Question
Download Solution PDF32cos2θ + 2tan2θ का न्यूनतम मान ज्ञात कीजिये।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFउपयोग किया गया सूत्र:
1 + tan2θ = sec2θ
गणना:
32cos2θ + 2tan2θ = 32cos2θ + 2(sec2θ – 1)
⇒ 32cos2θ + 2(sec2θ – 1) = 32cos2θ + 2sec2θ – 2
⇒ acos2θ + bsec2θ का न्यूनतम मान = 2√ab है जब b ≤ a है
⇒ 32cos2θ + 2sec2θ – 2 का न्यूनतम मान = 2√64 – 2 = 14
∴ 32cos2θ + 2tan2θ का न्यूनतम मान 14 है।Last updated on Jul 23, 2025
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