The angle of elevation of the top of a tower from a point on the ground, which is 48m away from the foot of the tower is 30°. Find the height of the tower.

Question

Question

This question was previously asked in

RRB NTPC Graduate Level CBT-I Official Paper (Held On: 05 Jun, 2025 Shift 2)

Answer 1

Given:

Horizontal distance = 48 m; angle elevation = \(30°\)

Formula used:

\(\tan θ = \frac{\text{height}}{\text{distance}}\)

Calculations:

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⇒ \(\tan30° = \frac{h}{48}\)

⇒ \(\frac{1}{√3} = \frac{h}{48}\)

⇒ h = \(48 × \frac{1}{√3} = \frac{48}{√3}\) = 16√3

∴ Height of the tower 16√3 m.