Question
Download Solution PDF10 செமீ ஆரம் கொண்ட ஒரு திடக் கோளம் சம ஆரம் கொண்ட 8 கோள வடிவ திடப் பந்துகளாக உருகினால், ஒவ்வொரு பந்தின் மேற்பரப்பளவு என்னவாக இருக்கும்? [π = \(\frac{{22}}{7}\) ஐ பயன்படுத்தவும்]
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFகொடுக்கப்பட்டது:
R = 10 செ.மீ
பயன்படுத்தப்பட்ட வாய்ப்பாடு:
பருமன் = 4/3 x 22/7 x r x r x r
TSA(கோளம்)= 4 x 22/7 x r x r
தீர்வு:
திடக் கோளத்தின் பருமன் = 4/3 x 22/7 x 103
= 88000/21 செ.மீ3
1 சிறிய கோளத்தின் பருமன் = (88000/21)/8 = 11000/21 செ.மீ3
1 சிறிய கோளத்தின் ஆரம் = 5 செ.மீ
TSA(கோளம்)= 4 x 22/7 x 52
= 88/7 x 25
= 314.285714 = 314\(2\over7\) செ.மீ2
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