Fluid Kinematics MCQ Quiz - Objective Question with Answer for Fluid Kinematics - Download Free PDF
Last updated on Jul 8, 2025
Latest Fluid Kinematics MCQ Objective Questions
Fluid Kinematics Question 1:
An open cubical tank of 2 m side is filled with water. If the tank is rotated with an acceleration such that half of the water spills out, then the acceleration is equal to
Answer (Detailed Solution Below)
Fluid Kinematics Question 1 Detailed Solution
Concept:
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The tank is cubical, side = L
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It is rotated about a vertical axis.
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The water surface tilts because of centrifugal force.
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When half the water spills out, the tilt height h = L. The water will go from depth 2 m at one side to zero at the other.
The tilt height for a rotating open tank: \(h=\frac{a.L}g\)
Where: = height difference (tilt); = side of tank
= centrifugal acceleration at edge; g = gravity = 9.81 m/s²
Calculation:
L = 2 m
Condition for half spillage:
For half water spillage → the surface tilts from 0 m to 2 m:
So, h = L = 2 m
\(2=\frac{a.2}{g}\)
\(a=g\)
For an open cubical tank rotating so that half water spills out → required centrifugal acceleration = g.
Fluid Kinematics Question 2:
Which of the following is NOT a type of flow line?
Answer (Detailed Solution Below)
Fluid Kinematics Question 2 Detailed Solution
Explanation:
In fluid mechanics, flow lines refer to visual representations of the motion of fluid particles. The three primary types of flow lines are:
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Pathline – The trajectory that a single fluid particle follows over time.
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Streakline – A line formed by all fluid particles that have passed through a particular point.
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Streamline – A line tangent to the velocity vector of the flow at every point.
Energy line:
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Refers to a line representing the total head (energy per unit weight) in the flow field.
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It is related to Bernoulli’s equation and is used in hydraulic grade line studies.
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It is not a type of flow line showing the motion or position of fluid particles.
Fluid Kinematics Question 3:
Dimension of circulation is
Answer (Detailed Solution Below)
Fluid Kinematics Question 3 Detailed Solution
Explanation:
Circulation
- Circulation is a concept in fluid dynamics that measures the total "rotational effect" of a fluid flow around a closed contour or loop. It is mathematically defined as the line integral of the velocity vector along a closed curve. The dimension of circulation can be derived from its physical definition and mathematical representation.
Circulation is defined as the line integral of velocity over a closed loop:
\( \Gamma = \oint \vec{V} \cdot d\vec{l} \)
Where:
- \( \vec{V} \) = velocity (dimension = \( \frac{L}{T} \))
- \( d\vec{l} \) = length element (dimension = \( L \))
Therefore,
\( \text{Dimension of } \Gamma = \frac{L}{T} \times L = \frac{L^2}{T} \)
Fluid Kinematics Question 4:
A vessel with square cross–section and height of 6 m is vertically partitioned. A small window of 100 cm2 with hinged door is fitted at a depth of 3 m in the partition wall. One part of the vessel is filled completely with water and the other side is filled with the liquid having density 1.5 × 103 kg/m3. What force one needs to apply on the hinged door so that it does not get opened ?
(Acceleration due to gravity = 10 m/s2)
Answer (Detailed Solution Below) 150
Fluid Kinematics Question 4 Detailed Solution
Calculation:
Calculate forces:
⇒ Fℓ = (P0 + ρℓ g h) A
⇒ Fw = (P0 + ρw g h) A
So,
⇒ Fext = Fℓ - Fw
⇒ Fext = [ (P0 + ρℓ g h) - (P0 + ρw g h) ] A
⇒ Fext = (ρℓ - ρw) g h A
⇒ Fext = (1500 - 1000) × 10 × 3 × (100 × 10-4)
⇒ Fext = 150 N
∴ The external force required is 150 N.
