apple production was 50% more than the previous year, so he returned 20% of his total apples produced quantity to Rajat. After receiving from Suman, Rajat's total apple quantity increased by 15%. In the year 2023, both had produced an equal quantity of apples, and Rajat's production of apples was increased by 20% over the total quantity of apples he had produced in the previous year.
What was the ratio of Rajat's total apples (own production + received) to Suman's total apples (after giving) in 2022?
Answer (Detailed Solution Below)
Caselet DI Question 3 Detailed Solution
General Solution:
Orchard Area Division
Total land = 6 acres
Rajat : Suman = 4 : 2 ⇒ 2 : 1
Apple Production in 2021:
Let Rajat's production = R₁ kg
He gave 60 kg to Suman, which was 10% of his production
⇒ 10% of R₁ = 60 ⇒ R₁ = 600 kg
Suman got 60 kg which increased his total by 30%
⇒ 60 = 30% of S₁ ⇒ S₁ = 200 kg
2021: Rajat = 600 kg, Suman = 200 kg
2022 Production:
Suman's 2022 production = 50% more than 2021 = 200 + 50% of 200 = 300 kg
He gives 20% of 300 = 60 kg to Rajat
Let Rajat's 2022 own production = R₂
Total apples with Rajat = R₂ + 60 = 15% more than R₂
⇒ R₂ + 60 = R₂ + 15% of R₂ = R₂ × 1.15
⇒ R₂ + 60 = 1.15R₂ ⇒ 60 = 0.15R₂ ⇒ R₂ = 400 kg
2022: Rajat = 400 kg, Suman = 300 kg
2023 Production:
Both produced equal quantities
Rajat's 2023 production is 20% more than previous year = 400 + 20% of 400 = 480 kg
⇒ So, Suman’s 2023 production = 480 kg
2023: Rajat = 480 kg, Suman = 480 kg
Thus:
| Year | Rajat (kg) | Suman (kg) |
|---|---|---|
| 2021 | 600 | 200 |
| 2022 | 400 | 300 |
| 2023 | 480 | 480 |
Calculations:
2022 Apple Quantities:
Rajat's own production in 2022 = 400 kg
He received 60 kg from Suman
Total apples with Rajat = 400 + 60 = 460 kg
Suman's production = 300 kg
He gave 20% of 300 = 60 kg to Rajat
Total apples left with Suman = 300 − 60 = 240 kg
Required Ratio:
⇒ Rajat : Suman = 460 : 240 ⇒ 23 : 12
Thus, the correct answer is 23 : 12.
Caselet DI Question 4:
Comprehension:
Directions: Study the information carefully and answer the questions.
Rajat and Suman jointly acquired a 6-acre fruit orchard in the ratio of 4:2 in the year 2020 and began cultivating apples in the year 2021. In that year, Rajat, being the primary investor, gave 60 kg of apples, which was 10% of his total production for that year, to Suman. As a result, Suman's total apple quantity increased by 30%. In the year 2022, Suman's total apple production was 50% more than the previous year, so he returned 20% of his total apples produced quantity to Rajat. After receiving from Suman, Rajat's total apple quantity increased by 15%. In the year 2023, both had produced an equal quantity of apples, and Rajat's production of apples was increased by 20% over the total quantity of apples he had produced in the previous year.
If in 2024, both Rajat and Suman decide to increase their production by the average annual percentage increase from 2021 to 2023, what would be the approximate total production in 2024?
