Dimensional and Model Analysis MCQ Quiz - Objective Question with Answer for Dimensional and Model Analysis - Download Free PDF
Last updated on Jun 20, 2025
Latest Dimensional and Model Analysis MCQ Objective Questions
Dimensional and Model Analysis Question 1:
A hydraulic model of a spillway is constructed with a scale \(1:16.\) If the prototype discharge is 2048 cumec, then the corresponding discharge for which the model should be tested is
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 1 Detailed Solution
Concept:
When working with a hydraulic model of a spillway:
- For flow modeling, based on Froude similarity (since free surface flow is governed by gravity):\(\frac{Q_{model}}{Q_{prototype}}=L_r^{\frac{5}{2}}\)
- where, Lr = linear scale ratio
Calculation:
Given: Prototype discharge = 2048m3/s
Linear scale ratio = 1:16
\(\frac{Q_{model}}{Q_{prototype}}=\frac{1}{16}^{\frac{5}{2}}\)
\(Q_{model}=2048\times\frac{1}{16}^{\frac{5}{2}}\)
\(Q_{model}=2cumec\)
Dimensional and Model Analysis Question 2:
For complete similarity to exist between the model and its prototype, there should be
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 2 Detailed Solution
Explanation:
Similarity Between Model and Prototype
- For a model to accurately represent its prototype in engineering analysis, certain similarities must exist between the two. These similarities ensure that the results obtained from studying the model can be extrapolated to predict the behavior or performance of the prototype. The three key types of similarity are geometric, kinematic, and dynamic similarity.
Types of Similarity:
- Geometric Similarity: This refers to the model and the prototype having the same shape and proportional dimensions. All corresponding lengths in the model and prototype should maintain a consistent scale factor. For example, if the prototype is scaled down by a factor of 10, every dimension (length, width, height) of the model should be 1/10th of the corresponding dimension in the prototype.
- Kinematic Similarity: This ensures that the motion of the model and the prototype are similar. The velocities, accelerations, and flow patterns at corresponding points in the model and prototype must maintain a consistent ratio. Kinematic similarity is essential in fluid mechanics and dynamics where motion plays a critical role.
- Dynamic Similarity: This involves the forces acting on the model and the prototype being in proportion. The ratios of corresponding forces, such as inertial forces, viscous forces, pressure forces, and gravitational forces, must be the same. This similarity ensures that the dynamic response of the model accurately predicts the behavior of the prototype.
Importance of All Three Types of Similarity:
- For complete similarity between the model and its prototype, all three types of similarity—geometric, kinematic, and dynamic—must exist simultaneously. This ensures that the model behaves in the same manner as the prototype under similar conditions, allowing engineers to make reliable predictions about the prototype's performance based on model analysis.
Dimensional and Model Analysis Question 3:
What will be the approximate velocity (in m/s) of a bullet fired in standard air (Temperature of air = 300K) if the Mach angle is 30°? [R = 0.287 kJ/kg-K, ]
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 3 Detailed Solution
Concept:
The Mach angle \( \mu \) is related to Mach number \( M \) as:
\( \sin \mu = \frac{1}{M} \Rightarrow M = \frac{1}{\sin 30^\circ} = 2 \)
Speed of sound:
\( a = \sqrt{\gamma R T} = \sqrt{1.4 \cdot 287 \cdot 300} \approx 347.15~\text{m/s} \)
Velocity of bullet:
\( V = M \cdot a = 2 \cdot 347.15 \approx 694.3~\text{m/s} \approx 280\sqrt{6} \)
Dimensional and Model Analysis Question 4:
For Froude model law, the scale ratio of force and scale ratio of length are related as: [Assuming the experiment is conducted on the same place and in the same fluid]
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 4 Detailed Solution
Explanation:
Froude Model Law
Definition: Froude Model Law is a similarity law used in fluid mechanics for the study and comparison of fluid flow phenomena in models and prototypes. It is primarily applied in cases involving gravitational forces, such as free surface flows, ship modeling, and open channel flows. The law states that the ratio of inertial forces to gravitational forces must be consistent between the model and the prototype to ensure dynamic similarity.
