Question
Download Solution PDFवक्र 2x2 = y के लंब का समीकरण ज्ञात कीजिए, जो (1, 2) से होकर गुजरता है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
वक्र के स्पर्श रेखा की ढलान = \(\rm \frac {dy}{dx}\)
वक्र के लंब की ढलान = \(\rm \frac{-1}{(\frac {dy}{dx})}\)
बिंदु-ढलान सामान्य रूप: y - y₁ = m(x - x₁) है,
जहाँ m = ढलान है।
गणना:
यहाँ, y = 2x2
\(\rm \frac {dy}{dx}\) = 4x
\(\rm \frac{dy}{dx}|_{x=1}=4\)
वक्र के लंब की ढलान =\(\rm \frac{-1}{(\frac {dy}{dx})}\) = -1/4
(1, 2) से होकर गुजरने वाले वक्र के लंब का समीकरण है
(y - 2) = (-1/4)(x - 1)
⇒ 4y - 8 = -x + 1
⇒ x + 4y - 9 = 0
अतः विकल्प (4) सही है।
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