Question
Download Solution PDF2.5 mW He-Ne लेजर के लिए उत्सर्जित फोटॉनों की संख्या ________ है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFHe-Ne लेजर के लिए:
λ = 6328 8 = 6.328 × 10-7 m
गणना :
शक्ति = 2.5 mW = 2.5 × 10 -3 W
ऊर्जा = शक्ति × समय = 0.0025 × 1 = 0.0025
प्रत्येक स्पंद में फोटॉनों की संख्या होगी:
\(n=Energy × \frac{λ}{ hc}\)
\(n=0.0025× \frac{6.328 × 10^{-7}}{ 6.6 × 10^{-34} × 3 × 10^8}\).....( λ = 6.328 × 10-7)
n = 7.989 × 1015
Last updated on Jun 19, 2025
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