Question
Download Solution PDFThe number of photons emitted for a 2.5 mW He-Ne laser is ________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFor a He-Ne laser:
λ = 6328 Ȧ = 6.328 × 10-7 m
Calculation:
Power = 2.5 mW = 2.5 × 10-3 W
Energy = Power × Time = 0.0025 × 1 = 0.0025
The number of photons in each pulse will be:
\(n=Energy × \frac{λ}{ hc}\)
\(n=0.0025× \frac{6.328 × 10^{-7}}{ 6.6 × 10^{-34} × 3 × 10^8}\)......( λ = 6.328 × 10-7)
n = 7.989 × 1015
Last updated on Jun 19, 2025
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