यदि \({\rm{co}}{{\rm{s}}^{ - 1}}\left( {\frac{1}{{\sqrt 5 }}} \right) = {\rm{\theta }}\) है तो \({\rm{cose}}{{\rm{c}}^{ - 1}}\left( {\sqrt 5 } \right)\) का मान क्या होगा?

  1. \(\left( {\frac{{\rm{\pi }}}{2}} \right) + {\rm{\theta }}\)
  2. \(\left( {\frac{{\rm{\pi }}}{2}} \right) - {\rm{\theta }}\)
  3. \(\frac{{\rm{\pi }}}{2}\)

Answer (Detailed Solution Below)

Option 2 : \(\left( {\frac{{\rm{\pi }}}{2}} \right) - {\rm{\theta }}\)
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NDA 01/2025: English Subject Test
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Detailed Solution

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धारणा:

sec-1 x = cos-1 (1/x)

cosec-1 (x) + sec-1 (x) = π / 2

गणना:

जैसा कि हम जानते हैं कि, 

sec-1 x = cos-1 (1/x)

\({\rm{co}}{{\rm{s}}^{ - 1}}\left( {\frac{1}{{\sqrt 5 }}} \right) = {\rm{\theta }} \)

\(\Rightarrow {\rm{se}}{{\rm{c}}^{ - 1}}\left( {\sqrt 5 } \right) = {\rm{\theta }}\)

जैसा कि हम जानते हैं कि, 

cosec-1 (x) + sec-1 (x) = π / 2

\(\Rightarrow \frac{{\rm{\pi }}}{2} - {\rm{cose}}{{\rm{c}}^{ - 1}}\left( {\sqrt 5 } \right) = {\rm{\theta }}\)

\(\therefore {\rm{cose}}{{\rm{c}}^{ - 1}}\left( {\sqrt 5 } \right) = \frac{{\rm{\pi }}}{2} - {\rm{\theta }}\)

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