Answer (Detailed Solution Below)
Caselet DI Question 4 Detailed Solution
General Solution:
Orchard Area Division
Total land = 6 acres
Rajat : Suman = 4 : 2 ⇒ 2 : 1
Apple Production in 2021:
Let Rajat's production = R₁ kg
He gave 60 kg to Suman, which was 10% of his production
⇒ 10% of R₁ = 60 ⇒ R₁ = 600 kg
Suman got 60 kg which increased his total by 30%
⇒ 60 = 30% of S₁ ⇒ S₁ = 200 kg
2021: Rajat = 600 kg, Suman = 200 kg
2022 Production:
Suman's 2022 production = 50% more than 2021 = 200 + 50% of 200 = 300 kg
He gives 20% of 300 = 60 kg to Rajat
Let Rajat's 2022 own production = R₂
Total apples with Rajat = R₂ + 60 = 15% more than R₂
⇒ R₂ + 60 = R₂ + 15% of R₂ = R₂ × 1.15
⇒ R₂ + 60 = 1.15R₂ ⇒ 60 = 0.15R₂ ⇒ R₂ = 400 kg
2022: Rajat = 400 kg, Suman = 300 kg
2023 Production:
Both produced equal quantities
Rajat's 2023 production is 20% more than previous year = 400 + 20% of 400 = 480 kg
⇒ So, Suman’s 2023 production = 480 kg
2023: Rajat = 480 kg, Suman = 480 kg
Thus:
| Year | Rajat (kg) | Suman (kg) |
|---|---|---|
| 2021 | 600 | 200 |
| 2022 | 400 | 300 |
| 2023 | 480 | 480 |
Calculations:
2021 total = 600 (Rajat) + 200 (Suman) = 800 kg
2023 total = 480 + 480 = 960 kg
Change over 2 years = 960 − 800 = 160 kg
Average annual % increase = [(Final − Initial)/Initial] ÷ 2 × 100
⇒ (960 − 800)/800 × 100 = 20% over 2 years ⇒ Annual average = 10%
2024 projection = 960 × (1 + 10/100) = 960 × 1.10 = 1056 kg
∴ Approximate total production in 2024 = 1056 kg
Caselet DI Question 5:
Comprehension:
Directions: Study the information carefully and answer the questions.
Rajat and Suman jointly acquired a 6-acre fruit orchard in the ratio of 4:2 in the year 2020 and began cultivating apples in the year 2021. In that year, Rajat, being the primary investor, gave 60 kg of apples, which was 10% of his total production for that year, to Suman. As a result, Suman's total apple quantity increased by 30%. In the year 2022, Suman's total apple production was 50% more than the previous year, so he returned 20% of his total apples produced quantity to Rajat. After receiving from Suman, Rajat's total apple quantity increased by 15%. In the year 2023, both had produced an equal quantity of apples, and Rajat's production of apples was increased by 20% over the total quantity of apples he had produced in the previous year.
What is the percentage change in the total apples produced by both Rajat and Suman combined in 2022 as compared to 2021?
Answer (Detailed Solution Below)
Caselet DI Question 5 Detailed Solution
General Solution:
Orchard Area Division
Total land = 6 acres
Rajat : Suman = 4 : 2 ⇒ 2 : 1
Apple Production in 2021:
Let Rajat's production = R₁ kg
He gave 60 kg to Suman, which was 10% of his production
⇒ 10% of R₁ = 60 ⇒ R₁ = 600 kg
Suman got 60 kg which increased his total by 30%
⇒ 60 = 30% of S₁ ⇒ S₁ = 200 kg
2021: Rajat = 600 kg, Suman = 200 kg
2022 Production:
Suman's 2022 production = 50% more than 2021 = 200 + 50% of 200 = 300 kg
He gives 20% of 300 = 60 kg to Rajat
Let Rajat's 2022 own production = R₂
Total apples with Rajat = R₂ + 60 = 15% more than R₂
⇒ R₂ + 60 = R₂ + 15% of R₂ = R₂ × 1.15
⇒ R₂ + 60 = 1.15R₂ ⇒ 60 = 0.15R₂ ⇒ R₂ = 400 kg
2022: Rajat = 400 kg, Suman = 300 kg
2023 Production:
Both produced equal quantities
Rajat's 2023 production is 20% more than previous year = 400 + 20% of 400 = 480 kg
⇒ So, Suman’s 2023 production = 480 kg
2023: Rajat = 480 kg, Suman = 480 kg
Thus:
| Year | Rajat (kg) | Suman (kg) |
|---|---|---|
| 2021 | 600 | 200 |
| 2022 | 400 | 300 |
| 2023 | 480 | 480 |
Calculations:
2021 total = 600 (Rajat) + 200 (Suman) = 800
2022 total = 400 (Rajat) + 300 (Suman) = 700
Change = (700 - 800) ÷ 800 × 100 = -12.5%
Thus, the correct answer is 12.5%.
Top Caselet DI MCQ Objective Questions
Comprehension:
Directions: Read the given information carefully and answer the following questions.
A and B invested in a business in the ratio 4 : 5. A invested for 4 months more than B. At the end of year, the total profit earned is Rs. 35000 out of which B earned Rs. 15000.
What is the ratio of the time period of investment of A and B?
Answer (Detailed Solution Below)
Caselet DI Question 6 Detailed Solution
Download Solution PDFGiven:
Investment ratio of A and B = 4:5.
Time invested by A = 4 months more than B.
Total profit = Rs. 35000.
Profit earned by B = Rs. 15000.
