Question
Download Solution PDF90 rpm की स्पिंडल गति और 0.3 mm/rev के पार संभरण के लिए 80 m व्यास वाले एक वस्तु के सम्मुख आने में लिया गया समय क्या होगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
वस्तु के सम्मुख आने में लिए गए समय को निम्न द्वारा ज्ञात किया गया है
\({T_m} = \frac{L}{{fN}}\)
यहाँ L = D/2, f – पार संभरण, N – स्पिंडल गति
गणना:
दिया गया है:
D = 80 mm, f = 0.3 mm/rev, N = 90 rpm
fN = 27 mm/min, L = 40 mm
लिया गया समय = 40/27 = 1.48 मिनटLast updated on Jun 23, 2025
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