The dimensions of electrical conductivity is

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  1. [M-2L-1T2A1]
  2. [M-3LT-2A-1]
  3. [M-1L-3T3A2]
  4. [ML-2A-3T2]

Answer (Detailed Solution Below)

Option 3 : [M-1L-3T3A2]
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CALCULATION:

1. The resistance may be written as

\(⇒ R =\frac{V}{I} =\frac{W}{I^2t^{}}\)

Where W is the work done and I is the current and t is the time

The dimension of R will be given by

\(⇒ \frac{W}{I^2t^{}}= \frac{ML^{2}T^{-2}}{A^{2}T} = ML^{2}T^{-3}A^{-2}\)

2. The resistivity is given by

\(⇒ \rho = \frac{RA}{l}\)

Where A =Area and l = length

The dimension of resistivity is 

\(⇒ \rho = \frac{RA}{l} = \frac{ML^{2}T^{-3}A^{2}\times L^{2}}{L} = ML^{3}T^{-3}A^{-2} \)

3. As we know, the conductivity is the inverse of resistivity taking the inverse of the dimension of resistivity, then the dimension of electrical conductivity is 

⇒ σ = M-1L-3T3A2

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