Question
Download Solution PDFFor perfect gas, the equation of state is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
A hypothetical gas that obeys the law PV = nR̅T at all pressures and temperatures is called Ideal gas. There are two equations for Ideal Gas.
- PV = nR̅T
- PV = mRT,
- P/ρ = RT
where,
P = Absolute pressure (Pa), V = Volume (m3), n = Number of moles of the gas \( = \frac{{\bf{m}}}{{\bf{M}}}\)
\({\bar{R}} = \;\)Universal gas constant (8314 J/kg-mol.K), T = Absolute Temperature (K)
\(R = characteristic\;gas\;constant = \frac{{\bar R}}{M}\;\left( {\frac{J}{{kg.K}}} \right)\), M = Molecular weight of the gas
m = Mass of gas (kg) & ρ = Density of gas (kg/m3).
Last updated on Jun 23, 2025
-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27.
-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been released on its official website.
-> JKSSB JE exam will be conducted on 10th August (Civil), and on 27th July 2025 (Electrical).
-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering.
-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025.
-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025
-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.
-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.
-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.