An R-C network has the transfer function \({G_C}\left( s \right) = \frac{{{s^2} + 10s + 24}}{{{s^2} + 10s + 16}}\)

The network could be used as

1. lead compensator

2. lag compensator

3. lag-lead compensator

Which of the above is/are correct?

This question was previously asked in
ESE Electrical 2016 Paper 1: Official Paper
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  1. 1 only
  2. 2 only
  3. 3 only
  4. 1, 2 and 3

Answer (Detailed Solution Below)

Option 3 : 3 only
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Detailed Solution

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Concept:

Pole zero plot of different compensators is given below.

Compensator

Pole zero plot

Important

Lag

F1 U.B Madhu 2.12.19 D1

Pole is near to the origin. Pole is dominant.

Lead

F1 U.B Madhu 2.12.19 D16

Zero is near to the origin. Zero is dominant.

Lag-lead

F1 U.B Deepak 31.03.2020 D3

Lag system is dominant. Lag system is near to the origin.

 

Application:

\({G_C}\left( s \right) = \frac{{{s^2} + 10s + 24}}{{{s^2} + 10s + 16}}\)

\( = \frac{{\left( {s + 4} \right)\left( {s + 6} \right)}}{{\left( {s + 2} \right)\left( {s + 8} \right)}}\)

Poles: s = -2, -8

Zeros: s = -4, -6

The pole-zero plot of the above transfer function is shown below.

F1 U.B Madhu 27.06.20 D12

The above pole-zero represents that the given system is a lag-lead compensator.

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