Formula Used:
Profit share ratio = (Investment × Time) ratio.
Calculation:
Let investment of A = 4x, and B = 5x.
Let time invested by B = t months, then A invested for t + 4 months.
Profit ratio = Profit of A : Profit of B.
From total profit, Profit of A = Rs. 35000 - Rs. 15000 = Rs. 20000.
Profit ratio = 20000 : 15000 = 4 : 3.
Setting up equation from profit ratio:
⇒ (4x × (t + 4)) / (5x × t) = 4 / 3
Removing x as it cancels out:
⇒ (4 × (t + 4)) / (5 × t) = 4 / 3
Cross multiply to solve for t:
⇒ 12 × (t + 4) = 20 × t
⇒ 12t + 48 = 20t
⇒ 8t = 48
⇒ t = 6
Time invested by B = 6 months, and A = 6 + 4 = 10 months.
Time ratio of A to B = 10 months : 6 months = 5 : 3.
The ratio of the time period of investment of A and B is 5:3.
Comprehension:
Directions: Read the given information carefully and answer the following questions.
A and B invested in a business in the ratio 4 : 5. A invested for 4 months more than B. At the end of year, the total profit earned is Rs. 35000 out of which B earned Rs. 15000.
What is the amount invested by A in the business?
Answer (Detailed Solution Below)
Caselet DI Question 7 Detailed Solution
Download Solution PDFLet the amount invested by A and B be 4x and 5x respectively
Let B invested by ‘t’ months
Time of investment of A = t + 4
Profit ratio = 4x × (t + 4) : 5x × t = (4t + 16) : 5t
Now, B’s share:
5t/(4t + 16 + 5t) × 35000 = 15000
35t = 27t + 48
8t = 48
t = 6 months
Period of investment: A = 10 months, B = 6 months
Amount invested by A = 4x
We cannot determine the value of ‘x’
∴ Amount invested by A cannot be determined.
Here many might mistake 'by the end of year' as one year and solve the question and get it wrong. Note that it is not written 'by the end of one year', since no numerical value of time is given, and with only the ratio given we can not reach a valid conclusion.
200 students appeared in a specific examination. There were 80 students who failed in Mathematics. 160 students passed in Physics. 30 students failed in Chemistry. 30 students failed in Mathematics and Physics. 15 students failed in Mathematics and Chemistry. 10 students failed in Physics and Chemistry. 100 students passed in all three subjects.
How many students failed in only one subject?
Answer (Detailed Solution Below)
Caselet DI Question 8 Detailed Solution
Download Solution PDFConcept used:
n(A U B U C) = n(A) + n (B) + n(c) - n(A ∩ B) - n(B ∩ C) - n(C ∩ A) + n(A ∩ B ∩ C)
Where, n(A U B U C) = no of students failed in all subject
n(A ∩ B ∩ C) = number of total students failed
Calculation:
Total students pass = 100
So, total students fail = 200 - 100 = 100
Students failed in Physics = 200 - 160 = 40
Now,
100 = 80 + 40 + 30 - (15 + 30 + 10) + students failed in all subjects
⇒ students failed in all subjects = 100 - 150 + 55
⇒ students failed in all subjects = 155 - 150 = 5
Again,
Failed in only (M, P) = 30 - 5 = 25
Failed in only (P, C) = 10 - 5 = 5
Failed in only (C, M) = 15 - 5 = 10
So,
Failed in only maths = 80 - (10 + 5 + 25) = 80 - 40 = 40
Failed in only physics = 40 - (25 + 5 + 5) = 40 - 35 = 5
Failed in only chemistry = 30 - (10 + 5 + 5) = 30 - 20 = 10
Thus, total students failed in only one subject = 40 + 5 + 10 = 55
∴ The correct answer is option (2).
Comprehension:
Directions: Consider the following information and answer the questions based on it
In a group of 75 students, 12 like only cabbage, 15 like only cauliflower, 21 like only carrot, 12 like both carrot and cabbage, 13 like only capsicum and 2 like both capsicum and cauliflower.
The difference between the people who like carrot and cauliflower is
A. 6
B. 18
C. 16
D. 4Answer (Detailed Solution Below)
Caselet DI Question 9 Detailed Solution
Download Solution PDFTotal number of people who like carrot = 21 + 12 = 33
Total number of people who like cauliflower = 15 + 2 = 17
∴ Required difference = 33 – 17 = 16
Comprehension:
Directions: Read the given information carefully and answer the following questions.
Three streams Arts, Science, and Commerce are offered in 3 colleges A, B, and C.