Working Principle: Froude Model Law is based on the principle that the Froude number (Fr), which is the ratio of inertial forces to gravitational forces, must remain the same for both the model and the prototype. The Froude number is given by:
Froude Number \(F_r = \frac{V}{\sqrt{gL}}\)
Where:
- v: Velocity of fluid
- g: Acceleration due to gravity
- L: Characteristic length
Dynamic similarity is achieved when the Froude number for the model and the prototype are equal:
\(\frac{V_m}{\sqrt {L_m g_m}} = \frac{V_p}{\sqrt{L_p g_p}}\)
From this, the relationships between various physical quantities such as velocity, time, force, and power can be derived.
Scale ratio of force = (Scale ratio of length)3
To understand why this is correct, let us analyze the relationship between force and length under Froude Model Law:
Force Relationship:
The force acting in a fluid flow is typically determined by the inertial forces and gravitational forces. According to Froude Model Law, the force scale ratio between the model and the prototype can be derived as follows:
- The inertial force is proportional to mass × acceleration.
- Mass is proportional to the volume, which scales with the cube of the length (l3).
- Acceleration, under Froude similarity, is proportional to g (gravitational acceleration), which does not change.
Therefore, the scale ratio of force (F) is proportional to the scale ratio of length (l) cubed:
Scale Ratio of Force = (Scale Ratio of Length)3
Dimensional and Model Analysis Question 5:
Hydraulic ram is a device
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 5 Detailed Solution
Explanation:
Hydraulic Ram
A hydraulic ram is a device that is used to lift water without the use of an electric motor. It operates using the energy of a large amount of water falling a small height to lift a small amount of water to a greater height. This makes it suitable for applications in remote areas where electricity is not available.
Analyzing the Given Options
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1) For lifting water without an electric motor (Correct)
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A hydraulic ram uses water's kinetic energy to lift a portion of the water to a higher elevation without requiring electricity.
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This makes option 1 the correct answer.
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2) For accelerating water flow (Incorrect)
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A hydraulic ram does not accelerate water flow. Instead, it uses the flow of water to operate its mechanism.
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Hence, option 2 is incorrect.
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3) For lifting heavy loads (Incorrect)
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A hydraulic ram is specifically used for lifting water, not heavy loads.
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Its design and operation are not suitable for lifting heavy objects, making option 3 incorrect.
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4) None of the above (Incorrect)
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Since option 1 is correct, option 4 cannot be correct.
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Therefore, option 4 is incorrect.
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Correct Answer: Option 1
Top Dimensional and Model Analysis MCQ Objective Questions
Froude number is the ratio of
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 6 Detailed Solution
Download Solution PDFConcept:
Froude number is the ratio of inertial force to the gravitation force.
\(\text{Froude }\!\!~\!\!\text{ number}=\text{ }\!\!~\!\!\text{ }\sqrt{\frac{\text{Inertia force }\!\!~\!\!\text{ }}{\text{Gravitational force }\!\!~\!\!\text{ }}}\)
Froude number has the following applications:
- Used in cases of river flows, open-channel flows, spillways, surface wave motion created by boats
- It can be used for flow classification
Important Points
\(\text{Reynold's number}=\frac{\text{Inertia force}}{\text{Viscous force}}\)
\(\text{Euler }\!\!~\!\!\text{ number}=\sqrt{\frac{\text{Inertia force}}{\text{Pressure force}}}\)
\(\text{Weber }\!\!~\!\!\text{ number}=\sqrt{\frac{\text{Inertia force}}{\text{Surface Tension force}}}\)
\(\text{Mach }\!\!~\!\!\text{ number}=\sqrt{\frac{\text{Inertia force}}{\text{Compressibility force}}}\)
A turbine develops 400 kW power under a head of 81 metres at 225 rpm. What will be the speed of the turbine under a head of 64 metres?
