Question
Download Solution PDFA perfect gas at 27°C is heated at constant pressure till its volume is double. The final temperature is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
As the gas is heated at constant pressure, so by applying Charles’s law
\(\frac{{{V_2}}}{{{V_1}}} = \frac{{{T_2}}}{{{T_1}}}\)
Calculation:
Given:
T1 = 27°C = 300 K, V1 = V, V2 = 2V
Therefore, \(2= \frac{{{T_2}}}{{300}} \)
T2 = 600 K = 600 - 273 = 327°C
Last updated on Apr 16, 2025
-> RVUNL JE Result 2025 out! Candidates can check their result on official website @rrvunl.exam.in.
-> Candidates who have cleared cut off will be called for Document Verification.
-> RVUNL JEN Exam was conducted on 11th and 12th April 2025 for Junior Engineer and Junior Chemist posts.
-> The RVUNL JEN Notification 2025 was released for 228 vacancies.
-> The application process was started on 30th January 2025 and ended on 20th February 2025.
-> Engineering graduates, between 21 to 43 years of age can apply for the RVUNL JE Recruitment.
-> The selection process includes a written test and document verification.