(1) There are 1750 students in college A. The number of Commerce students in college A is 400 more than that of in Science in college A. the ratio of the number of students in college A in Arts and Science is 23 : 2.
(2) There are 3250 students in Arts in all colleges. The number of students in Science in all colleges is 37.5% less than that of in Commerce in all colleges.
(3) The number of Arts students in college C is 10% more than that of in college B. the ratio of the number of students in Science in college B to that of in college C is 3 : 4.
(4) The number of students in Commerce in college B is 30% less than that in college A. total number of students in college B is 280 less than that of in college C.
The total number of students in college B is what percent more/less than that of in Science in all colleges?
Answer (Detailed Solution Below)
Caselet DI Question 10 Detailed Solution
Download Solution PDFLet the number of students in Arts and Science in college A be 23x and 2x respectively.
⇒ Number of students in Commerce in college A = 400 + 2x
23x + 2x + 400 + 2x = 1750
27x = 1350
x = 50
College A: Arts = 1150, Science = 100, Commerce = 500
Let the number of Commerce students in all colleges be 8y
⇒ Number of Science students in all colleges = 62.5/100 × 8y = 5y
Number of students in Commerce in college B = 70/100 × 500 = 350
⇒ Number of students in Commerce in college C = 8y – (500 + 350)
⇒ 8y – 850
Let the number of students in Arts in college B be z
⇒ Number of students in Arts in college C = 110/100 × z = 1.1z
1150 + z + 1.1z = 3250
2.1z = 2100
z = 1000
Number of students in Science in college B = 3/7 × (5y – 100) = 15y/7 – 300/7
Number of students in Science in college C = 4/7 × (5y – 100) = 20y/7 – 400/7
Now, Total number of students in college B = 1000 + 350 + 15y/7 – 300/7
⇒ 1350 – 300/7 + 15y/7
Total number of students in college C = 1100 + 20y/7 – 400/7 + 8y – 850
⇒ 250 – 400/7 + 20y/7 + 8y
Now, 250 – 400/7 + 20y/7 + 8y – 280 = 1350 – 300/7 + 15y/7
⇒ 1380 + 100/7 = 61y/7
⇒ y = 160
Now, putting the value of y and z, we get
|
College |
Number of students in Arts |
Number of students in Science |
Number of students in Commerce |
|
A |
1150 |
100 |
500 |
|
B |
1000 |
300 |
350 |
|
C |
1100 |
400 |
430 |
Total students in college B = 1000 + 300 + 350 = 1650
Total students in Science in all colleges = 100 + 300 + 400 = 800
∴ Required percent = (1650 – 800)/800 × 100 = 106.25%
Comprehension:
Directions: Read the following information carefully and answer the given questions:-
In school, the total number of students is 14,000. On the annual function of the school, 25% of the total boys and 60% of total girls have participated and the number of total girls in the school is equal to the number of boys who have not participated in the function.
Find the number of boys who have participated in annual function of the school.
Answer (Detailed Solution Below)
Caselet DI Question 11 Detailed Solution
Download Solution PDFTotal number of students = 14,000
Percentage of boys who participated in annual function = 25%
Percentage of girls who participated in annual function = 60%
Number of girls in school = Number of boys who have not participated in function
Concept used:
Total number of boys or girls = Number of those who participated + Number of those who have not participated
Calculation:
Let the number of boys and girls be x and y respectively
Number of boys who have participated in annual function = 25% of x
⇒ 0.25x
Number of boys who have not participated = (x – 0.25x)
⇒ 0.75x
Number of girls in school = y = 0.75x
Now, as per the question
⇒ x + y = 14,000
⇒ x + 0.75x = 14,000
⇒ 1.75x = 14,000
⇒ x = 8000
Number of boys who have participated in annual function = 0.25x
⇒ 0.25 × 8000
⇒ 2000
∴ The number of boys who have participated in annual function is 2000
District XYZ has 50,000 voters; out of them, 20% are urban voters and 80% rural voters. For an election, 25% of the rural voters were shifted to the urban area. Out of the voters in both rural and urban areas, 60% are honest, 70% are hardworking, and 35% are both honest and hardworking.
Two candidates, A and B, contested the election. Candidate B swept the urban vote, while Candidate A found favour with the rural voters. Voters who were both honest and hardworking voted for NOTA. How many votes were polled in favour of candidate A, candidate B and NOTA, respectively?
