Question
Download Solution PDFबिंदु (1, -2) पर वक्र y = 3x2 - 7x + 2 की प्रवणता ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
वक्र के किसी बिंदु पर प्रवणता को उस बिंदु की स्पर्शरेखा के रूप में परिभाषित किया जाता है।
\(Δ f(x,y,z)= \frac{\delta f(x,y,z)}{\delta x}+\frac{\delta f(x,y,z)}{\delta y}+\frac{\delta f(x,y,z)}{\delta z}\)
विश्लेषण:
दिया गया है कि y = 3x2 - 7x + 2
\(\frac{dy}{dx}= {\frac{d(3x^2 -7x + 2)}{dx}}|_{(1,-2)}\)
\(\frac{dy}{dx}= {6x -7}|_{(1,-2)}\)
y की प्रवणता = -1
अत: विकल्प (4) सही है
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