Sum of two consecutive natural numbers is 31. What is the difference of their squares?

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  1. 961
  2. 31
  3. 1
  4. 62

Answer (Detailed Solution Below)

Option 2 : 31
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Detailed Solution

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Given:

Sum of two consecutive natural numbers is 31.

Calculation:

Let the two consecutive numbers be n and n + 1.

The difference of their squares:

⇒ (n+1)2 - n2 = n2 + 2n + 1 - n2 = 2n + 1

Given that: n + (n + 1) = 31

⇒ 2n + 1 = 31

The difference of their squares is:

2n + 1 = 31

∴ The correct answer is option 2.

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