Which of the following numbers is divisible by both 4 and 9?

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  1. 4512
  2. 3241
  3. 2345
  4. 1728

Answer (Detailed Solution Below)

Option 4 : 1728
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Detailed Solution

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Formula Used:

A number is divisible by 4 if the last two digits form a number divisible by 4.

A number is divisible by 9 if the sum of its digits is divisible by 9.

Calculation:

Option 1: 4512

Last two digits: 12

12 ÷ 4 = 3 (divisible by 4)

Sum of digits: 4 + 5 + 1 + 2 = 12

12 ÷ 9 = 1.33 (not divisible by 9)

Option 2: 3241

Last two digits: 41

41 ÷ 4 = 10.25 (not divisible by 4)

Option 3: 2345

Last two digits: 45

45 ÷ 4 = 11.25 (not divisible by 4)

Option 4: 1728

Last two digits: 28

28 ÷ 4 = 7 (divisible by 4)

Sum of digits: 1 + 7 + 2 + 8 = 18

18 ÷ 9 = 2 (divisible by 9)

Therefore, the correct option is Option 4: 1728.

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