What is 3 (sin x - cos x)4 + 6 (sin x + cos x)2 + 4 (sin x)6 + 4 (cos x)equal to ?

This question was previously asked in
CDS Elementary Mathematics 3 Sep 2023 Official Paper
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  1. 9
  2. 11
  3. 13
  4. 15

Answer (Detailed Solution Below)

Option 3 : 13
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 Put x = 0, 

3 (sin x - cos x)4 + 6 (sin x + cos x)2 + 4 (sin x)6 + 4 (cos x)6

⇒ 3 (sin 0 - cos 0)4 + 6 (sin 0 + cos 0)2 + 4 (sin 0)6 + 4 (cos 0)6

⇒ 3 (-1)4 + 6 (1)2 + 4 (0)6 + 4 (1)6

⇒ 3 + 6 + 4 = 13

∴ 3 (sin x - cos x)4 + 6 (sin x + cos x)2 + 4 (sin x)6 + 4 (cos x)equal to 13.

Alternate MethodConcept Used:

(a + b)2 = a2 + b2 + 2ab

(a - b)2 = a2 + b2 - 2ab

sinθ + cosθ = 1 

Calculation:

⇒ 3 [sin x - cos x]4 + 6 [sin x + cos x]+ 4 [sinx + cosx]

⇒ 3 {(sin x - cos x)2}2 + 6 (sinx + cosx + 2 sin x cos x) + 4 [(sinx)3 + (cosx)3]

⇒ 3 {(sinx + cosx - 2 sin x cos x)2} + 6 (1 + 2 sin x cos x) + 4 [(sinx + cosx)(sinx + cosx - sinx cosx)]

⇒ 3 (1 - 2 sin x cos x)2 + 6 (1 + 2sin x cos x) + 4 [(sinx)2 + (cosx)2 + 2 sinx cosx - 3 sinx cosx]

⇒ 3 (1 + 4 sinx cosx - 4sin x cos x) + 6 (1 + 2sin x cos x) + 4 [(sinx + cosx)2 - 3 sinx cosx]

⇒ 3 + 12 sinx cosx - 12 sin x cos x + 6 + 12 sin x cos x + 4 - 12 sinx cosx

⇒ 13

∴ 3 (sin x - cos x)4 + 6 (sin x + cos x)2 + 4 (sin x)6 + 4 (cos x)equal to 13.

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