Question
Download Solution PDFThe smallest number which when reduced by 5, is divisible 12, 16, and 18 is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven
The smallest number reduced by 5 is divisible by 12, 16, and 18
Concept:
To find the smallest number that satisfies certain conditions, we need to find the least common multiple (LCM) of the given numbers.
Solution:
The LCM of 12, 16, and 18 is 144.
Let the smallest number be N. According to the given information:
(N - 5) is divisible by 12, 16, and 18
We can write this as an equation:
N - 5 = 144k
where k is an integer.
To find the smallest value of N, we need to find the smallest positive integer value of k that satisfies the equation.
By trying different values of k, we find that k = 1 satisfies the equation:
N - 5 = 144 × 1
N - 5 = 144
N = 149
Therefore, the smallest number that satisfies the given conditions is 149.
Last updated on Jun 30, 2025
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