Fluid Kinematics Question 5:
In a flow, velocity vector is given by \(\vec{V} = -y^2\hat{i} - 6x\hat{j}\) . The equation of streamline passing through the point (1,1) will be:
Answer (Detailed Solution Below)
Fluid Kinematics Question 5 Detailed Solution
Concept:
For a 2D flow, the equation of a streamline is given by:
\( \frac{dx}{u} = \frac{dy}{v} \)
Given:
\( u = -y^2, \quad v = -6x \)
So,
\( \frac{dx}{-y^2} = \frac{dy}{-6x} \Rightarrow \frac{dx}{y^2} = \frac{dy}{6x} \)
Cross-multiplying:
\( 6x \, dx = y^2 \, dy \)
Integrating both sides:
\( \int 6x \, dx = \int y^2 \, dy \Rightarrow 3x^2 = \frac{y^3}{3} + C \)
Multiply by 3:
\( 9x^2 - y^3 = C \)
Using point (1,1):
\( 9(1)^2 - (1)^3 = 8 \Rightarrow C = 8 \)
Top Fluid Kinematics MCQ Objective Questions
In a stream line steady flow, two points A and B on a stream line are 1 m apart and the flow velocity varies uniformly from 2 m/s to 5 m/s. What is the acceleration of fluid at B?
Answer (Detailed Solution Below)
Fluid Kinematics Question 6 Detailed Solution
Download Solution PDFConcept:
For flow along a stream line acceleration is given as
If V = f(s, t)
Then, \(dV = \frac{{\partial V}}{{\partial s}}ds + \frac{{\partial V}}{{\partial t}}dt\)
\(a = \frac{{dV}}{{dt}} = \;\frac{{\partial V}}{{\partial s}} \times \frac{{ds}}{{dt}} + \frac{{\partial V}}{{\partial t}}\)
For steady flow \(\frac{{\partial V}}{{\partial t}} = 0\)
Then \(a = \frac{{\partial V}}{{\partial s}} \times \frac{{ds}}{{dt}}\)
Since V = f(s) only for steady flow therefore \(\frac{{\partial v}}{{\partial s}} = \frac{{dv}}{{ds}}\)
Therefore \(a = V \times \frac{{dV}}{{ds}}\)
Calculation:
Given, VA = 2 m/s, VB = 5 m/s, and distance s = 1 m
\(\frac{{dV}}{{ds}} = \frac{{\left( {5 - 2} \right)}}{1} = 3\)
So acceleration of fluid at B is
\({a_B} = {V_B} \times \frac{{dV}}{{ds}} = 5 \times 3 = 15\)
A vortex flow is
Answer (Detailed Solution Below)
Fluid Kinematics Question 7 Detailed Solution
Download Solution PDFConcept:
Vortex flow:
The motion of a fluid in a curved path is known as vortex flow.
When a cylindrical vessel containing some liquid is rotated about its vertical axis, the vortex flow will be followed by liquid.
Vortex motion is of two types:
1. Forced vortex:
- In the forced vortex, fluid moves on the curve under the influence of external torque.
- Due to the external torque, a forced vortex is a rotational flow.
- As there is the continuous expenditure of energy, Bernoulli's equation is not valid for forced vortex.
- For forced vortex, v = rω is applicable.
- Examples:
- The flow of water through a runner of the turbine.
- Rotation of water in the washing machine.
2. Free vortex:
- When no external torque is required to rotate the fluid mass, that type of flow is called a free vortex.
- As there is no torque in the free vortex, so free vortex is an irrotational flow.
- For free vortex, a moment of momentum is constant i.e. vr = constant.
- Examples:
- The flow of liquid through a hole provided at the bottom of a container.
- Draining the bathtub.
∴vortex flow is both rotational and irrotational flow depending on the torque applied.
Which of the following statements are correct for an incompressible flow?
I) In incompressible flows, variation in density is negligible.
II) Incompressible flows are always laminar.
III) Incompressible flows can be internal as well as external.
Answer (Detailed Solution Below)
Fluid Kinematics Question 8 Detailed Solution
Download Solution PDFExplanation:
Incompressible flow: It is that type of flow in which the density is constant for the fluid flow. Liquids are generally incompressible while gases are compressible.