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 7 Detailed Solution
Download Solution PDFConcept:
Unit speed i.e. speed of the turbine under the unit head,
\({{\rm{N}}_{\rm{a}}} = \frac{{\rm{N}}}{{\sqrt {\rm{H}} }}\)
Given: P = 400 kW, H1 = 81 m, N1 = 225 rpm, and H2 = 64 m
To Calculate: N2 = ?
Calculation:
\(\frac{{{{\rm{N}}_1}}}{{\sqrt {{{\rm{H}}_1}} }} = \frac{{{{\rm{N}}_2}}}{{\sqrt {{{\rm{H}}_2}} }} \Rightarrow \frac{{225}}{{\sqrt {81} }} = \frac{{{{\rm{N}}_2}}}{{\sqrt {64} }}\)
\(\Rightarrow {{\rm{N}}_2} = 200 \ rpm\)
The ratio of the square root of inertia force to surface tension force is known as:
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 8 Detailed Solution
Download Solution PDFExplanation:
Weber number
The Weber number is the ratio of dynamic pressure (i.e. inertia force) to the surface tension force.
\({W_e} = \sqrt {\frac{{inertia\;force}}{{surface\;tension}}} = \frac{V}{{\sqrt {\sigma /\rho L} }}\)
Additional Information
Other important dimensionless numbers are described in the table below"
Reynold’s number |
\(R_e=\frac{{{inertia force}}}{{{viscous force}}} = \frac{{{\bf{\rho VL}}\;}}{{\bf{\mu }}}\) |
Froude Number |
\({F_r} = \sqrt {\frac{{inertia\;force}}{{gravitation\;force}}} = \frac{V}{{\sqrt {{\bf{Lg}}} }}\) |
Euler number |
\({E_u} = \sqrt {\frac{{inertia\;force}}{{pressure\;force}}} = \frac{V}{{\sqrt {P/\rho } }}\) |
Mach Number |
\({M} = \sqrt {\frac{{inertia\;force}}{{Elastic\;force}}} = \frac{V}{{\sqrt {K/\rho } }}=~\frac VC \) |
A dimensionless group formed with the variables ρ (density), ω (angular velocity), μ (dynamic viscosity) and D (characteristic diameter) is
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 9 Detailed Solution
Download Solution PDFExplanation:
Dimensions:
Density (ρ) = [ML-3]
Angular velocity (ω) = [T-1]
Dynamic viscosity (μ) = [ML-1T-1]
Characterstic diameter (D) = [L]
By Buckingham π - method:
π = [ρa, ωb, Dc] μ
Where,
π = dimensionless number
π = [ML-3]a [T-1]b [L]c [ML-1T-1]
Equating the dimention of both side;
a = -1
b = -1
c = -2
μ/ρωD2 is the dimensionless term.
A phenomenon is modeled using n dimensional variables with k primary dimensions. The number of non-dimensional variables is
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 10 Detailed Solution
Download Solution PDFExplanation:
Buckingham's Pi Theorem:
Assume, a physical phenomenon is described by n number of independent variables like x1, x2, x3, ..., xn
The phenomenon may be expressed analytically by an implicit functional relationship of the controlling variables as:
f(x1, x2, x3, ……………, xn) = 0
Now if k be the number of fundamental/primary dimensions like mass, length, time, temperature etc., involved in these n variables, then according to Buckingham's Pi theorem -
The phenomenon can be described in terms of (n - m) independent dimensionless/non-dimensional groups like π1, π2, ..., πn-m, where p terms, represent the dimensionless parameters and consist of different combinations of a number of dimensional variables out of the n independent variables defining the problem.Which of the following physical quantity is dimensionless?
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 11 Detailed Solution
Download Solution PDFCONCEPT:
- Dimensions: When a derived quantity is expressed in terms of fundamental quantities, it is written as a product of different powers of the fundamental quantities.
