Question
Download Solution PDFThe velocity of belt for maximum power is
(Where m = mass of the belt in kg per metre length. T = Tension)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Power transmitted by a belt:
P = (T1 – T2)v
For maximum power:
T1 = T/3
where T1 = Tension in the tight side, T = Maximum tension to which the belt is subjected.
The velocity of the belt for maximum power (Maximum Permissible velocity)
\(v = \sqrt {\frac{T}{{3m}}} =\sqrt{\frac{Tg}{3w}}\)
where m is mass of belt per unit length.
m = Area × length × density = b.t.l.ρ
Last updated on Mar 26, 2025
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