Question
Download Solution PDFA vertical pole and a vertical tower are on the same level of ground in such a way that from the top of the pole, the angle of elevation of the top of the tower is 60º and the angle of depression of the bottom of the tower is 30º. If the height of the tower is 76 m, then find the height (in m) of the pole.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The angle of elevation of the top of the tower from the top of the pole = 60º
The angle of depression of the bottom of the tower from the top of the pole = 30º
Calculation:
Let, the height of the pole (AB) = CD = x m
So, the height of ED = (76 - x) m
So, In ΔACD, tan 30° = CD/AD
⇒ 1/√3 = x/AD
⇒ AD = √3x .....(1)
In ΔAED, tan 60° = ED/AD
⇒ √3 = (76 - x)/√3x
⇒ 76 - x = 3x
⇒ 3x + x = 76
⇒ 4x = 76
⇒ x = 76/4 = 19
∴ The height (in m) of the pole is 19 m
Last updated on Jun 13, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.