A और B एक साथ किसी कार्य को 20 दिनों में पूरा कर सकते हैं जबकि B और C मिलकर इसे 24 दिनों में पूरा कर सकते हैं। यदि A, C से दोगुना कुशल है, तब B अकेले उसी कार्य का 40% कितने समय में करेगा?

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SSC CGL 2020 Tier-I Official Paper 10 (Held On : 18 Aug 2021 Shift 1)
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  1. 12 दिन
  2. 10 दिन
  3. 18 दिन
  4. 15 दिन

Answer (Detailed Solution Below)

Option 1 : 12 दिन
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दिया गया है:

A = 2C

A + B कार्य 20 दिनों में करते हैं।

B + C कार्य 24 दिनों में करते हैं।

प्रयुक्त अवधारणा:

कुल कार्य = कार्य करने में लिए गये समय का लघुत्तम समापवर्तक 

गणना:

20 और 24 का लघुत्तम समापवर्तक 120 है 

इसलिए, A और B की दक्षता = 120/20 = 6 तथा B और C की दक्षता = 120/24 = 5

अब 2C + B = 6 और B + C = 5

इसलिए, C = 1

B = 4

कार्य का 40% = 120 × 2/5 = 48 इकाई

इसलिए, B समय लेगा = 48/4 = 12 दिन 

∴ B अकेले उसी कार्य का 40% भाग 12 दिनों में पूरा करेगा। 

Shortcut Trick F1 Madhuri SSC 28.03.2022 D1

अब 2C + B = 6 और B + C = 5

इसलिए, C = 1

B = 4

इसलिए,

A, B और C = 2, 4 और 1

कार्य का 40% = 120 × 2/5 = 48 इकाइयाँ

इसलिए, B को 48/4 = 12 दिन लगेंगे।

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