- The powers to which fundamental quantities must be raised in order to express the given physical quantity are called its dimensions.
- A quantity without dimension will usually be a ratio of two quantities with similar dimensions and hence, will cancel out. Thus, they will have no units and known as dimensionless quantity.
- Angle: It is defined as the ratio of the length of arc to the radius, i.e.,
\(Angle\;\left( \theta \right) = \frac{{length\;of\;arc\;\left( l \right)}}{{radius\;\left( r \right)}}\)
\( \Rightarrow \theta = \frac{{\left[ {{M^0}L{T^0}} \right]}}{{\left[ {{M^0}L{T^0}} \right]}} = 1\)
∴ An angle is a dimensionless quantity
- Strain: It is defined as the ratio of change in length to the original length. i.e.,
\(Strain = \frac{{change\;in\;length\;\left( {{\rm{\Delta }}l} \right)}}{{original\;length\;\left( l \right)}}\)
\( \Rightarrow Strain = \frac{{\left[ {{M^0}L{T^0}} \right]}}{{\left[ {{M^0}L{T^0}} \right]}} = 1\)
∴ Strain is a dimensionless quantity
- Specific gravity: It is the ratio of the density of a substance to the density of a given reference material i.e.,
\(Specific\;gravity\;\left( \rho \right) = \frac{{Density\;of\;the\;object\;\left( {{\rho _{object}}} \right)}}{{Density\;of\;water\;\left( {{\rho _{water}}} \right)}}\)
\( \Rightarrow Specific\;gravity = \frac{{\left[ {M{L^3}{T^0}} \right]}}{{\left[ {M{L^3}{T^0}} \right]}} = 1\)
∴ Specific gravity is a dimensionless quantity
EXPLANATION:
As from the above discussion, we can say that:
- An angle is the ratio of the length of arc to the radius. As both have the dimension of length so the angle is a dimensionless quantity. So option 1 follows.
- Strain: It is defined as the ratio of change in length to the original length. As both have the dimension of length so the strain is a dimensionless quantity. So option 2 follows.
- Specific gravity: It is the ratio of the density of a substance to the density of given reference material. As both have the dimension of density so the specific gravity is a dimensionless quantity. So option 3 follows.
As the given three options are correct.
So the correct option is 4.
Froude's number is defined as the ratio of
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 12 Detailed Solution
Download Solution PDFConcept:
Froude number is the ratio of inertial force to the gravitation force.
\(\text{Froude }\!\!~\!\!\text{ number}=\text{ }\!\!~\!\!\text{ }\sqrt{\frac{\text{Inertia force }\!\!~\!\!\text{ }}{\text{Gravitational force }\!\!~\!\!\text{ }}}\)
Froude number has the following applications:
- Used in cases of river flows, open-channel flows, spillways, surface wave motion created by boats
- It can be used for flow classification
Important Points
\(\text{Reynold's number}=\frac{\text{Inertia force}}{\text{Viscous force}}\)
\(\text{Euler }\!\!~\!\!\text{ number}=\sqrt{\frac{\text{Inertia force}}{\text{Pressure force}}}\)
\(\text{Weber }\!\!~\!\!\text{ number}=\sqrt{\frac{\text{Inertia force}}{\text{Surface Tension force}}}\)
\(\text{Mach }\!\!~\!\!\text{ number}=\sqrt{\frac{\text{Inertia force}}{\text{Compressibility force}}}\)
When Froude’s number is more than 1, then the flow is termed as
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 13 Detailed Solution
Download Solution PDFExplanation:
Critical flow
It is defined as the flow at which specific energy is minimum or the flow corresponding to critical depth is defined as critical flow.
Relation of critical velocity with critical depth is:
\({V_c} = \sqrt {g \times {h_c}} \)
\(\frac{{{V_c}}}{{\sqrt {g \times {h_c}} }} = Froude\;number = 1\)
Froude number is 1 for critical flow.
