The value of \(\rm \displaystyle\int x^2 e^{ax} dx\) is

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  1. \(\rm \frac{e^{ax}}{a} (a^2 x^2 + 3ax - 2)\)
  2. \(\rm \frac{e^{ax}}{a^4} (a^3x^2 -a^2 x+ 2ax +1)\)
  3. \(\rm \frac{e^{ax}}{a^3} (a^2 x^2 -2ax + 2)\)
  4. \(\rm \frac{e^{ax}}{a^2} (a^3x^2 -2a^2x + 4)\)

Answer (Detailed Solution Below)

Option 3 : \(\rm \frac{e^{ax}}{a^3} (a^2 x^2 -2ax + 2)\)
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Detailed Solution

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Concept:

The product of function can be integrated by the method of "Integration by parts".

By the method of integration by parts we have,

\(\smallint f\left( x \right)g\left( x \right)dx\; = \;f\left( x \right)\smallint g\left( x \right)dx - \smallint \left[ {f'\left( x \right)\smallint g\left( x \right)dx} \right]dx\)

Where f is the first function and g is the second function.

Which is chosen based on the order for the selection of the first function: ILATE (Inverse, Logarithmic, Algebraic, Trigonometric, Exponent)

Calculation:

From the above formula,

\(\int x^2e^{ax}dx=\frac{x^2e^{ax}}{a}-\int \frac{2xe^{ax}}{a}dx\)

⇒ \(x^2e^{ax}-\frac{2}{a}[\frac{xe^{ax}}{a}-\frac{e^{ax}}{a^2}]\)

⇒ \(x^2e^{ax}-\frac{2}{a^2}xe^{ax}+\frac{2}{a^3}e^{ax}\)

Hence, \(\rm \displaystyle\int x^2 e^{ax} dx\) = \(\rm \frac{e^{ax}}{a^3} (a^2 x^2 -2ax + 2)\)

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