Question
Download Solution PDF27℃ तापमान और 0.26 N/mm² (निरपेक्ष) दाब पर 20 N/m³ भार वाला एक आदर्श गैस है। गैस स्थिरांक होगा [g = 9.81 m/s² लीजिये]
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
आदर्श गैस नियम से: \( P = \rho R T \Rightarrow R = \frac{P}{\rho T} \)
भार घनत्व \( w = \rho g \Rightarrow \rho = \frac{w}{g} \)
गणना:
\( w = 20~\text{N/m}^3, \, g = 9.81~\text{m/s}^2 \Rightarrow \rho = \frac{20}{9.81} = 2.039~\text{kg/m}^3 \)
\( P = 0.26~\text{N/mm}^2 = 0.26 \times 10^6~\text{N/m}^2 \), \( T = 27^\circ C = 300~K \)
\( R = \frac{260000}{2.039 \times 300} = \frac{260000}{611.7} \approx 425.1~\text{J/kg-K} = 0.4251~\text{kJ/kg-K} \)
Last updated on Jul 15, 2025
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