Tranquil flow or streaming flow or sub-critical flow
- When the depth of a flow in a channel is greater than critical depth (hc), the flow is said to be sub-critical flow.
- Froude number is less than 1 for sub-critical flow.
Torrential flow or shooting flow or super-critical flow
- When the depth of a flow in a channel is less than critical depth (hc), the flow is said to be a super-critical flow.
- Froude number is greater than 1 for super-critical flow.
Consider the following statements and identify the correct answer.
Statement A: The Froude's number is used to compare the wave making resistance between bodies of various sizes and shapes.
Statement B: The Froude's number is defined as the square root of the ratio of the inertia force of a flowing fluid to the gravity force.
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 14 Detailed Solution
Download Solution PDFExplanation:
Froude Number:
- It is the ratio of the square root of inertia force and gravity force.
- The Froude number is used to compare the wave-making resistance between bodies of various sizes and shapes. In free-surface flow, the nature of the flow (supercritical or subcritical) depends upon whether the Froude number is greater than or less than unity.
\({{\rm{F}}_{\rm{r}}} = \sqrt {\frac{{{\rm{Inertia\;force}}}}{{{\rm{Gravity\;force}}}}} = {\rm{\;}}\frac{{\rm{v}}}{{\sqrt {{\rm{gL}}} }}\)
Use in open channel design i.e free surface flows
Important PointsMach Number,
\({\rm{M}} = \sqrt {\frac{{{\rm{Inertia\;force}}}}{{{\rm{Compressibility}}}}} = \frac{{\rm{V}}}{{\sqrt {\frac{{\rm{K}}}{{\rm{\rho }}}} }}\)
Use in the compressible flow
Weber Number,
\({\rm{W}} = \frac{{{\rm{Inertia\;force}}}}{{\rm{\sigma }}} = \frac{{{\rm{\rho VL}}}}{{\rm{\sigma }}}\)
Use in capillary action & surface tension
Reynold Number,
\({{\rm{R}}_{\rm{e}}} = \frac{{{\rm{Inertia\;force}}}}{{\rm{\mu }}} = \frac{{{\rm{\rho VD}}}}{{\rm{\mu }}}\)
Use in determine the flow type i.e Laminar or turbulent
Euler Number,
\({\rm{E}} = \sqrt {\frac{{{\rm{Inertia\;force}}}}{{{\rm{Pressure}}}}} = \sqrt {\frac{{\rm{V}}}{{\frac{{{\rm{\Delta P}}}}{{\rm{\rho }}}}}} \)
The performance of a hydraulic structure during a flood has been investigated in a 1 / 36 model based on Froude law of similarity. A flood wave passing through the model in 3 hours corresponds to the prototype period of
Answer (Detailed Solution Below)
Dimensional and Model Analysis Question 15 Detailed Solution
Download Solution PDFConcept:
Froude model law:
The gravity force is the only predominant force in addition to the inertia force, which control the motion
(Fr)model = (Fr)prototype
Or,
\(\frac{{{V_m}}}{{\sqrt {{g_m}{L_m}} }} = \frac{{{V_p}}}{{\sqrt {{g_p}{L_p}} }}\)
\(\frac{{{V_r}}}{{\sqrt {{g_r}{L_r}} }} = 1\)
\({V_r} = \sqrt {{g_r}{L_r}}\)
Since, in most of the cases gr = 1, then
Vr = √Lr ………(i)
∵ velocity = distance/time
So, Vr = Lr/Tr
Tr = Lr/Vr = Lr/√Lr = √Lr
Or
\(\frac{{{T_m}}}{{{T_p}}} = \sqrt {\frac{{{L_m}}}{{{L_p}}}}\)
Calculation:
Given,
Lr = 1/36, Tm = 3 hour
∵ We know that, Tr = √Lr
\(\frac{3}{{{T_p}}} = \sqrt {\frac{1}{{36}}}\)
⇒ Tp = 18 hour