Mathematically, ρ = Constant.
These can be laminar or turbulent, external or internal.
Laminar and Turbulent flow is considered to be incompressible if the density is constant or the fluid expands with little energy in compressing the flow. Hence a flow with varying density (Incompressible) flow could be Laminar & Turbulent.
Additional Information
Compressible flow: The flow in which the density of the fluid changes from point to point or the density is not constant for the fluid
Mathematically, for compressible flow ρ ≠ Constant
If velocity potential (ϕ) exists in a fluid flow, then the flow is said to be:
Answer (Detailed Solution Below)
Fluid Kinematics Question 9 Detailed Solution
Download Solution PDFExplanation:
Velocity Potential function
- This function is defined as a function of space and time in a flow such that the negative derivation of this function with respect to any direction gives the velocity of the fluid in that direction.
Properties of Velocity Potential function:
- If velocity potential (ϕ) exists, there will be a flow.
- Velocity potential function exists for flow then the flow must be irrotational.
- If velocity potential (ϕ) satisfies the Laplace equation, it represents the possible steady incompressible irrotational flow.
Additional Information
Stream Function:
- It is the scalar function of space and time.
- The partial derivative of stream function with respect to any direction gives the velocity component perpendicular to that direction. Hence it remains constant for a streamline
- Stream function defines only for the two-dimensional flow which is steady and incompressible..
Properties of stream function:
- If ψ exists, it follows continuity equation and the flow may be rotational or irrotational.
- If ψ satisfies the Laplace equation, then the flow is irrotational.
A flow field which has only convective acceleration is
Answer (Detailed Solution Below)
Fluid Kinematics Question 10 Detailed Solution
Download Solution PDFExplanation:
Total acceleration of a flow is given by:
\(\frac{D\vec V}{Dt}=\frac{\partial\vec V}{\partial t}+u\frac{\partial\vec V}{\partial x}+v\frac{\partial\vec V}{\partial y}+w\frac{\partial\vec V}{\partial z}\)
The total derivative,
\(\frac{D}{Dt}=\frac{\partial}{\partial t}+u\frac{\partial}{\partial x}+v\frac{\partial}{\partial y}+w\frac{\partial}{\partial z}\)
The total differential D/Dt is known as the material or substantial derivative with respect to time.
The first term \(\frac{\partial}{\partial t}\) in the right hand side is known as temporal or local derivative which expresses the rate of change with time, at a fixed position.
The last three terms \(u\frac{\partial}{\partial x}+v\frac{\partial}{\partial y}+w\frac{\partial}{\partial z}\) in the right hand side of are together known as convective derivative which represents the time rate of change due to change in position in the field.
Type of Flow |
Material Acceleration |
|
|
Temporal |
Convective |
Steady Uniform flow |
0 |
0 |
Steady non-uniform flow |
0 |
exists |
Unsteady Uniform flow |
exists |
0 |
Unsteady non-uniform flow |
exists |
exists |
The motion of outgoing water from the hole made at the midpoint of a completely filled open cylindrical tank with water is ___________.
Answer (Detailed Solution Below)
Fluid Kinematics Question 11 Detailed Solution
Download Solution PDFExplanation:
Free vortex
When the fluid mass is rotating about an axis without any external torque is known as a free vortex and free vortex motion is irrotational flow.
Forced vortex
When an external force is required to rotate the fluid mass at a constant angular velocity about an axis is known as a forced vortex.
By deriving the condition for free vortex flow by considering fundamental equations of vortex flow, Bernoulli’s equation will be valid, which ultimately proves the flow to be irrotational (one of the assumptions of Bernoulli’s equation).When 0.1 m3/s water flows through a pipe of area 0.25 m2, which later reduces to 0.1 m2, what is the velocity of flow in the reduced pipe?
Answer (Detailed Solution Below)
Fluid Kinematics Question 12 Detailed Solution
Download Solution PDFConcept:
Continuity equation: It is the conservation of mass flow rate.