Answer (Detailed Solution Below)
Caselet DI Question 12 Detailed Solution
Download Solution PDFGiven:
District XYZ has 50,000 voters; out of them, 20% are urban voters and 80% rural voters.
Calculation:
Total votes = 50000
⇒ Urban votes originally = 20/100 × 50000 = 10000 and Rural votes originally = 80/100 × 50000 = 40000
For election, 25% of the rural voters were shifted to the urban area
⇒ 25/100 × 40000 = 10000 rural votes shifted to urban area.
⇒ Now, Urban votes = 10000 + 10000 = 20000 and Rural votes = 40000 - 10000 = 30000
Out of the voters in both rural and urban areas, 60% are honest, 70% are hardworking, and 35% are both honest and hardworking.
Voters who were both honest and hardworking voted for NOTA.
∴ Votes swept by NOTA = 35% of urban + 35% of rural = 35/100 × 20000 + 35/100 × 30000 = 17500
Candidate A found favour with the rural voters, rural voters left = 100% - 35% = 65% of rural voters
∴ Votes swept by A = 65/100 × 30000 = 19500
Candidate B found favour with the urban voters, Urban voters left = 100% - 35% = 65% of urban voters
∴ Votes swept by B = 65/100 × 20000 = 13000
⇒ Votes polled in favor of candidate A, candidate B and NOTA are 19500, 13000 and 17500 respectively
Comprehension:
Direction: Read the information carefully and answer the following questions:
In a school of 750 students, each student likes atleast one of the three colors- Red, Green and Blue. 109 students like only red color, 150 students like only green color and 125 students like only blue color. The number of students who like red and green colors only is 70% of the students who like only green color. The number of students who like red and blue colors only is 60% of the students who like only blue color. 100 students like all the colors.
Find the number of students who like green and blue colours only.
Answer (Detailed Solution Below)
Caselet DI Question 13 Detailed Solution
Download Solution PDFGiven:
Total number of students = 750
The number of students who like red and green colours only = 70% of 150 students
and The number of students who like red and blue colours only = 60% of 125 students
Calculation:
Let the number of students who like green and blue colours only be a.
Number of students who like red and green colours only = (70/100) × 150
⇒ 105 students
Number of students who like red and blue colours only = (60/100) × 125
⇒ 75 students
Now, The total number of students = 750
⇒ 109 + 150 + 125 + 100 + 105 + 75 + a = 750
⇒ 664 + a = 750
⇒ a = 750 – 664
⇒ a = 86 students
∴ 86 students like both green and blue colors only.
A survey of 170 families, 115 drink Coffee, 110 drink Tea and 130 drink Milk. Also, 85 drink Coffee and Milk, 75 drink Coffee and Tea, 95 drink Tea and Milk, 70 drink all the three. Find How many use Coffee and Milk but not Tea.
Answer (Detailed Solution Below)
Caselet DI Question 14 Detailed Solution
Download Solution PDFGiven,
Number of families who participate in survey = 170
Number of families who drink Coffee = 115
Number of families who drink Tea = 110
Number of families who drink Milk = 130
Number of families who drink Coffee and Milk = 85
Number of families who drink Coffee and Tea = 75
Number of families who drink Tea and Milk = 95
Number of families who drink Coffee, Milk and Tea = 70
Calculation:
Number of families who drink only Milk and Tea = 95 – 70 = 25
Number of families who drink only Coffee and Milk = 85 – 70 = 15Comprehension:
Direction: Read the following data carefully and answer the following questions:
There are two villages A and B in a certain district. The population of village A is 35% less than the population of village B. Total population of both villages is 8250. The ratio between adults and children in two villages is 20: 13. The difference between the number of adults and children including two villages is 1750. In village A, the number of adults is 60% more than the number of children. While in village B, the number of adults is 1.5 times the number of children.
Find the difference between the number of adults in village B and the number of children village B.
Answer (Detailed Solution Below)
Caselet DI Question 15 Detailed Solution
Download Solution PDFLet the population of village A and Village B be A and B respectively.
⇒ A + B = 8250
⇒ 65B/100 + B = 8250
⇒ B = 5000
⇒ A = 3250
Let adults of village A and Village B be P and Q respectively while children of village A and Village B be S and T respectively.
⇒ P + S = 3250
⇒ 160S/100 + S = 3250
S = 1250 = children of village A
P = 2000 = adults of village A
⇒ Q + T = 5000
⇒ 1.5T + T = 5000
T = 2000 = children of village B
Q = 3000 = adults of village B
Required difference = 3000 – 2000 = 1000