- ρ1A1V1 = ρ1A1V1
For incompressible fluid density will be constant thus continuity equation will be:
- A1V1 = A2V2
where, A1, A2 = area of section 1 & 2 respectively, V1, V2 = velocity of section 1 & 2 respectively
The flow rate of liquid is equal to Q = AV.
Calculation:
Given:
Area: A1 = 0.25 m2, A2 = 0.1 m2.
Flow rate: Q = 0.1 m3/s.
Q = A1V1 = A2V2
\(V_1 = \frac{Q}{A_1} = \frac{0.1}{0.25} = 0.4\ m/s\)
\(V_2 = \frac{Q}{A_2} = \frac{0.1}{0.1} = 1\ m/s\)
∴ The velocity of flow in the reduced pipe is 1 m/s
In a free vortex, the flow is:
Answer (Detailed Solution Below)
Fluid Kinematics Question 13 Detailed Solution
Download Solution PDFConcept:
Vortex flow:
The motion of a fluid in a curved path is known as vortex flow.
When a cylindrical vessel containing some liquid is rotated about its vertical axis, the vortex flow will be followed by liquid.
Vortex motion is of two types:
1. Forced vortex:
- In the forced vortex, fluid moves on the curve under the influence of external torque.
- Due to the external torque, a forced vortex is a rotational flow.
- As there is the continuous expenditure of energy, Bernoulli's equation is not valid for forced vortex.
- For forced vortex, v = rω is applicable.
- Examples:
- The flow of water through a runner of the turbine.
- Rotation of water in the washing machine.
2. Free vortex:
- When no external torque is required to rotate the fluid mass, that type of flow is called a free vortex.
- As there is no torque in the free vortex, so free vortex is an irrotational flow.
- For free vortex, a moment of momentum is constant i.e. vr = constant.
- Examples:
- The flow of liquid through a hole provided at the bottom of a container.
- Draining the bathtub.
∴ Vortex flow is both rotational and irrotational flow depending on the torque applied.
In a one-dimensional flow field in a pipe, the fluid velocity is given by u = x + 2t where ‘t’ is the time. The flow in the pipe is:
Answer (Detailed Solution Below)
Fluid Kinematics Question 14 Detailed Solution
Download Solution PDFExplanation:
Steady Flow: The flow is defined as steady flow when the velocity and other hydrodynamic parameters do not change with time at any given point.
Unsteady Flow: The flow is defined as unsteady flow when the velocity and other hydrodynamic parameters change with time at any given point.
Uniform flow: The flow is defined as uniform flow when the velocity and other hydrodynamic parameters do not change from point to point at any given instant of time.
Non-uniform flow: The flow is defined as non-uniform flow when the velocity and other hydrodynamic parameters change from point to point at any given instant of time.
The given function of u = x + 2t
u = f (x,t)
u is a function of both time and space. Therefore the velocity will vary with time as well as space. Hence it is unsteady and non-uniform flow.For the continuity equation given by \(\vec \nabla \cdot {\rm{\vec V}} = 0\) to be valid, where \({\rm{\vec V}}\) is the velocity vector, which one of the following is a necessary condition?
Answer (Detailed Solution Below)
Fluid Kinematics Question 15 Detailed Solution
Download Solution PDFExplanation:
General Continuity equation:
\(\begin{array}{l} \frac{{\partial \left( {\rho u} \right)}}{{\partial x}} + \frac{{\partial \left( {\rho v} \right)}}{{\partial y}} + \frac{{\partial \left( {\rho w} \right)}}{{\partial z}} + \frac{{\partial \rho }}{{\partial t}} = 0\\ \frac{{\partial \rho }}{{\partial t}} + \vec \nabla.\left( {\rho \vec V} \right) = 0 \end{array}\)
For incompressible and steady flow:
\(\frac{{\partial u}}{{\partial x}} + \frac{{\partial v}}{{\partial y}} + \frac{{\partial w}}{{\partial z}} = 0\)
\(\vec \nabla \cdot {\rm{\vec V}} = 0\)
∴ The flow needs to be steady and incompressible.